{"segment":[{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"\u0110\u1ec1 chung cho b\u1ed1n c\u00e2u","temp":"fill_the_blank","correct":[[["2"],["2"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<span class='basic_left'>Tr\u00ean c\u00f9ng m\u1ed9t h\u1ec7 tr\u1ee5c t\u1ecda \u0111\u1ed9 $Oxy$ cho c\u00e1c \u0111\u01b0\u1eddng th\u1eb3ng <br\/>$\\begin{align}&\\left( {{d}_{1}} \\right):\\,y=x;\\,\\,\\left( {{d}_{2}} \\right):\\,y=-x;\\,\\,\\left( {{d}_{3}} \\right):\\,y=2\\\\&\\left( {{d}_{1}} \\right)\\cap \\left( {{d}_{3}} \\right)=A ;\\,\\,\\,\\left( {{d}_{2}} \\right)\\cap \\left( {{d}_{3}} \\right)=B\\\\ \\end{align}$ <br\/><br\/><b>C\u00e2u 1:<\/b> \u0110i\u1ec3m $A$ c\u00f3 t\u1ecda \u0111\u1ed9 l\u00e0 (_input_;_input_)<\/span>","hint":"","explain":"<span class='basic_left'> Ta c\u00f3 $\\left( {{d}_{1}} \\right):\\,\\,y=x;\\,\\,\\,\\left( {{d}_{3}} \\right):\\,\\,y=2$ <br\/>$\\left( {{d}_{1}} \\right)\\cap \\left( {{d}_{3}} \\right)=A$ <br\/>X\u00e9t ph\u01b0\u01a1ng tr\u00ecnh ho\u00e0nh \u0111\u1ed9 giao \u0111i\u1ec3m gi\u1eefa \u0111\u01b0\u1eddng th\u1eb3ng $(d_{1})$ v\u00e0 $(d_{3})$ ta c\u00f3: $x=2$. <br\/>Thay $x=2$ v\u00e0o ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng $d_1$ ta c\u00f3: $y=2$.<br\/>V\u1eady t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m $A$ l\u00e0: $ (2;2)$<br\/><span class='basic_pink'> Do \u0111\u00f3 s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u1ea7n l\u01b0\u1ee3t l\u00e0 $2; 2$.<\/span><\/span>"}]}],"id_ques":51},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"\u0110\u1ec1 chung cho b\u1ed1n c\u00e2u","temp":"fill_the_blank","correct":[[["-2"],["2"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<span class='basic_left'>Tr\u00ean c\u00f9ng m\u1ed9t h\u1ec7 tr\u1ee5c t\u1ecda \u0111\u1ed9 $Oxy$ cho c\u00e1c \u0111\u01b0\u1eddng th\u1eb3ng <br\/>$\\begin{align}&\\left( {{d}_{1}} \\right):\\,y=x;\\,\\,\\left( {{d}_{2}} \\right):\\,y=-x;\\,\\,\\left( {{d}_{3}} \\right):\\,y=2\\\\&\\left( {{d}_{1}} \\right)\\cap \\left( {{d}_{3}} \\right)=A ;\\,\\,\\,\\left( {{d}_{2}} \\right)\\cap \\left( {{d}_{3}} \\right)=B\\\\ \\end{align}$ <br\/><br\/><b>C\u00e2u 2: <\/b>\u0110i\u1ec3m $B$ c\u00f3 t\u1ecda \u0111\u1ed9 l\u00e0 (_input_;_input_)<\/span>","explain":"<span class='basic_left'> Ta c\u00f3 $\\left( {{d}_{2}} \\right):\\,\\,y=-x;\\,\\,\\,\\left( {{d}_{3}} \\right):\\,\\,y=2$ <br\/>$\\left( {{d}_{2}} \\right)\\cap \\left( {{d}_{3}} \\right)=B$ <br\/>X\u00e9t ph\u01b0\u01a1ng tr\u00ecnh ho\u00e0nh \u0111\u1ed9 giao \u0111i\u1ec3m gi\u1eefa \u0111\u01b0\u1eddng th\u1eb3ng $(d_2)$ v\u00e0 $(d_3)$, ta c\u00f3: $-x=2\\Rightarrow x=-2$<br\/>Thay $x=-2$ v\u00e0o ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng $d_2$ ta c\u00f3: $y=-(-2)=2$<br\/>V\u1eady t\u1ecda \u0111\u1ed9 c\u1ee7a \u0111i\u1ec3m $B$ l\u00e0 $(-2;2)$<br\/><span class='basic_pink'> V\u1eady c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u1ea7n l\u01b0\u1ee3t l\u00e0 $- 2; 2$.