{"segment":[{"time":24,"part":[{"title":"Kh\u1eb3ng \u0111\u1ecbnh sau. <b> \u0110\u00fang<\/b> hay <b> Sai <\/b> ","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai11/lv1/img\/10.jpg' \/><\/center>Cho hai \u0111\u01b0\u1eddng th\u1eb1ng $y=ax+b\\,\\, (d)$ v\u00e0 $y= a\u2019x+b \\,\\,(d\u2019)\\,\\,(a\\ne 0;\\,a\u2019\\ne 0)$ <br\/>Ta c\u00f3: $(d)\\bot (d') \\Leftrightarrow a.a'=-1$","select":["A. \u0110\u00fang ","B. Sai"],"explain":"Kh\u1eb3ng \u0111\u1ecbnh tr\u00ean l\u00e0 <b> \u0110\u00fang <\/b> <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span>","column":2}]}],"id_ques":101},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["2"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<span class='basic_left'>Cho \u0111\u01b0\u1eddng th\u1eb3ng $(d): y=3x+ b$. X\u00e1c \u0111\u1ecbnh $b$ \u0111\u1ec3 \u0111\u01b0\u1eddng th\u1eb3ng $(d)$ c\u1eaft tr\u1ee5c tung t\u1ea1i \u0111i\u1ec3m c\u00f3 tung \u0111\u1ed9 b\u1eb1ng $2$.<br\/><br\/><b> \u0110\u00e1p \u00e1n: <\/b> $b=$ _input_<\/span>","explain":" \u0110\u01b0\u1eddng th\u1eb3ng $(d)$ c\u1eaft tr\u1ee5c tung t\u1ea1i \u0111i\u1ec3m c\u00f3 tung \u0111\u1ed9 b\u1eb1ng $2$, ta c\u00f3: <br\/>$3.0 +b=2\\Leftrightarrow b= 2$<br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $2$.<\/span>"}]}],"id_ques":102},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"\u0110\u1ec1 chung cho b\u1ed1n c\u00e2u","temp":"fill_the_blank","correct":[[["1"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<span class='basic_left'><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai11/lv1/img\/4.jpg' \/><\/center><span class='basic_left'>Cho ba \u0111\u01b0\u1eddng th\u1eb3ng<br\/> $\\,(d_{1}):\\,\\,y=(m+2)x-5$; $\\,(d_{2}):\\,\\,y=3x+1$; $\\,(d_{3}):\\,\\,y=(m-1)x+3$<br\/><b> C\u00e2u 1:<\/b> T\u00ecm \u0111i\u1ec1u ki\u1ec7n c\u1ee7a $m$ \u0111\u1ec3 $\\,d_{1}\/\/d_{2}$<br\/><br\/><b> \u0110\u00e1p \u00e1n: <\/b> $m=$ _input_<\/span><\/span>","hint":"","explain":"<span class='basic_left'>\u0110\u1ed3 th\u1ecb hai h\u00e0m s\u1ed1 $d_{1}$ v\u00e0 $d_{2}$ l\u00e0 hai \u0111\u01b0\u1eddng song song v\u1edbi nhau khi v\u00e0 ch\u1ec9 khi $a=a'$ v\u00e0 $b \\ne b'$.<br\/>Theo \u0111\u1ec1 b\u00e0i ta c\u00f3 $b \\ne b'$ (v\u00ec $-5\\ne 1$)<br\/>V\u1eady \u0111\u1ed3 th\u1ecb c\u1ee7a hai h\u00e0m s\u1ed1 song song v\u1edbi nhau khi v\u00e0 ch\u1ec9 khi: $m+2=3\\Rightarrow m=1$<br\/>V\u1eady v\u1edbi $m=1$ th\u00ec $\\,d_{1}\/\/d_{2}$.<br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $1$<\/span><\/span> "}]}],"id_ques":103},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"\u0110\u1ec1 chung cho b\u1ed1n c\u00e2u","temp":"fill_the_blank","correct":[[["4"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<span class='basic_left'>Cho ba \u0111\u01b0\u1eddng th\u1eb3ng<br\/> $\\,(d_{1}):\\,\\,y=(m+2)x-5$; $\\,(d_{2}):\\,\\,y=3x+1$; $\\,(d_{3}):\\,\\,y=(m-1)x+3$<br\/><b> C\u00e2u 2:<\/b> T\u00ecm \u0111i\u1ec1u ki\u1ec7n c\u1ee7a $m$ \u0111\u1ec3 $\\,d_{2}\/\/d_{3}$.