{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/8.jpg' \/><\/center> \u0110\u1ec3 $(x^2+ax-25)\\,: \\, (x+5)$ d\u01b0 $5$ th\u00ec: ","select":["A. $a=-1$ ","B. $a=1$","C. $a=10$","D. $a=5$"],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Th\u1ef1c hi\u1ec7n ph\u00e9p chia $(x^2+ax-25)\\,: \\, (x+5)$, t\u00ecm d\u01b0.<br\/> <b> B\u01b0\u1edbc 2:<\/b> Cho d\u01b0 \u0111\u00f3 b\u1eb1ng $5$ \u0111\u1ec3 t\u00ecm $a$. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> \u0110\u1eb7t ph\u00e9p chia <br\/> $\\left. \\begin{align} & \\begin{matrix} {{x}^{2}}+ax-25\\,\\,\\,\\,\\,\\,\\,\\,\\, \\\\ {{x}^{2}}+5x\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\, \\\\\\end{matrix} \\\\ & \\overline{\\begin{align} & \\,\\,\\,\\,\\,\\,\\left( a-5 \\right)x-25\\,\\,\\,\\,\\,\\,\\, \\\\ & \\,\\,\\,\\,\\,\\,\\left( a-5 \\right)x+5a-25\\,\\, \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\overline{\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,-5a\\,\\,\\,\\,\\,} \\\\ \\end{align}} \\\\ \\end{align} \\right|\\begin{matrix} \\dfrac{x+5}{x+a-5} \\\\ \\begin{matrix} {} \\\\ {} \\\\\\end{matrix} \\\\ {} \\\\\\end{matrix}$<br\/> V\u1eady $(x^2+ax-25)\\,: \\, (x+5)$ d\u01b0 $-5a$.<br\/> \u0110\u1ec3 ph\u00e9p chia $(x^2+ax-25)\\,: \\, (x+5)$ c\u00f3 d\u01b0 l\u00e0 $5$ th\u00ec $-5a=5\\Rightarrow a=-1$. <br\/> <span class='basic_pink'> V\u1eady ch\u1ecdn \u0111\u00e1p \u00e1n A. <\/span><\/span> ","column":2}]}],"id_ques":681},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/5.jpg' \/><\/center> \u0110\u1ec3 $(10x^2-7x+a)\\,\\vdots \\, (2x-3)$ th\u00ec: ","select":["A. $a=-11$ ","B. $a=-12$","C. $a=-13$","D. $a=-14$"],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Th\u1ef1c hi\u1ec7n ph\u00e9p chia $(10x^2-7x+a)\\,: \\, (2x-3)$, t\u00ecm s\u1ed1 d\u01b0.<br\/> <b> B\u01b0\u1edbc 2:<\/b> Cho s\u1ed1 d\u01b0 \u0111\u00f3 b\u1eb1ng $0$ \u0111\u1ec3 t\u00ecm $a$. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> \u0110\u1eb7t ph\u00e9p chia <br\/> $\\begin{matrix} \\,\\,\\,\\,\\,10{{x}^{2}}-7x+a \\\\ \\begin{matrix} 10{{x}^{2}}-15x \\\\ \\,\\,\\,\\,\\,\\,\\,\\,\\overline{\\dfrac{\\begin{matrix} \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,8x+a \\\\ \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,8x-12 \\\\\\end{matrix}}{\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,a+12}} \\\\\\end{matrix} \\\\\\end{matrix}\\left| \\begin{matrix} \\dfrac{2x-3}{5x+4} \\\\ {} \\\\ {} \\\\ {} \\\\\\end{matrix} \\right.$<br\/> V\u1eady $(10x^2-7x+a)\\,: \\, (2x-3)$ d\u01b0 $a+12$<br\/> \u0110\u1ec3 ph\u00e9p chia $ (10x^2-7x+a)\\,: \\,(2x-3)$ l\u00e0 ph\u00e9p chia h\u1ebft th\u00ec $a+12=0\\Rightarrow a=-12$. <br\/> <span class='basic_pink'> V\u1eady ch\u1ecdn \u0111\u00e1p \u00e1n B. <\/span><\/span> ","column":2}]}],"id_ques":682},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/5.jpg' \/><\/center> \u0110\u1ec3 $(4x^2-6x+a)\\,\\vdots \\, (x-3)$ th\u00ec: ","select":["A. $a=-18$ ","B. $a=11$","C. $a=-16$","D. $a=2$"],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Th\u1ef1c hi\u1ec7n ph\u00e9p chia $(4x^2-6x+a)\\,:\\, (x-3)$, t\u00ecm s\u1ed1 d\u01b0.