<\/span><\/span>"}]}],"id_ques":52},{"time":4,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"select":["AB = 4; OA = $\\sqrt{2}$","AB = 6; OA = $2\\sqrt{2}$","AB = 4; OA = $2\\sqrt{2}$"],"ques":"<span class='basic_left'>Tr\u00ean c\u00f9ng m\u1ed9t h\u1ec7 tr\u1ee5c t\u1ecda \u0111\u1ed9 $Oxy$ cho c\u00e1c \u0111\u01b0\u1eddng th\u1eb3ng <br\/>$\\begin{align}&\\left( {{d}_{1}} \\right):\\,y=x;\\,\\,\\left( {{d}_{2}} \\right):\\,y=-x;\\,\\,\\left( {{d}_{3}} \\right):\\,y=2\\\\&\\left( {{d}_{1}} \\right)\\cap \\left( {{d}_{3}} \\right)=A ;\\,\\,\\,\\left( {{d}_{2}} \\right)\\cap \\left( {{d}_{3}} \\right)=B\\\\ \\end{align}$ <br\/><br\/><b>C\u00e2u 3: <\/b> \u0110\u1ed9 d\u00e0i \u0111o\u1ea1n th\u1eb3ng $AB$ = ?<br\/> \u0110\u1ed9 d\u00e0i \u0111o\u1ea1n th\u1eb3ng $OA$ = ? <\/span>","hint":"H\u1ea1 $AH\\bot Oy$, ch\u1ec9 ra $H$ thu\u1ed9c $AB$","explain":"<span class='basic_left'> Theo c\u00e2u 1 v\u00e0 c\u00e2u 2 tr\u00ean, ta c\u00f3 $A (2; 2); B(-2; 2)$.<br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai10/lv1/img\/D922_D9a.png' \/><\/center> <br\/>H\u1ea1 $AH\\bot Oy$, ta c\u00f3: $H(0;2)\\Rightarrow H \\in (d_3)$.<br\/>Ta l\u1ea1i c\u00f3, $B\\in (d_3)\\Rightarrow A,H$ v\u00e0 $B$ th\u1eb3ng h\u00e0ng.<br\/>Ta c\u00f3: $AH=|x_A|=2$; $BH=|x_B|=2$. Suy ra $AB=AH+HB=2+2=4$.<br\/>X\u00e9t tam gi\u00e1c $AOH$ vu\u00f4ng t\u1ea1i $H$ c\u00f3: $AH=2; HO=2$. \u00c1P d\u1ee5ng \u0111\u1ecbnh l\u00fd Pytago ta c\u00f3:<br\/>$AO^2=AH^2+HO^2=4+4=8\\Rightarrow AO=\\sqrt {8}=2\\sqrt{2}$<br\/><span class='basic_pink'> \u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0: AB = 4; OA = $2\\sqrt{2}$ <\/span><br\/><span class='basic_green'>Nh\u1eadn x\u00e9t: <\/span>Ngo\u00e0i c\u00e1ch tr\u00ean, ta c\u00f3 th\u1ec3 t\u00ednh \u0111\u1ed9 d\u00e0i \u0111o\u1ea1n th\u1eb3ng $AB$ v\u00e0 $AO$ b\u1eb1ng c\u00e1ch \u00e1p d\u1ee5ng c\u00f4ng th\u1ee9c t\u00ednh \u0111\u1ed9 d\u00e0i \u0111o\u1ea1n th\u1eb3ng khi bi\u1ebft t\u1ecda \u0111\u1ed9 hai \u0111\u1ea7u m\u00fat.<br\/>\u0110\u1ed9 d\u00e0i \u0111o\u1ea1n th\u1eb3ng $AB$ l\u00e0:<br\/>$\\begin{align}AB & =\\sqrt{{{\\left( {{x}_{B}}-{{x}_{A}} \\right)}^{2}}+{{\\left( {{y}_{B}}-{{y}_{A}} \\right)}^{2}}} \\\\ & =\\sqrt{{{\\left( -2-2 \\right)}^{2}}+{{\\left( 2-2 \\right)}^{2}}} \\\\ & =\\sqrt{16}=4 \\\\ \\end{align}$ <br\/>\u0110\u1ed9 d\u00e0i \u0111o\u1ea1n th\u1eb3ng $OA$ l\u00e0: <br\/>$\\begin{align}AO & =\\sqrt{{{\\left( {{x}_{O}}-{{x}_{A}} \\right)}^{2}}+{{\\left( {{y}_{O}}-y_{A} \\right)}^{2}}} \\\\ & =\\sqrt{{{2}^{2}}+{{2}^{2}}} \\\\ & =2\\sqrt{2} \\\\ \\end{align}$<\/span>"}]}],"id_ques":53},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"\u0110\u1ec1 chung cho b\u1ed1n c\u00e2u","temp":"fill_the_blank_random","correct":[[["4"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<span class='basic_left'>Tr\u00ean c\u00f9ng m\u1ed9t h\u1ec7 tr\u1ee5c t\u1ecda \u0111\u1ed9 $Oxy$ cho c\u00e1c \u0111\u01b0\u1eddng th\u1eb3ng <br\/>$\\begin{align}&\\left( {{d}_{1}} \\right):\\,y=x;\\,\\,\\left( {{d}_{2}} \\right):\\,y=-x;\\,\\,\\left( {{d}_{3}} \\right):\\,y=2\\\\&\\left( {{d}_{1}} \\right)\\cap \\left( {{d}_{3}} \\right)=A ;\\,\\,\\,\\left( {{d}_{2}} \\right)\\cap \\left( {{d}_{3}} \\right)=B\\\\ \\end{align}$ <br\/><br\/><b>C\u00e2u 4: <\/b> Di\u1ec7n t\u00edch tam gi\u00e1c $OAB$ l\u00e0 _input_ (\u0111\u01a1n v\u1ecb di\u1ec7n t\u00edch)<\/span>","hint":"$S_{\\Delta OAB}=\\dfrac{1}{2}AB.OH$.","explain":"<span class='basic_left'>Theo c\u00e2u 3 tr\u00ean ta c\u00f3: $AB= 4$<br\/>$OH \\bot AB$ t\u1ea1i $H$ c\u00f3 $OH =2$ (theo h\u00ecnh v\u1ebd)<br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai10/lv1/img\/D922_D9.png' \/><\/center><br\/>$S_{\\Delta OAB}=\\dfrac{1}{2}AB.OH=\\dfrac{1}{2}.4.2=4 $ (\u0111\u01a1n v\u1ecb di\u1ec7n t\u00edch)<br\/><span class='basic_pink'> Do \u0111\u00f3 s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $4$.<\/span>"}]}],"id_ques":54},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai10/lv1/img\/4.jpg' \/><\/center>\u0110i\u1ec3m $P (1;2)$ thu\u1ed9c \u0111\u01b0\u1eddng th\u1eb3ng n\u00e0o sau \u0111\u00e2y?","select":["A. $y=2x-1$","B. $y=x+1$","C. $y=-x+4$ "],"hint":"Thay t\u1ecda \u0111\u1ed9 c\u1ee7a $P$ v\u00e0o c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/>Thay t\u1ecda \u0111\u1ed9 c\u1ee7a $P$ v\u00e0o t\u1eebng \u0111\u01b0\u1eddng th\u1eb3ng <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Thay t\u1ecda \u0111\u1ed9 c\u1ee7a $P$ v\u00e0o t\u1eebng \u0111\u01b0\u1eddng th\u1eb3ng ta c\u00f3: <br\/>$\\begin{align} & 2.1-1=1\\ne 2\\,\\,\\Rightarrow P\\left( 1;2 \\right)\\notin y=2x-1 \\\\ & 1+1=2\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\Rightarrow P\\left( 1;2 \\right)\\in y=x+1 \\\\ & -1+4=3\\ne 2\\Rightarrow P\\left( 1;2 \\right)\\notin y=-x+4 \\\\ \\end{align}$ <br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n l\u00e0 B.<\/span>","column":3}]}],"id_ques":55},{"time":24,"part":[{"title":"V\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y = 2x+1$","title_trans":"","temp":"coordinates","correct":[["0,1","0.5,2","1.5,4","2,5","2.5,6","-0.5,0","-1,-1","-1.5,-2","-2,-3","-2.5,-4","-3,-5","-3.5,-6"]],"list":[{"point":5,"toa_do":[["1","3","A"]],"is_click":1,"name_toado_click":"B","draw_line":1,"ques":"Cho \u0111i\u1ec3m $A (1; 3)$ thu\u1ed9c \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y = 2x+1$. H\u00e3y click th\u00eam m\u1ed9t \u0111i\u1ec3m thu\u1ed9c \u0111\u1ed3 th\u1ecb \u0111\u1ec3 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1.<br\/>_inputduongthang_ <br\/> ","explain":"<span class='basic_left'>Ta x\u00e1c \u0111\u1ecbnh \u0111i\u1ec3m $B$ b\u1ea5t k\u1ef3 c\u0169ng thu\u1ed9c \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y = 2x+1$ b\u1eb1ng c\u00e1ch:<br\/> Cho $x= 0 \\Rightarrow y=1\\Rightarrow B (0;1)$<br\/>\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y=2x+1$ l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng \u0111i qua $A, B$.