<br\/><br\/><b> \u0110\u00e1p \u00e1n: <\/b> $m=$ _input_<\/span>","hint":"Hai \u0111\u01b0\u1eddng th\u1eb3ng song song th\u00ec c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c b\u1eb1ng nhau, tung \u0111\u1ed9 g\u1ed1c kh\u00e1c nhau. ","explain":"<span class='basic_left'>\u0110\u1ed3 th\u1ecb hai h\u00e0m s\u1ed1 $d_{2}$ v\u00e0 $d_{3}$ l\u00e0 hai \u0111\u01b0\u1eddng song song v\u1edbi nhau khi v\u00e0 ch\u1ec9 khi $a=a'$ v\u00e0 $b \\ne b'$.<br\/>Theo \u0111\u1ec1 b\u00e0i ta c\u00f3 $b \\ne b'$ (v\u00ec $3\\ne 1$)<br\/>V\u1eady \u0111\u1ed3 th\u1ecb c\u1ee7a hai h\u00e0m s\u1ed1 song song v\u1edbi nhau khi v\u00e0 ch\u1ec9 khi: $m-1=3\\Rightarrow m=4$<br\/>V\u1eady v\u1edbi $m=4$ th\u00ec $\\,d_{2}\/\/d_{3}$.<br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $4$.<\/span>"}]}],"id_ques":104},{"time":9,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"select":["A. $\\dfrac{7}{3}$","B. $-\\dfrac{7}{3}$","C. $\\dfrac{8}{3}$","D. $-\\dfrac{8}{3}$"],"ques":"<span class='basic_left'>Cho ba \u0111\u01b0\u1eddng th\u1eb3ng <br\/>$\\,(d_{1}):\\,\\,y=(m+2)x-5$; $\\,(d_{2}):\\,\\,y=3x+1$; $\\,(d_{3}):\\,\\,y=(m-1)x+3$<br\/><br\/><b> C\u00e2u 3:<\/b> T\u00ecm \u0111i\u1ec1u ki\u1ec7n c\u1ee7a $m$ \u0111\u1ec3 $(d_{1})\\bot (d_{2})$.<br\/><b> \u0110\u00e1p \u00e1n: <\/b> $m=$ ?<\/span>","hint":"V\u1edbi hai \u0111\u01b0\u1eddng th\u1eb1ng $y=ax+b\\,\\, (d)$ v\u00e0 $y= a\u2019x+b\\,\\, (d\u2019)$ $\\,(a\\ne0;\\,a\u2019\\ne 0)$ <br\/>$(d)\\bot (d') \\Leftrightarrow a.a'=-1$ ","explain":" \u0110\u1ec3 $(d_{1})\\bot (d_{2})\\Leftrightarrow (m+2).3=-1$$\\,\\Leftrightarrow m=-\\dfrac{1}{3}-2=-\\dfrac{7}{3}$ <br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0: $-\\dfrac{7}{3}$.<\/span>"}]}],"id_ques":105},{"time":9,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"select":["A. $\\dfrac{2}{3}$","B. $-\\dfrac{2}{3}$","C. $\\dfrac{5}{3}$","D. $-\\dfrac{5}{3}$"],"ques":"<span class='basic_left'>Cho ba \u0111\u01b0\u1eddng th\u1eb3ng<br\/> $\\,(d_{1}):\\,\\,y=(m+2)x-5$; $\\,(d_{2}):\\,\\,y=3x+1$; $\\,(d_{3}):\\,\\,y=(m-1)x+3$<br\/><br\/><b> C\u00e2u 4: <\/b>T\u00ecm \u0111i\u1ec1u ki\u1ec7n c\u1ee7a $m$ \u0111\u1ec3 $(d_{2})\\bot (d_{3})$ <br\/><b> \u0110\u00e1p \u00e1n: <\/b> $m=$ ?<\/span>","hint":"V\u1edbi hai \u0111\u01b0\u1eddng th\u1eb1ng $y=ax+b\\,\\, (d)$ v\u00e0 $y= a\u2019x+b\\,\\, (d\u2019)$ $\\,(a\\ne0;\\,a\u2019\\ne 0)$ <br\/>$(d)\\bot (d') \\Leftrightarrow a.a'=-1$ ","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>$(d_{2})\\bot (d_{3})\\Leftrightarrow (m-1).3=-1$$\\,\\Leftrightarrow m=-\\dfrac{1}{3}+1=\\dfrac{2}{3}$ <br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0: $\\dfrac{2}{3}$<\/span>"}]}],"id_ques":106},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $\\,(d_{1}):\\,\\, y = -3x+ 1\\,$ v\u00e0 $\\,(d_{2}):\\,\\,y=\\dfrac{1}{3}x-3\\,$. Khi \u0111\u00f3: ","select":["A. $d_{1}\\bot d_{2}$ ","B. $d_{1} \/\/ d_{2}$","C. $d_{1}\\equiv d_{2}$ "],"explain":" <span class='basic_left'>Theo b\u00e0i $(d_{1})\\,\\,y=-3x+1\\,$ c\u00f3 h\u1ec7 s\u1ed1 $a= -3$ <br\/> $(d_{2})\\,\\,y=\\dfrac{1}{3}x-3\\,$ c\u00f3 h\u1ec7 s\u1ed1 $a'= \\dfrac{1}{3}$ <br\/>Suy ra $\\,a.a'=3.\\dfrac{1}{3}=-1\\,$.<br\/> Do \u0111\u00f3 $(d_{1})\\,\\bot\\,(d_{2})$<br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span> <\/span>","column":3}]}],"id_ques":107},{"time":24,"part":[{"title":"V\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y = x-2$","title_trans":"\u0110\u1ec1 chung cho hai c\u00e2u","temp":"coordinates","correct":[["0,-2","0.5,-1.5","1.5,-0.5","2,0","2.5,0.5","3,1","3.5,1.5","4,2","4.5,2.5","-0.5,-2.5","-1,-3","-1.5,-3.5","-2,-4","-2.5,-4.5","-3,-5"]],"list":[{"point":5,"toa_do":[["2","0","A"]],"is_click":1,"name_toado_click":"B","draw_line":1,"ques":"Cho s\u1eb5n \u0111i\u1ec3m $A (2; 0)$. H\u00e3y click th\u00eam m\u1ed9t \u0111i\u1ec3m thu\u1ed9c \u0111\u1ed3 th\u1ecb \u0111\u1ec3 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1.<br\/>_inputduongthang_ <br\/> ","hint":"X\u00e1c \u0111\u1ecbnh giao \u0111i\u1ec3m c\u1ee7a \u0111\u1ed3 th\u1ecb v\u1edbi hai tr\u1ee5c t\u1ecda \u0111\u1ed9.","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<br\/><\/span>+ Cho $x = 0 \\Rightarrow y= b \\Rightarrow B(0;b)$<br\/>+ V\u1ebd \u0111\u01b0\u1eddng th\u1eb1ng qua $A;B$ ta \u0111\u01b0\u1ee3c \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y= ax + b$. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Cho $x= 0 \\Rightarrow y=-2\\Rightarrow B (0,-2)$<br\/> \u0110\u01b0\u1eddng th\u1eb3ng n\u1ed1i hai \u0111i\u1ec3m $A;B$ l\u00e0 \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y=x-2$.<br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai11/lv1/img\/D923_D2.png' \/><\/center>"}]}],"id_ques":108},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"\u0110\u1ec1 chung cho hai c\u00e2u","temp":"fill_the_blank","correct":[[["45"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"T\u00ednh g\u00f3c $\\alpha\\,$ t\u1ea1o b\u1edfi \u0111\u01b0\u1eddng th\u1eb3ng $y=x - 2$ v\u00e0 tr\u1ee5c $Ox$.<br\/><br\/><b> \u0110\u00e1p s\u1ed1:<\/b> $\\,\\,\\alpha=$ _input_ $^o$","hint":"\u0110\u01b0\u1eddng th\u1eb3ng $y=ax + b\\,\\, (a > 0)$ t\u1ea1o v\u1edbi tia $Ox$ m\u1ed9t g\u00f3c $\\,\\alpha\\,$ th\u00ec $\\,a=tg\\alpha$","explain":"<span class='basic_left'> Theo c\u00e2u tr\u00ean ta c\u00f3 \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 $y=x-2$.