<br\/> <b> B\u01b0\u1edbc 2:<\/b> Cho s\u1ed1 d\u01b0 \u0111\u00f3 b\u1eb1ng $0$ \u0111\u1ec3 t\u00ecm $a$. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> \u0110\u1eb7t ph\u00e9p chia <br\/> $\\begin{matrix} \\,\\,\\,\\,4{{x}^{2}}-6x+a \\\\ \\begin{matrix} 4{{x}^{2}}-12x \\\\ \\,\\,\\,\\,\\,\\,\\,\\,\\overline{\\dfrac{\\begin{matrix} \\,\\,\\,\\,\\,\\,6x+a \\\\ \\,\\,\\,\\,\\,\\,\\,6x-18 \\\\\\end{matrix}}{\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,a+18}} \\\\\\end{matrix} \\\\\\end{matrix}\\left|\\begin{matrix} \\dfrac{x-3}{4x+6} \\\\ {} \\\\ {} \\\\ {} \\\\\\end{matrix} \\right.$<br\/> V\u1eady $(4x^2-6x+a)\\,: \\, (x-3)$ d\u01b0 $a+18$.<br\/> \u0110\u1ec3 ph\u00e9p chia $ (4x^2-6x+a)\\,: \\, (x-3)$ l\u00e0 ph\u00e9p chia h\u1ebft th\u00ec $a+18=0\\Rightarrow a=-18$ <br\/> <span class='basic_pink'> V\u1eady ch\u1ecdn \u0111\u00e1p \u00e1n A. <\/span><\/span> ","column":2}]}],"id_ques":683},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["x-3","-3+x"]]],"list":[{"point":5,"width":40,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/2.jpg' \/><\/center> Ph\u00e9p chia $\\left( 9x^4-6x^3-15x^2+x-3 \\right):3x^2$ c\u00f3 d\u01b0 l\u00e0 _input_","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Chia t\u1eebng h\u1ea1ng t\u1eed trong \u0111a th\u1ee9c $ 9x^4-6x^3-15x^2+x-3$ cho \u0111\u01a1n th\u1ee9c $3x^2$ <br\/> <b> B\u01b0\u1edbc 2:<\/b> Nh\u1eefng h\u1ea1ng t\u1eed n\u00e0o c\u00f3 b\u1eadc nh\u1ecf h\u01a1n b\u1eadc c\u1ee7a \u0111\u01a1n th\u1ee9c chia th\u00ec h\u1ea1ng t\u1eed \u0111\u00f3 kh\u00f4ng chia h\u1ebft cho \u0111\u01a1n th\u1ee9c chia, v\u00e0 \u0111\u00f3 ch\u00ednh l\u00e0 d\u01b0 c\u1ee7a ph\u00e9p chia. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/>$Do\\,\\,\\left\\{ \\begin{align} & 9{{x}^{4}}\\,\\,\\vdots \\,\\,3{{x}^{2}} \\\\ & 6{{x}^{3}}\\,\\vdots \\,\\,3{{x}^{2}} \\\\ & 15{{x}^{2}}\\,\\vdots \\,\\,3{{x}^{2}} \\\\ & x\\,\\not\\vdots \\,\\,3{{x}^{2}} \\\\ & -3\\,\\not\\vdots \\,\\,3{{x}^{2}} \\\\ \\end{align} \\right.\\Rightarrow \\left( 9{{x}^{4}}-6{{x}^{3}}-15{{x}^{2}}+x-3 \\right)\\,\\,:3{{x}^{2}}\\,\\,\\text{d\u01b0}\\,\\,\\,x-3$<br\/> Ph\u00e9p chia c\u00f3 d\u01b0 l\u00e0 $x - 3$. <br\/> <span class='basic_pink'> Do \u0111\u00f3 d\u01b0 ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $x-3$. <\/span><br\/> <b>Nh\u1eadn x\u00e9t:<\/b>V\u1edbi d\u1ea1ng b\u00e0i n\u00e0y, ngo\u00e0i c\u00e1ch gi\u1ea3i tr\u00ean ta c\u00f2n c\u00f3 th\u1ec3 s\u1eed d\u1ee5ng c\u00e1ch \u0111\u1eb7t ph\u00e9p chia v\u00e0 t\u00ecm s\u1ed1 d\u01b0. <\/span> "}]}],"id_ques":684},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["4x-4","-4+4x","4(x-1)"]]],"list":[{"point":5,"width":40,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/4.jpg' \/><\/center> Ph\u00e9p chia $\\left( 20x^4-12x^3-4x^2+4x-4 \\right):4x^2$ c\u00f3 d\u01b0 