<br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai10/lv1/img\/D922_D7a.png' \/><\/center>"}]}],"id_ques":56},{"time":4,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"select":["$a = -\\dfrac{1}{2}$","$a =\\dfrac{1}{2}$","$a = \\dfrac{3}{2}$"],"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai10/lv1/img\/9.jpg' \/><\/center>Bi\u1ebft \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y=2ax -3$ \u0111i qua \u0111i\u1ec3m $M(-1;-2)$. T\u00ecm $a$.<br\/>\u0110\u00e1p \u00e1n: $a=$?","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<br\/><\/span>Thay t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m $M(-1;-2)$ v\u00e0o \u0111\u01b0\u1eddng th\u1eb3ng $y= 2ax -3$. <br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3: $M(-1;-2) \\in y= 2ax - 3$ <br\/> Thay t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m $M$ v\u00e0o \u0111\u01b0\u1eddng th\u1eb3ng $y$ \u0111\u00e3 cho, ta \u0111\u01b0\u1ee3c: <br\/> $ -2=2a.(-1)-3\\Leftrightarrow a =-\\dfrac{1}{2}$<br\/><span class='basic_pink'> \u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0: $-\\dfrac{1}{2}$.<\/span>"}]}],"id_ques":57},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y= \\dfrac{1}{4}x-3$ c\u1eaft tr\u1ee5c tung t\u1ea1i \u0111i\u1ec3m:","select":["A. $M(0; -3)$","B. $M(0; 3)$","C. $M\\left( 0; 12 \\right)$ ","D. $M\\left( 0; -12 \\right)$ "],"hint":"\u0110\u1ed3 th\u1ecb $y= ax + b\\, (a \\ne 0)$ l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng c\u1eaft tr\u1ee5c tung t\u1ea1i $A (0;b)$, tr\u1ee5c ho\u00e0nh t\u1ea1i $B\\left(- \\dfrac{b}{a};0 \\right)$ ","explain":"<span class='basic_left'> Thay $x=0$ v\u00e0o h\u00e0m s\u1ed1 $y= \\dfrac{1}{4}x-3$, ta c\u00f3: $y=\\dfrac{1}{4}.0-3=-3\\Leftrightarrow y= -3$ <br\/>\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y= \\dfrac{1}{4}x-3$ c\u1eaft tr\u1ee5c tung t\u1ea1i \u0111i\u1ec3m $M\\left( 0; -3 \\right)$. <br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n l\u00e0 A.<\/span>","column":4}]}],"id_ques":58},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai10/lv1/img\/2.jpg' \/><\/center>Cho $A (2; 0)$ v\u00e0 $B(0; 3)$. Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng $AB$ c\u00f3 d\u1ea1ng l\u00e0: ","select":["A. $y=-\\dfrac{3}{2}x+3$ ","B. $y=-\\dfrac{3}{2}x-3$","C. $ y=\\dfrac{3}{2}x+3$","D. $y=\\dfrac{3}{2}x-3$ "],"hint":"Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng c\u00f3 d\u1ea1ng $y= ax + b$ <br\/>Thay t\u1ecda \u0111\u1ed9 c\u1ee7a $A$ v\u00e0 $B$ v\u00e0o \u0111\u01b0\u1eddng th\u1eb3ng tr\u00ean \u0111\u1ec3 t\u00ecm ra $a$ v\u00e0 $b$. ","explain":"<span class='basic_left'> Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng $AB$ c\u00f3 d\u1ea1ng $y=ax+b\\,\\,\\,\\left( d \\right)$ <br\/> Theo b\u00e0i: $A\\left( 2;0 \\right)\\,\\in\\, d$$\\Rightarrow a.2+b=0\\Leftrightarrow 2a=-b $<br\/> $ B\\left( 0,3 \\right)\\,\\in \\, d$$\\Rightarrow a.0+b=3\\Leftrightarrow b=3 $ <br\/>Suy ra $a= \\dfrac{-3}{2}$<br\/>V\u1eady ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng $AB$ l\u00e0 $y=\\dfrac{-3}{2}x + 3$<br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n l\u00e0 A.