<br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai11/lv1/img\/D923_D2.png' \/><\/center><br\/>Ta c\u00f3: $OA= 2; OB= 2$<br\/>X\u00e9t tam gi\u00e1c $OAB$ vu\u00f4ng t\u1ea1i$ O$, c\u00f3:<br\/> $tg {\\widehat{OBA}}=\\dfrac{OA}{OB}=1 \\Rightarrow \\widehat{OBA}=45^o \\Rightarrow \\alpha=\\widehat{OBA}=45^o$ (hai g\u00f3c \u0111\u1ed1i \u0111\u1ec9nh)<br\/><span class='basic_pink'> Do \u0111\u00f3 s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $45$.<\/span>"}]}],"id_ques":109},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 v\u00e0 c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c b\u1eb1ng $5$ c\u00f3 d\u1ea1ng l\u00e0: ","select":["A. $y=5x$ ","B. $y=5x-2$","C. $y=\\dfrac{1}{5}x$ ","D. $y=5x+1$ "],"explain":" <span class='basic_left'>\u0110\u01b0\u1eddng th\u1eb3ng $(d)$ \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 c\u00f3 d\u1ea1ng $y= ax$.<br\/> $(d)$ c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c b\u1eb1ng $5$ n\u00ean $a=5$.<br\/>V\u1eady ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng c\u1ea7n t\u00ecm l\u00e0 $y= 5x$.<br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n l\u00e0 A.<\/span> <\/span>","column":4}]}],"id_ques":110},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"\u0110\u1ec1 chung cho b\u1ed1n c\u00e2u","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<span class='basic_left'>Cho \u0111\u01b0\u1eddng th\u1eb3ng $(d):\\,\\,y = (a+1)x+a$ <br\/><b> C\u00e2u 1: <\/b> X\u00e1c \u0111\u1ecbnh $a$ \u0111\u1ec3 h\u00e0m s\u1ed1 \u0111\u1ed3ng bi\u1ebfn. <\/span>","select":["A. $\\,a\\,>-1\\,$ ","B. $\\,a\\,<-1\\,$","C. $a=-1$ "],"explain":"H\u00e0m s\u1ed1 \u0111\u1ed3ng bi\u1ebfn $\\Leftrightarrow a+ 1> 0\\, \\Leftrightarrow a\\,>-1$ <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span>","column":3}]}],"id_ques":111},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"\u0110\u1ec1 chung cho b\u1ed1n c\u00e2u","temp":"fill_the_blank","correct":[[["0"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<span class='basic_left'>Cho \u0111\u01b0\u1eddng th\u1eb3ng $(d):\\,\\,y = (a+1)x+a$ <br\/><b> C\u00e2u 2: <\/b> X\u00e1c \u0111\u1ecbnh $a$ \u0111\u1ec3 \u0111\u01b0\u1eddng th\u1eb3ng \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9.<br\/><b> \u0110\u00e1p s\u1ed1 :<\/b> $a=$ _input_ <\/span>","hint":"\u0110i\u1ec3m $O(0; 0)$ thu\u1ed9c \u0111\u01b0\u1eddng th\u1eb3ng $\\,y=(a+1)x+a$. ","explain":"<span class='basic_left'>Ta c\u00f3 $O(0; 0) \\,\\in (d)$$\\,\\Leftrightarrow 0=(a+1).0+a\\Leftrightarrow a=0$<br\/><span class='basic_pink'> Do \u0111\u00f3 s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $0$.<\/span>"}]}],"id_ques":112},{"time":24,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"select":["A. $a = \\sqrt{3}$","B. $a = 2\\sqrt{3}$","C. $a = 3\\sqrt{3}$","D. $a = 4\\sqrt{3}$"],"ques":"<span class='basic_left'>Cho \u0111\u01b0\u1eddng th\u1eb3ng $(d):\\,\\,y = (a+1)x+a$. <br\/>X\u00e1c \u0111\u1ecbnh $a$ \u0111\u1ec3 \u0111\u01b0\u1eddng th\u1eb3ng $(d)$ song song v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng $y=(\\sqrt{3}+1)x+4$.