l\u00e0 _input_","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Chia t\u1eebng h\u1ea1ng t\u1eed trong \u0111a th\u1ee9c $ 20x^4-12x^3-4x^2+4x-4$ cho \u0111\u01a1n th\u1ee9c $4x^2$ <br\/> <b> B\u01b0\u1edbc 2:<\/b> Nh\u1eefng h\u1ea1ng t\u1eed n\u00e0o c\u00f3 b\u1eadc nh\u1ecf h\u01a1n b\u1eadc c\u1ee7a \u0111\u01a1n th\u1ee9c chia th\u00ec h\u1ea1ng t\u1eed \u0111\u00f3 kh\u00f4ng chia h\u1ebft cho \u0111\u01a1n th\u1ee9c chia, v\u00e0 \u0111\u00f3 ch\u00ednh l\u00e0 d\u01b0 c\u1ee7a ph\u00e9p chia <br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> $Do\\,\\,\\left\\{ \\begin{align} & 20{{x}^{4}}\\,\\,\\vdots \\,\\,4{{x}^{2}} \\\\ & -12{{x}^{3}}\\,\\vdots \\,\\,4{{x}^{2}} \\\\ & 4{{x}^{2}}\\,\\vdots \\,\\,4{{x}^{2}} \\\\ & 4x\\,\\not\\vdots \\,\\,4{{x}^{2}} \\\\ & -4\\,\\not\\vdots \\,\\,4{{x}^{2}} \\\\ \\end{align} \\right.\\Rightarrow \\left( 20x^4-12x^3-4x^2+4x-4 \\right)\\,\\,:4{{x}^{2}}\\,\\,\\text{d\u01b0}\\,\\,\\,4x-4$ <br\/> Ph\u00e9p chia c\u00f3 d\u01b0 l\u00e0 $4x-4$ <br\/> <span class='basic_pink'> Do \u0111\u00f3 d\u01b0 ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $4x-4$. <\/span><\/span> "}]}],"id_ques":685},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["5x+2","2+5x"]]],"list":[{"point":5,"width":40,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/3.jpg' \/><\/center> Ph\u00e9p chia $\\left( 12x^4+20x^3+4x^2+5x+2 \\right):4x^2$ c\u00f3 d\u01b0 l\u00e0 _input_","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Chia t\u1eebng h\u1ea1ng t\u1eed trong \u0111a th\u1ee9c $ 12x^4+20x^3+4x^2+5x+2$ cho \u0111\u01a1n th\u1ee9c $4x^2$ <br\/> <b> B\u01b0\u1edbc 2:<\/b> Nh\u1eefng h\u1ea1ng t\u1eed n\u00e0o c\u00f3 b\u1eadc nh\u1ecf h\u01a1n b\u1eadc c\u1ee7a \u0111\u01a1n th\u1ee9c chia th\u00ec h\u1ea1ng t\u1eed \u0111\u00f3 kh\u00f4ng chia h\u1ebft cho \u0111\u01a1n th\u1ee9c chia, v\u00e0 \u0111\u00f3 ch\u00ednh l\u00e0 d\u01b0 c\u1ee7a ph\u00e9p chia. <br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> $Do\\,\\,\\left\\{ \\begin{align} & 12{{x}^{4}}\\,\\,\\vdots \\,\\,4{{x}^{2}} \\\\ & 20{{x}^{3}}\\,\\vdots \\,\\,4{{x}^{2}} \\\\ & 4{{x}^{2}}\\,\\vdots \\,\\,4{{x}^{2}} \\\\ & 5x\\,\\not\\vdots \\,\\,4{{x}^{2}} \\\\ & 2\\,\\not\\vdots \\,\\,4{{x}^{2}} \\\\ \\end{align} \\right.$$\\Rightarrow \\left( 12x^4+20x^3+4x^2+5x+2 \\right)\\,\\,:4{{x}^{2}}\\,\\,\\text{d\u01b0}\\,\\,\\,5x+2$ <br\/> Ph\u00e9p chia c\u00f3 d\u01b0 l\u00e0 $5x+2$ <br\/> <span class='basic_pink'> Do \u0111\u00f3 d\u01b0 ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $5x+2$. <\/span><\/span> "}]}],"id_ques":686},{"time":24,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"select":["A. $\\left[ \\begin{aligned} & x= 0 \\\\ & x = \\dfrac{1}{2} \\\\ & x =\\dfrac{-1}{2} \\\\ \\end{aligned} \\right. $","B. $\\left[ \\begin{aligned} & x =\\dfrac{-2}{3} \\\\ & x = 1 \\\\ & x =\\dfrac{1}{3} \\\\ \\end{aligned} \\right. $","C. $\\left[ \\begin{aligned} & x =\\dfrac{-1}{3} \\\\ & x = 1 \\\\ & y=\\dfrac{1}{3} \\\\ \\end{aligned} \\right. $"],"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/16.jpg' \/><\/center>Bi\u1ebft $(12x^4+12x^3-3x^2-3x):(3x+3)=0$, gi\u00e1 tr\u1ecb c\u1ee7a $x =?