<\/span>","column":2}]}],"id_ques":59},{"time":24,"part":[{"title":"Kh\u1eb3ng \u0111\u1ecbnh sau \u0110\u00fang hay Sai","title_trans":"","temp":"true_false","correct":[["f","t","f"]],"list":[{"point":5,"image":"img\/4.jpg","col_name":["Cho h\u00e0m s\u1ed1 $y= 2x$","\u0110\u00fang","Sai"],"arr_ques":["H\u00e0m s\u1ed1 ngh\u1ecbch bi\u1ebfn tr\u00ean $\\mathbb{R}$","\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 lu\u00f4n \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9","\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u1eaft tr\u1ee5c ho\u00e0nh t\u1ea1i \u0111i\u1ec3m c\u00f3 t\u1ecda \u0111\u1ed9 b\u1eb1ng $2$"],"hint":"H\u00e0m s\u1ed1 $y= ax+ b$ (v\u1edbi $a \\ne 0$) \u0111\u1ed3ng bi\u1ebfn n\u1ebfu $a >0$ v\u00e0 ngh\u1ecbch bi\u1ebfn n\u1ebfu $a < 0$","explain":["<span class='basic_left'>1 - Sai, v\u00ec h\u00e0m s\u1ed1 $y=2x$ c\u00f3 h\u1ec7 s\u1ed1 $a=2 > 0 \\Rightarrow$ H\u00e0m s\u1ed1 \u0111\u1ed3ng bi\u1ebfn tr\u00ean $\\mathbb{R}$. <\/span>","<span class='basic_left'> 2 - \u0110\u00fang, v\u00ec h\u00e0m s\u1ed1 $y= 2x$ c\u00f3 d\u1ea1ng $y=ax$ l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng lu\u00f4n \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 $O (0;0)$. <\/span>","<span class='basic_left'>3 - Sai, v\u00ec $x= 2\\Rightarrow y= 4 \\Rightarrow A(2,4) \\notin Ox$ <\/span>"]}]}],"id_ques":60},{"time":24,"part":[{"title":"V\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y = x+3$","title_trans":"","temp":"coordinates","correct":[["0,3","0.5,3.5","1.5,4.5","2,5","2.5,5.5","-0.5,2.5","-1,2","-1.5,1.5","-2,1","-2.5,0.5","-3,0","-3.5,-0.5","-4,-1","-4.5,-1.5"]],"list":[{"point":5,"toa_do":[["1","4","A"]],"is_click":1,"name_toado_click":"B","draw_line":1,"ques":"Cho s\u1eb5n \u0111i\u1ec3m $A (1; 4)$. H\u00e3y click th\u00eam m\u1ed9t \u0111i\u1ec3m thu\u1ed9c \u0111\u1ed3 th\u1ecb \u0111\u1ec3 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1.<br\/>_inputduongthang_ <br\/> ","explain":"<span class='basic_left'><span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/>Cho x = 0 $\\Rightarrow$ y= b $\\Rightarrow B(0;b)$<br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Cho $x= 0 \\Rightarrow y=3\\Rightarrow B (0,3)$<br\/> N\u1ed1i $A$ v\u1edbi $B$ \u0111\u01b0\u1ee3c \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 $y=x+3$.<br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai10/lv1/img\/D922_D5a.png' \/><\/center>"}]}],"id_ques":61},{"time":4,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"select":["A. $\\dfrac{9}{2}$","B. $\\dfrac{9}{4}$","C. $\\dfrac{9}{5}$"],"ques":"<span class='basic_left'>Cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y= x + 3$. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u1eaft tr\u1ee5c $Ox$ v\u00e0 $Oy$ l\u1ea7n l\u01b0\u1ee3t t\u1ea1i $B$ v\u00e0 $A$.<br\/> <b> C\u00e2u 1: <\/b> Di\u1ec7n t\u00edch tam gi\u00e1c $AOB$ = ?