<br\/><b> \u0110\u00e1p s\u1ed1 :<\/b> $a=$ ?<\/span>","explain":"<span class='basic_left'>Ta c\u00f3: $(d) \/\/\\,y=(\\sqrt{3}+1)x+4$ $\\,\\Leftrightarrow$ $\\left\\{ \\begin{align} & a+1=\\sqrt{3}+1 \\\\ & a\\ne 4 \\\\ \\end{align} \\right.\\Rightarrow a=\\sqrt{3}$ <br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0: $\\sqrt{3}$.<\/span>"}]}],"id_ques":113},{"time":24,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"select":["A. $\\frac{1}{2}$","B. $-\\frac{1}{2}$","C. $\\frac{3}{2}$","D. $-\\frac{3}{2}$"],"ques":"<span class='basic_left'>Cho \u0111\u01b0\u1eddng th\u1eb3ng $(d):\\,\\,y = (a+1)x+a$ <br\/>X\u00e1c \u0111\u1ecbnh $a$ \u0111\u1ec3 \u0111\u01b0\u1eddng th\u1eb3ng $(d)$ c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c b\u1eb1ng $\\dfrac{1}{2}$.<br\/><b> \u0110\u00e1p s\u1ed1 :<\/b> $a=$ ?<\/span>","hint":"\u0110\u01b0\u1eddng th\u1eb3ng $y = ax + b$ c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c l\u00e0 $a$.","explain":"\u0110\u01b0\u1eddng th\u1eb3ng (d) c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c l\u00e0 $\\dfrac{1}{2}$ suy ra $ a +1 = \\dfrac{1}{2} \\Leftrightarrow a= -\\dfrac{1}{2}$<br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 $-\\dfrac{1}{2}$.<\/span>"}]}],"id_ques":114},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00fang hay sai","title_trans":"","temp":"true_false","correct":[["t","f","t"]],"list":[{"point":5,"image":"https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai11/lv1/img\/2.jpg","col_name":["Trong m\u1eb7t ph\u1eb3ng $Oxy$, cho ba \u0111\u01b0\u1eddng th\u1eb3ng<br\/> $\\,d_{1}:y=2x+1$; $\\,d_{2}: y=2x-5\\,$ v\u00e0 $\\,d_{3}: y=x+1\\,$. <br\/> Khi \u0111\u00f3: ","\u0110\u00fang","Sai"],"arr_ques":["$d_{1}\/\/d_{2}$ ","$d_{2}\/\/d_{3}$","$d_{1}$ c\u1eaft $d_{3}$"],"explain":["\u0110\u00fang, v\u00ec $d_{1}$ v\u00e0 $d_{2}$ c\u00f3 h\u1ec7 s\u1ed1 $a=a'$ ($2=2$) v\u00e0 $b\\ne b'$ ($1\\ne -5$)","<br\/>Sai, v\u00ec $d_{2}$ v\u00e0 $d_{3}$ c\u00f3 $a\\ne a'$ ($2\\ne 1$) n\u00ean $d_{2}$ c\u1eaft $d_{3}$","<br\/> \u0110\u00fang, v\u00ec $d_{1}$ v\u00e0 $d_{3}$ c\u00f3 $a\\ne a'$ ($2\\ne 1$) n\u00ean $d_{1}$ c\u1eaft $d_{3}$"]}]}],"id_ques":115},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai11/lv1/img\/2.png' \/><\/center><br\/>Cho \u0111\u01b0\u1eddng th\u1eb3ng $(d):\\,\\,y = (m-3)x + 2 $. <br\/>G\u00f3c t\u1ea1o b\u1edfi \u0111\u01b0\u1eddng th\u1eb3ng $(d)\\,$ v\u1edbi tr\u1ee5c $Ox$ l\u00e0 g\u00f3c nh\u1ecdn khi: ","select":["A. $\\,m\\,= 3\\,$ ","B. $\\,m\\,<\\,3$","C. $\\,m\\,>\\,3\\,$ "],"explain":"<span class='basic_left'>G\u1ecdi $\\alpha$ l\u00e0 g\u00f3c t\u1ea1o b\u1edfi \u0111\u01b0\u1eddng th\u1eb3ng $d$ v\u00e0 $Ox$.