$","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Ph\u00e2n t\u00edch $12x^4+12x^3-3x^2-3x$ th\u00e0nh nh\u00e2n t\u1eed b\u1eb1ng c\u00e1ch nh\u00f3m h\u1ea1ng t\u1eed r\u1ed3i \u0111\u1eb7t nh\u00e2n t\u1eed chung<br\/> <b> B\u01b0\u1edbc 2:<\/b> Th\u1ef1c hi\u1ec7n ph\u00e9p chia \u0111\u1ec3 t\u00ecm gi\u00e1 tr\u1ecb c\u1ee7a $x$. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> $ (12x^4+12x^3-3x^2-3x):(3x+3)=0 \\\\ \\Leftrightarrow [(12x^4+12x^3)-(3x^2+3x)](3x+3)=0 \\\\ \\Leftrightarrow [12x^3(x+1)-3x(x+1)]:3(x+1)=0 \\\\ \\Leftrightarrow 3x(x+1)(4x^2-1):3(x+1)=0 \\\\ \\Leftrightarrow x(4x^2-1)=0 \\\\ \\Leftrightarrow x(2x-1)(2x+1)=0 \\\\ \\Leftrightarrow \\left[ \\begin{align} & x=0 \\\\ & x=\\dfrac{1}{2} \\\\ & x=-\\dfrac{1}{2} \\\\ \\end{align} \\right.$<\/span> "}]}],"id_ques":687},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["1"]]],"list":[{"point":5,"width":40,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/13.jpg' \/><\/center>Bi\u1ebft $(8+y^3):(4-2y+y^2)=3$, gi\u00e1 tr\u1ecb c\u1ee7a $y$ l\u00e0 _input_","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Ph\u00e2n t\u00edch $8+y^3$ theo h\u1eb1ng \u0111\u1eb3ng th\u1ee9c $a^3+b^3=(a+b)(a^2-ab+b^2)$.<br\/> <b> B\u01b0\u1edbc 2:<\/b> Th\u1ef1c hi\u1ec7n ph\u00e9p chia \u0111\u00e3 cho \u0111\u1ec3 t\u00ecm gi\u00e1 tr\u1ecb c\u1ee7a y. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> $ (8+y^3):(4-2y+y^2) =3 \\\\ \\Leftrightarrow (2+y)(4-2y+y^2):(4-2y+y^2) =3 \\\\ \\Leftrightarrow 2+y =3 \\\\ \\Leftrightarrow y =1 $ <br\/> <span class='basic_pink'> Do \u0111\u00f3 s\u1ed1 ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $1$. <\/span><\/span> "}]}],"id_ques":688},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["-1"]]],"list":[{"point":5,"width":40,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/12.jpg' \/><\/center>Bi\u1ebft $(4x^2-4):(2x-2)=0$, gi\u00e1 tr\u1ecb c\u1ee7a $x$ l\u00e0 _input_","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Ph\u00e2n t\u00edch $4x^2-4$ theo h\u1eb1ng \u0111\u1eb3ng th\u1ee9c $a^2-b^2=(a+b)(a-b)$.<br\/> <b> B\u01b0\u1edbc 2:<\/b> Th\u1ef1c hi\u1ec7n ph\u00e9p chia \u0111\u00e3 cho \u0111\u1ec3 t\u00ecm gi\u00e1 tr\u1ecb c\u1ee7a $x$. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> $ (4x^2-4):(2x-2)=0 \\\\ \\Leftrightarrow (2x+2)(2x-2):(2x-2)=0 \\\\ \\Leftrightarrow 2x+2=0 \\\\ \\Leftrightarrow x=-1 $ <br\/> <span class='basic_pink'> Do \u0111\u00f3 s\u1ed1 ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $-1$. <\/span><\/span> "}]}],"id_ques":689},{"time":24,"part":[{"title":"\u0110i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["-18"]]],"list":[{"point":5,"width":50,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/11.jpg' \/><\/center> \u0110\u1ec3 ph\u00e9p chia $(3x^3-3x^2+ax):(3x+6)$ l\u00e0 ph\u00e9p chia h\u1ebft th\u00ec $a$ = _input_","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Th\u1ef1c hi\u1ec7n ph\u00e9p chia $(3x^3-3x^2+ax):(3x+6)$, t\u00ecm s\u1ed1 d\u01b0.