(\u0111\u01a1n v\u1ecb di\u1ec7n t\u00edch)<\/span>","hint":"${{S}_{AOB}}=\\dfrac{1}{2}OA.OB$ ","explain":"<span class='basic_left'> Cho $x= 0 \\Rightarrow y=3\\,\\,\\Rightarrow A \\,(0,\\,3)\\Rightarrow OA=3$<br\/> Cho $y= 0 \\Rightarrow x=-3\\Rightarrow B (-3, 0)\\Rightarrow OB=3$<br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai10/lv1/img\/D922_D5.png' \/><\/center>${{S}_{AOB}}=\\dfrac{1}{2}OA.OB=\\dfrac{1}{2}.3.3=\\dfrac{9}{2}$ (\u0111\u01a1n v\u1ecb di\u1ec7n t\u00edch)<br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0: $\\dfrac{9}{2}$.<\/span>"}]}],"id_ques":62},{"time":4,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"select":["A. $6 + \\sqrt{2}$","B. $6 + 2\\sqrt{2}$","C. $6 + 3\\sqrt{2}$"],"ques":"<span class='basic_left'>Cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y= x + 3$. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u1eaft tr\u1ee5c $Ox$ v\u00e0 $Oy$ l\u1ea7n l\u01b0\u1ee3t t\u1ea1i $B$ v\u00e0 $A$.<br\/> <b> C\u00e2u 2: <\/b> Chu vi tam gi\u00e1c $AOB$ l\u00e0 ? <\/span>","hint":"","explain":"<span class='basic_left'>Theo c\u00e2u 1 tr\u00ean, ta c\u00f3: $OA= 3; OB= 3$. <br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai10/lv1/img\/D922_D5.png' \/><\/center><br\/>X\u00e9t $\\Delta AOB$ vu\u00f4ng t\u1ea1i $O$ c\u00f3: <br\/> $AB^2=OA^2+OB^2$ (\u0111\u1ecbnh l\u00ed Py - ta - go) <br\/> $\\Rightarrow AB^2=3^2+3^2 $ <br\/> $\\Rightarrow AB= 3\\sqrt{2}$<br\/>Chu vi tam gi\u00e1c $AOB$ l\u00e0: $OA + OB + AB= 3+3+ 3\\sqrt{2}=6+3\\sqrt{2}$<br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0: $6+3\\sqrt{2}$.<\/span>"}]}],"id_ques":63},{"time":24,"part":[{"title":"V\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y= -2x$ <br\/>(H\u00e3y click th\u00eam m\u1ed9t \u0111i\u1ec3m thu\u1ed9c \u0111\u1ed3 th\u1ecb \u0111\u1ec3 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 )","title_trans":"","temp":"coordinates","correct":[["0.5,-1","1,-2","1.5,-3","2,-4","2.5,-5","3,-6","-0.5,1","-1,2","-1.5,3","-2,4","-2.5,5","-3,6"]],"list":[{"point":5,"toa_do":[["0","0",""]],"is_click":1,"name_toado_click":"A","draw_line":1,"ques":"<br\/>_inputduongthang_ <br\/> Cho \u0111i\u1ec3m $O(0; 0)$ thu\u1ed9c \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y= -2x$.","hint":"T\u00ecm th\u00eam m\u1ed9t \u0111i\u1ec3m kh\u00e1c $O$ thu\u1ed9c \u0111\u1ed3 th\u1ecb","explain":"<span class='basic_left'> Thay $x=1$ v\u00e0o \u0111\u01b0\u1eddng th\u1eb3ng $y=-2x$, ta \u0111\u01b0\u1ee3c: <br\/> $y=-2.1=-2$ <br\/> \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y=-2x$ l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 $O(0; 0)$ v\u00e0 \u0111i\u1ec3m $A (1; -2)$. <br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai10/lv1/img\/D922_D3.png' \/><\/center>"}]}],"id_ques":64},{"time":24,"part":[{"title":"Kh\u1eb3ng \u0111\u1ecbnh sau \u0110\u00fang hay Sai","title_trans":"","temp":"true_false","correct":[["t","f","t"]],"list":[{"point":5,"image":"img\/2.png","col_name":["","\u0110\u00fang","Sai"],"arr_ques":["G\u1ed1c t\u1ecda \u0111\u1ed9 bi\u1ec3u di\u1ec5n \u0111i\u1ec3m $O (0; 0)$ ","Nh\u1eefng \u0111i\u1ec3m c\u00f3 ho\u00e0nh \u0111\u1ed9 b\u1eb1ng $0$ n\u1eb1m tr\u00ean tr\u1ee5c ho\u00e0nh","\u0110\u1ed3 th\u1ecb $y=x$ \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 $O(0; 0)$"],"hint":"\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y= ax$ l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng lu\u00f4n \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 $O(0; 0)$.","explain":["<span class='basic_left'>1 - \u0110\u00fang, v\u00ec g\u1ed1c t\u1ecda \u0111\u1ed9 l\u00e0 \u0111i\u1ec3m $O(0; 0)$.