<br\/>Ta c\u00f3, $\\alpha$ l\u00e0 g\u00f3c nh\u1ecdn, suy ra $tg\\, \\alpha >0$$\\Leftrightarrow m -3 \\,>0\\Leftrightarrow m\\,> 3$ <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><br\/><span class='basic_green'>L\u01b0u \u00fd: <\/span> \u0110\u01b0\u1eddng th\u1eb3ng $y=ax+b$ ($a$ kh\u00e1c $0$) t\u1ea1o v\u1edbi $Ox$ g\u00f3c $\\alpha$ th\u00ec $tg\\,\\alpha=a$<\/span>","column":3}]}],"id_ques":116},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Cho \u0111\u01b0\u1eddng th\u1eb3ng $(d):\\,\\,y = ax + b $ <br\/>G\u00f3c t\u1ea1o b\u1edfi \u0111\u01b0\u1eddng th\u1eb3ng $\\,(d)\\,$ v\u1edbi tr\u1ee5c $Ox$ l\u00e0 g\u00f3c t\u00f9 khi: ","select":["A. $\\,a\\,>0\\,$ ","B. $\\,a\\,<0\\,$","C. $a=0$ "],"explain":"G\u1ecdi $\\,\\alpha\\,$ l\u00e0 g\u00f3c t\u1ea1o b\u1edfi \u0111\u01b0\u1eddng th\u1eb3ng $y= ax + b$ v\u1edbi tia $Ox$<br\/>\u0110\u1ec3 $\\alpha > 90^0\\Leftrightarrow tg\\, \\alpha <0$, suy ra $a < 0$. <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span>","column":3}]}],"id_ques":117},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $\\,(d_{1})\\,\\, y = -2x+ 1\\,$ v\u00e0 $\\,(d_{2})\\,\\,y=3x+2\\,$. Khi \u0111\u00f3: ","select":["A. $d_{1}$ c\u1eaft $d_{2}$ ","B. $d_{1} \/\/ d_{2}$","C. $d_{1}\\equiv d_{2}$ ","D. $d_{1}\\bot d_{2}$ "],"explain":"Ta c\u00f3:<br\/>$(d_{1}):\\,y=-2x+1$ c\u00f3 h\u1ec7 s\u1ed1 $a= -2$. <br\/>$(d_{2}):\\,y=3x+2$ c\u00f3 h\u1ec7 s\u1ed1 $a'= 3$. <br\/>Ta th\u1ea5y: $a\\ne a' \\Rightarrow (d_{1})$ v\u00e0 $(d_{2})$ c\u1eaft nhau.<br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span>","column":2}]}],"id_ques":118},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng \u0111i qua \u0111i\u1ec3m $A (1; 0)$ v\u00e0 c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c b\u1eb1ng $2$ c\u00f3 d\u1ea1ng l\u00e0:","select":["A. $y=2x$ ","B. $y=2x+1$","C. $y=2x+2$ ","D. $y=2x-2$ "],"explain":"G\u1ecdi $(d)$ l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c l\u00e0 $2$, khi \u0111\u00f3 $(d)$ c\u00f3 d\u1ea1ng: $y=2x+b.$<br\/>Ta l\u1ea1i c\u00f3: $A(1; 0)\\,\\in\\,(d)\\,\\Leftrightarrow 2.1 + b=0 \\Leftrightarrow b= -2$<br\/>V\u1eady ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng c\u1ea7n t\u00ecm l\u00e0: $y= 2x - 2$. <br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n l\u00e0 D.<\/span>","column":4}]}],"id_ques":119},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $y = ax+ b\\,$ v\u00e0 $y=a'x+b'\\,(a,\\,a' \\ne 0)$. Hai \u0111\u01b0\u1eddng th\u1eb3ng song song v\u1edbi nhau khi: ","select":["A. $a=a',\\, b=b'$ ","B. $a= a',\\,b\\ne b'$","C. $a\\ne a',\\, b = b'$ ","D. $a\\ne a',\\, b\\ne b'$"],"explain":"Hai \u0111\u01b0\u1eddng th\u1eb3ng $\\,y=ax+b\\,(a\\ne 0)$ v\u00e0 $\\,y=a'x+b'\\,(a'\\ne 0)$ song song khi v\u00e0 ch\u1ec9 khi $a= a'$ v\u00e0 $b \\,\\ne\\, b'$<br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span>","column":2}]}],"id_ques":120}],"lesson":{"save":0,"level":1}}