<br\/> <b> B\u01b0\u1edbc 2:<\/b> Cho s\u1ed1 d\u01b0 \u0111\u00f3 b\u1eb1ng $0$ \u0111\u1ec3 t\u00ecm $a, b.$ <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> Ta c\u00f3: <br\/> $\\left. \\begin{matrix} 3{{x}^{3}}-3{{x}^{2}}+ax\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\, \\\\ \\begin{aligned} & \\underline{3{{x}^{3}}+6{{x}^{2}}\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,} \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,-9{{x}^{2}}+ax\\,\\,\\,\\,\\,\\,\\,\\,\\, \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,-9{{x}^{2}}-18x \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\overline{\\begin{aligned} & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\left( a+18 \\right)x \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\left( a+18 \\right)x+2a+36 \\\\ & \\overline{\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,-2a-36\\,\\,\\,\\,} \\\\ \\end{aligned}} \\\\ \\end{aligned} \\\\\\end{matrix} \\right|\\begin{matrix} \\begin{matrix} \\begin{aligned} & 3x+6 \\\\ & \\overline{{{x}^{2}}-3x+\\dfrac{a+18}{3}} \\\\ & \\\\ \\end{aligned} \\\\ {} \\\\ {} \\\\ {} \\\\\\end{matrix} \\\\ {} \\\\\\end{matrix}$<br\/> V\u1eady $(3x^3-3x^2+ax-b):(3x+6)=x^2-3x +\\dfrac{a+18}{3}$ d\u01b0 $-2a-36$.<br\/> \u0110\u1ec3 ph\u00e9p chia $(3x^3-3x^2+ax):(3x+6)$ l\u00e0 ph\u00e9p chia h\u1ebft th\u00ec s\u1ed1 d\u01b0 b\u1eb1ng $0$, t\u1ee9c l\u00e0: <br\/>$-2a - 36 = 0 \\\\ \\Leftrightarrow a = -18$<br\/> <span class='basic_pink'> Do \u0111\u00f3 s\u1ed1 ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $-18$. <\/span><\/span> "}]}],"id_ques":690},{"time":24,"part":[{"title":"\u0110i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["-51"]]],"list":[{"point":5,"width":50,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/11.jpg' \/><\/center> \u0110\u1ec3 ph\u00e9p chia $(x^3-2x^2+x-m+2):(x+3)$ c\u00f3 s\u1ed1 d\u01b0 b\u1eb1ng $5$ th\u00ec $m$ = _input_","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Th\u1ef1c hi\u1ec7n ph\u00e9p chia $(x^3-2x^2+x-m+2):(x+3)$, t\u00ecm s\u1ed1 d\u01b0.<br\/> <b> B\u01b0\u1edbc 2:<\/b> Cho s\u1ed1 d\u01b0 \u0111\u00f3 b\u1eb1ng $5$ \u0111\u1ec3 t\u00ecm $m$. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> Ta c\u00f3: <br\/> $\\left. \\begin{align} & \\begin{matrix} {{x}^{3}}-2{{x}^{2}}+x-m+2\\, \\\\ {{x}^{3}}+3{{x}^{2}}\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\, \\\\\\end{matrix} \\\\ & \\overline{\\,\\,\\,\\,\\,\\,-5{{x}^{2}}+x-m+2\\,\\,\\,\\,\\,\\,\\,} \\\\ \\end{align} \\right|\\begin{matrix} \\dfrac{x+3}{{{x}^{2}}} \\\\ {} \\\\\\end{matrix}$<br\/> Ti\u1ebfp t\u1ee5c chia:<br\/>$\\left. \\begin{align} & -5{{x}^{2}}+x-m+2 \\\\ & -5{{x}^{2}}-15x \\\\ & \\overline{\\begin{align} & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,16x-m+2 \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,16x+48 \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\overline{\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,-m-46} \\\\ \\end{align}} \\\\ \\end{align} \\right|\\begin{matrix} \\dfrac{x+3}{{{x}^{2}}-5x+16} \\\\ {} \\\\\\end{matrix}$ <br\/> V\u1eady $(x^3-2x^2+x-m+2):(x+3)=x^2-5x+16$ d\u01b0 $-m-46$.