<br\/> <\/span>","<span class='basic_left'>2 - Sai, v\u00ec \u0111i\u1ec3m $A(0,1)$ kh\u00f4ng n\u1eb1m tr\u00ean tr\u1ee5c ho\u00e0nh. <\/span>","<span class='basic_left'>3 - \u0110\u00fang, v\u00ec \u0111\u1ed3 th\u1ecb $y=x$ c\u00f3 d\u1ea1ng $y=ax$ l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 $O(0,0)$ <\/span>"]}]}],"id_ques":65},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai10/lv1/img\/2.jpg' \/><\/center>Cho $A (-1; 0)$ v\u00e0 $B(0; 2)$. Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng $AB$ c\u00f3 d\u1ea1ng l\u00e0: ","select":["A. $y=2x -2$ ","B. $y= 2x +2$","C. $y= 2x-1$ ","D. $y= - 2x +2$ "],"hint":"Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng c\u00f3 d\u1ea1ng $y= ax + b$. <br\/>Thay t\u1ecda \u0111\u1ed9 c\u1ee7a $A, B$ v\u00e0o ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng \u0111\u1ec3 t\u00ecm $a, b$ ","explain":"<span class='basic_left'> Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng $AB$ c\u00f3 d\u1ea1ng $y=ax+b\\,\\,\\,\\left( d \\right)$ <br\/>$A\\left( -1;0 \\right)\\in d$$\\Rightarrow a.(-1)+b=0\\Leftrightarrow b-a=0 $<br\/>$B\\left( 0,2 \\right)\\in d$$\\Rightarrow a.0+b=2\\Leftrightarrow b=2$ <br\/>Suy ra $a= 2; b=2 \\Rightarrow$ Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng $AB$ l\u00e0: $y=2x + 2$.<br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n l\u00e0 B.<\/span>","column":4}]}],"id_ques":66},{"time":24,"part":[{"title":"V\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y= x$ <br\/>(H\u00e3y click th\u00eam m\u1ed9t \u0111i\u1ec3m thu\u1ed9c \u0111\u1ed3 th\u1ecb \u0111\u1ec3 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 )","title_trans":"","temp":"coordinates","correct":[["-4.5,-4.5","-4,-4","-3.5,-3.5","-3,-3","-2.5,-2.5","-2,-2","-1.5,-1.5","-1,-1","-0.5,-0.5","0.5,0.5","1,1","4.5,4.5","4,4","3.5,3.5","3,3","2.5,2.5","2,2","1.5,1.5"]],"list":[{"point":5,"toa_do":[["0","0",""]],"is_click":1,"name_toado_click":"A","draw_line":1,"ques":"<br\/>_inputduongthang_ <br\/> Cho s\u1eb5n \u0111i\u1ec3m $O(0; 0)$","hint":"T\u00ecm th\u00eam m\u1ed9t \u0111i\u1ec3m kh\u00e1c $O$ thu\u1ed9c \u0111\u1ed3 th\u1ecb","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<br\/><\/span>\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y=ax$ l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 $O(0; 0)$ v\u00e0 \u0111i\u1ec3m $A (1; a)$ <br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Thay $x=1$ v\u00e0o \u0111\u01b0\u1eddng th\u1eb3ng $y=x$, ta \u0111\u01b0\u1ee3c: $y=1$. <br\/> \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y=x$ l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 $O(0; 0)$ v\u00e0 \u0111i\u1ec3m $A (1; 1)$<br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai10/lv1/img\/D922_D1.png' \/><\/center>"}]}],"id_ques":67},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["2"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai10/lv1/img\/10.jpg' \/><\/center>Bi\u1ebft \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y=ax +7$ \u0111i qua \u0111i\u1ec3m $M(-1; 5)$. T\u00ecm $a$.<br\/>\u0110\u00e1p \u00e1n: $a=$ _input_","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<br\/><\/span>Thay t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m $M$ v\u00e0o ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng $y= ax + 7$. <br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3: $M(-1;5) \\in y= ax + 7$. <br\/>$\\Rightarrow 5=a.(-1)+7\\Leftrightarrow a =2$<br\/><span class='basic_pink'> Do \u0111\u00f3 s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $2$.<\/span>"}]}],"id_ques":68},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai10/lv1/img\/4.jpg' \/><\/center>\u0110i\u1ec3m $P (1;-3)$ thu\u1ed9c \u0111\u01b0\u1eddng th\u1eb3ng n\u00e0o sau \u0111\u00e2y?","select":["A. $3x-2y=3$","B. $0.x+y=4$","C. $3x-y=0$ ","D. $0.x-3y=9$ "],"explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/>Thay t\u1ecda \u0111\u1ed9 c\u1ee7a $P$ v\u00e0o t\u1eebng \u0111\u01b0\u1eddng th\u1eb3ng.<br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> Thay t\u1ecda \u0111\u1ed9 c\u1ee7a \u0111i\u1ec3m $P$ v\u00e0o t\u1eebng \u0111\u01b0\u1eddng th\u1eb3ng ta c\u00f3: <br\/>$\\begin{align} & 3.1-2.(-3)=9 \\ne 3\\Rightarrow P\\notin 3x-2y=3 \\\\ & 3.1-\\left( -3 \\right)=6\\ne 0\\,\\,\\,\\,\\,\\,\\,\\Rightarrow P\\notin 3x-y=0 \\\\ & 0.1+\\left( -3 \\right)=-3\\ne 4\\,\\,\\,\\Rightarrow P\\notin 0.x+y=4 \\\\ & 0.1-3\\left( -3 \\right)=9\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\Rightarrow P\\in 0x-3y=9 \\\\ \\end{align}$ <br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n l\u00e0 D.<\/span>","column":4}]}],"id_ques":69},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y= 2x+1\\,\\,(d)$ c\u1eaft tr\u1ee5c ho\u00e0nh t\u1ea1i \u0111i\u1ec3m:","select":["A. $M(1; 0)$","B. $M(-1; 0)$","C. $M\\left( \\dfrac{1}{2};0 \\right)$ ","D. $M\\left( -\\dfrac{1}{2};0 \\right)$ "],"hint":"\u0110\u1ed3 th\u1ecb $y= ax + b\\, (a \\ne 0)$ l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng $(d)$ c\u1eaft tr\u1ee5c tung t\u1ea1i $A (0;b)$, tr\u1ee5c ho\u00e0nh t\u1ea1i $B \\left(- \\dfrac{b}{a};0 \\right)$ ","explain":"<span class='basic_left'>\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y = 2x + 1$ c\u1eaft tr\u1ee5c ho\u00e0nh t\u1ea1i \u0111i\u1ec3m $M(x_M;y_M)$ suy ra $y_M=0$ <br\/>Ta c\u00f3: <br\/> $M\\in (d) \\Rightarrow y_M= 2x_M+1\\Leftrightarrow 0=2x_m+1 \\Leftrightarrow x_M=-\\dfrac{1}{2}$ <br\/>\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y= 2x+1$ c\u1eaft tr\u1ee5c ho\u00e0nh t\u1ea1i \u0111i\u1ec3m $M\\left( -\\dfrac{1}{2};0 \\right)$ <br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n l\u00e0 D.<\/span>","column":2}]}],"id_ques":70}],"lesson":{"save":0,"level":1}}