<br\/> \u0110\u1ec3 ph\u00e9p chia c\u00f3 s\u1ed1 d\u01b0 b\u1eb1ng $5$ th\u00ec $-m-46=5\\Rightarrow m=-51$. <br\/> <span class='basic_pink'> Do \u0111\u00f3 s\u1ed1 ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $-51$. <\/span><\/span> "}]}],"id_ques":691},{"time":24,"part":[{"title":"\u0110i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["-20"]]],"list":[{"point":5,"width":50,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/11.jpg' \/><\/center> \u0110\u1ec3 ph\u00e9p chia $(2x^2-x+a):(2x-5)$ c\u00f3 s\u1ed1 d\u01b0 l\u00e0 $-10$ th\u00ec $a$ = _input_","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Th\u1ef1c hi\u1ec7n ph\u00e9p chia $(2x^2-x+a):(2x-5)$, t\u00ecm s\u1ed1 d\u01b0.<br\/> <b> B\u01b0\u1edbc 2:<\/b> Cho s\u1ed1 d\u01b0 \u0111\u00f3 b\u1eb1ng $-10$ \u0111\u1ec3 t\u00ecm $a$. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> Ta c\u00f3: <br\/> $\\begin{matrix} \\,\\,\\,\\,\\,\\,2{{x}^{2}}-x+a \\\\ \\begin{matrix} 2{{x}^{2}}-5x \\\\ \\,\\,\\,\\,\\,\\,\\,\\,\\overline{\\dfrac{\\begin{matrix} \\,\\,\\,\\,\\,\\,\\,\\,\\,4x+a \\\\ \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,4x-10 \\\\\\end{matrix}}{\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,a+10}} \\\\\\end{matrix} \\\\\\end{matrix}\\left| \\begin{matrix} \\dfrac{2x-5}{x+2} \\\\ {} \\\\ {} \\\\ {} \\\\\\end{matrix} \\right.$<br\/> V\u1eady $(2x^2-x+a):(2x-5)=x+2$ d\u01b0 $a+10$<br\/> \u0110\u1ec3 s\u1ed1 d\u01b0 b\u1eb1ng $-10$, t\u1ee9c l\u00e0: $a+10=-10\\Rightarrow a = -20$ <br\/> <span class='basic_pink'> Do \u0111\u00f3 s\u1ed1 ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 -$20$. <\/span><\/span> "}]}],"id_ques":692},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/10.jpg' \/><\/center> K\u1ebft qu\u1ea3 ph\u00e9p chia $(16+24y+9y^2):(4+3y)$ l\u00e0: ","select":["A. $4+3y$ ","B. $y+1$ ","C. $4-3y$","D. $1-y$"],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Ph\u00e2n t\u00edch \u0111a th\u1ee9c $16+24y+9y^2$ th\u00e0nh nh\u00e2n t\u1eed theo c\u00e1ch d\u00f9ng h\u1eb1ng \u0111\u1eb3ng th\u1ee9c.<br\/> <b> B\u01b0\u1edbc 2:<\/b> Th\u1ef1c hi\u1ec7n ph\u00e9p chia sau khi ph\u00e2n t\u00edch. <br\/><span class='basic_green'>Gi\u1ea3i<\/span><br\/><span class='basic_left'>Ta c\u00f3:<br\/> $16+24y+9y^2=(4+3y)^2$ <br\/> Khi \u0111\u00f3:<br\/> $(16+24y+9y^2):(4+3y)=(4+3y)^2:(4+3y)=4+3y$. <span><br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span>","column":2}]}],"id_ques":693},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/9.jpg' \/><\/center> K\u1ebft qu\u1ea3 ph\u00e9p chia $(20x^4-20x^3+10x^2):5x^2$ l\u00e0: ","select":["A. $4x^2-4x+2$ ","B. $(2x+1)^2$ ","C. $(2x-1)^2$","D. $4x^2-3x+1$"],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Ph\u00e2n t\u00edch \u0111a th\u1ee9c $20x^4-20x^3+10x^2$ th\u00e0nh nh\u00e2n t\u1eed theo c\u00e1ch \u0111\u1eb7t nh\u00e2n t\u1eed chung.<br\/> <b> B\u01b0\u1edbc 2:<\/b> Th\u1ef1c hi\u1ec7n ph\u00e9p chia sau khi ph\u00e2n t\u00edch. <br\/><span class='basic_green'>Gi\u1ea3i<\/span><br\/><span class='basic_left'>Ta c\u00f3:<br\/> $ 20{{x}^{4}}-20{{x}^{3}}+10{{x}^{2}} =10{{x}^{2}}\\left( 2{{x}^{2}}-2x+1 \\right)$ <br\/> Khi \u0111\u00f3:<br\/> $10{{x}^{2}}\\left( 2{{x}^{2}}-2x+1 \\right):5{{x}^{2}}=2\\left( 2{{x}^{2}}-2x+1 \\right)=4{{x}^{2}}-4x+2$ <span><br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span>","column":2}]}],"id_ques":694},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/8.jpg' \/><\/center> K\u1ebft qu\u1ea3 ph\u00e9p chia $(16x^4+8x^3-12x^2):4x^2$ l\u00e0: ","select":["A. $4x^2-2x+3$ ","B. $4x^2+2x-3$ ","C. $4x^2-4x-3$","D. $4x^2-4x-8$"],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Ph\u00e2n t\u00edch \u0111a th\u1ee9c $16x^4+8x^3-12x^2$ th\u00e0nh nh\u00e2n t\u1eed theo c\u00e1ch \u0111\u1eb7t nh\u00e2n t\u1eed chung.<br\/> <b> B\u01b0\u1edbc 2:<\/b> Th\u1ef1c hi\u1ec7n ph\u00e9p chia sau khi ph\u00e2n t\u00edch. <br\/><span class='basic_green'>Gi\u1ea3i<\/span><br\/><span class='basic_left'>Ta c\u00f3:<br\/> $16x^4+8x^3-12x^2=4x^2(4x^2+2x-3)$<br\/> Khi \u0111\u00f3:<br\/> $(16x^4+8x^3-12x^2):4x^2=4x^2(4x^2+2x-3):4x^2=4x^2+2x-3$ <span><br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span>","column":2}]}],"id_ques":695},{"time":24,"part":[{"title":"\u0110i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng \u0111\u1ec3 ho\u00e0n th\u00e0nh ph\u00e9p chia sau ","title_trans":"","temp":"fill_the_blank_random","correct":[[["2x"],["1"]]],"list":[{"point":5,"width":50,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/5.jpg' \/><\/center> $(8x^3+1):(\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}+\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{})=4x^2-2x+1$","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b>Ph\u00e2n t\u00edch $8x^3+1$ th\u00e0nh nh\u00e2n t\u1eed b\u1eb1ng c\u00e1ch s\u1eed d\u1ee5ng h\u1eb1ng \u0111\u1eb3ng th\u1ee9c.<br\/> <b> B\u01b0\u1edbc 2:<\/b> Th\u1ef1c hi\u1ec7n ph\u00e9p chia $(8x^3+1):(4x^2-2x+1)$ <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> Ta c\u00f3:<br\/> $ (8x^3+1):(4x^2-2x+1) $<br\/>$ =(2x+1)(4x^2-2x+1):(4x^2-2x+1) $<br\/>$ =2x+1 $ <br\/> <span class='basic_pink'> Do \u0111\u00f3 s\u1ed1 ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $2x$ v\u00e0 $1$. <\/span><\/span> "}]}],"id_ques":696},{"time":24,"part":[{"title":"\u0110i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng \u0111\u1ec3 ho\u00e0n th\u00e0nh ph\u00e9p chia sau ","title_trans":"","temp":"fill_the_blank","correct":[[["4z-1","-1+4z"]]],"list":[{"point":5,"width":50,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/5.jpg' \/><\/center> $(16z^2-8z+1):\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}=4z-1$","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Ph\u00e2n t\u00edch \u0111a th\u1ee9c b\u1ecb chia th\u00e0nh nh\u00e2n t\u1eed.<br\/> <b> B\u01b0\u1edbc 2:<\/b> Th\u1ef1c hi\u1ec7n ph\u00e9p chia $(16z^2-8z+1):(4z-1)$ <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> Ta c\u00f3 <br\/> $\\begin{align} & (16z^2-8z+1):(4z-1) \\\\ & =(4z-1)^2:(4z-1) \\\\ & =4z-1 \\\\ \\end{align}$ <br\/> <span class='basic_pink'> Do \u0111\u00f3 ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $4z-1$. <\/span><\/span> "}]}],"id_ques":697},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["x+1","1+x"]]],"list":[{"point":5,"width":50,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/4.jpg' \/><\/center> K\u1ebft qu\u1ea3 ph\u00e9p chia <br\/> $(x^3+1):(x^2-x+1)=$ _input_","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Ph\u00e2n t\u00edch $x^3+1$ theo h\u1eb1ng \u0111\u1eb3ng th\u1ee9c t\u1ed5ng hai l\u1eadp ph\u01b0\u01a1ng.<br\/> <b> B\u01b0\u1edbc 2:<\/b>\u00c1p d\u1ee5ng $(a.b):b=a$ \u0111\u1ec3 th\u1ef1c hi\u1ec7n ph\u00e9p chia. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> $\\begin{align} & (x^3+1):(x^2-x+1) \\\\ & =\\left( x+1 \\right)\\left( x^2-x+1 \\right):\\left( x^2-x+1\\right) \\\\ & =x+1 \\\\ \\end{align}$ <br\/> <span class='basic_pink'> Do \u0111\u00f3 th\u01b0\u01a1ng ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $x+1$. <\/span><\/span> "}]}],"id_ques":698},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["x-2","-2+x"]]],"list":[{"point":5,"width":50,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/3.jpg' \/><\/center> K\u1ebft qu\u1ea3 ph\u00e9p chia <br\/> $(x^2-4):(x+2)=$ _input_","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Ph\u00e2n t\u00edch $x^2-4$ theo h\u1eb1ng \u0111\u1eb3ng th\u1ee9c $a^2-b^2=(a+b)(a-b)$<br\/> <b> B\u01b0\u1edbc 2:<\/b> \u00c1p d\u1ee5ng $(a.b):b=a$ \u0111\u1ec3 th\u1ef1c hi\u1ec7n ph\u00e9p chia.<br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> $\\begin{align} & ({{x}^{2}}-4):(x+2) \\\\ & =\\left( x+2 \\right)\\left( x-2 \\right):\\left( x+2 \\right) \\\\ & =x-2 \\\\ \\end{align}$ <br\/> <span class='basic_pink'> Do \u0111\u00f3 th\u01b0\u01a1ng ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $x-2$. <\/span><\/span> "}]}],"id_ques":699},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["x-1","-1+x"]]],"list":[{"point":5,"width":50,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai9/lv1/img\/2.jpg' \/><\/center> K\u1ebft qu\u1ea3 ph\u00e9p chia <br\/> $(x-1)(x+2):(x+2)=$ _input_","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> \u00c1p d\u1ee5ng $(a.b):b=a$ \u0111\u1ec3 th\u1ef1c hi\u1ec7n ph\u00e9p chia<br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> $(x-1)(x+2):(x+2)=x-1$ <br\/> <span class='basic_pink'> Do \u0111\u00f3 th\u01b0\u01a1ng ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $x-1$ <\/span><\/span> "}]}],"id_ques":700}],"lesson":{"save":0,"level":1}}