{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"T\u00ecm $m$ \u0111\u1ec3 $x = 2$ l\u00e0 nghi\u1ec7m c\u1ee7a b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh: $\\dfrac{x - 18}{4} - m < 3x - \\dfrac{m - x}{2}$","select":[" A. $m > 22$"," B. $m < 22$","C. $m > -22$","D. $m < -22$"],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/><b>B\u01b0\u1edbc 1:<\/b> Thay $x = 2$ v\u00e0o b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh \u0111\u1ec3 \u0111\u01b0\u1ee3c b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh m\u1edbi \u1ea9n $m$<br\/><b>B\u01b0\u1edbc 2:<\/b> Gi\u1ea3i b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh m\u1edbi v\u00e0 t\u00ecm $m$<\/span> <br\/><span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>V\u00ec $x = 2$ l\u00e0 nghi\u1ec7m c\u1ee7a b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh n\u00ean ta c\u00f3:<br\/>$\\dfrac{2 - 18}{4} - m < 3.2 - \\dfrac{m - 2}{2}$<br\/>$\\Leftrightarrow -4 - m < 6 - \\dfrac{m - 2}{2}$<br\/>$\\Leftrightarrow -4 - m < \\dfrac{12 - m + 2}{2}$<br\/> $\\Leftrightarrow 2(-4 - m) < 14 - m$<br\/>$\\Leftrightarrow -8 - 2m < 14 - m$<br\/>$\\Leftrightarrow -2m + m < 14 + 8$<br\/>$\\Leftrightarrow -m < 22$<br\/>$\\Leftrightarrow m > -22$<br\/>V\u1eady \u0111i\u1ec1u ki\u1ec7n c\u1ea7n t\u00ecm c\u1ee7a $m$ l\u00e0 $m > -22$<br\/>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 <span class='basic_pink'>C. $m > -22$<\/span> <\/span> <br\/><\/span><br\/>","column":2}]}],"id_ques":1141},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":"Gi\u1ea3i v\u00e0 bi\u1ec7n lu\u1eadn b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh: $(m - 2)x - 4 > x + m$ $(1)$","select":[" A. $m = 3$ th\u00ec b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh $(1)$ v\u00f4 nghi\u1ec7m"," B. $m > 3$ th\u00ec b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh $(1)$ c\u00f3 nghi\u1ec7m l\u00e0 $x > \\dfrac{m + 4}{m - 3}$","C. $m < 3$ th\u00ec b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh $(1)$ c\u00f3 nghi\u1ec7m l\u00e0 $x < \\dfrac{m + 4}{m - 3}$","D. T\u1ea5t c\u1ea3 c\u00e1c \u0111\u00e1p \u00e1n tr\u00ean \u0111\u1ec1u \u0111\u00fang"],"hint":"","explain":"<span class='basic_left'>Ta c\u00f3: $(m - 2)x - 4 > x + m \\Leftrightarrow (m - 3)x > m + 4$<br\/>+ N\u1ebfu $m - 3 = 0 \\Leftrightarrow m = 3$, th\u00ec $(1)$ tr\u1edf th\u00e0nh: $0x > 7$ (v\u00f4 l\u00ed) $\\Rightarrow$ b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh $(1)$ v\u00f4 nghi\u1ec7m<br\/>+ N\u1ebfu $m - 3 > 0 \\Leftrightarrow m > 3$, th\u00ec $(1) \\Leftrightarrow x > \\dfrac{m + 4}{m - 3}$<br\/>+ N\u1ebfu $m - 3 < 0 \\Leftrightarrow m < 3$, th\u00ec $(1) \\Leftrightarrow x < \\dfrac{m + 4}{m - 3}$<br\/><b>K\u1ebft lu\u1eadn:<\/b><br\/>+ N\u1ebfu $m = 3$ th\u00ec b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh $(1)$ v\u00f4 nghi\u1ec7m<br\/>+ N\u1ebfu $m > 3$ th\u00ec b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh (1) c\u00f3 nghi\u1ec7m l\u00e0 $x > \\dfrac{m + 4}{m - 3}$<br\/>+ N\u1ebfu $m < 3$ th\u00ec b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh $(1)$ c\u00f3 nghi\u1ec7m l\u00e0 $x < \\dfrac{m + 4}{m - 3}$<br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 D<\/span><\/span>","column":1}]}],"id_ques":1142},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"T\u00ecm $m$ \u0111\u1ec3 b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh sau nghi\u1ec7m \u0111\u00fang v\u1edbi m\u1ecdi $x \\in \\mathbb{R}$:<br\/>$m^2x \\geq 9x + m^2 + 3m$","select":[" A. $m < -3$"," B. $m > 3$ $","C. $m = -3$","D.$m = 3$"],"hint":"","explain":"<span class='basic_left'>Ta c\u00f3: $m^2x \\geq 9x + m^2 + 3m \\Leftrightarrow m^2x - 9x \\geq m^2 + 3m \\Leftrightarrow (m^2 - 9)x \\geq m(m + 3)$<br\/>B\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh nghi\u1ec7m \u0111\u00fang v\u1edbi m\u1ecdi $x \\in \\mathbb{R}$ khi v\u00e0 ch\u1ec9 khi:<br\/> $\\left\\{\\begin{array}{l} m^2 - 9 = 0\\\\ m(m + 3) \\leq 0\\end{array} \\right. \\Leftrightarrow \\left\\{\\begin{array}{l} (m - 3)(m + 3) = 0\\\\ \\left\\{\\begin{array}{l} m \\leq 0\\\\ m + 3 \\geq 0 \\end{array} \\right. \\end{array} \\right. \\Leftrightarrow \\left\\{\\begin{array}{l} \\left[\\begin{array}{l} m = -3\\\\ m = 3\\end{array} \\right.\\\\ \\left\\{\\begin{array}{l} m \\leq 0\\\\ m \\geq -3\\end{array} \\right.\\end{array} \\right. \\Leftrightarrow m = -3$<br\/>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 <span class='basic_pink'>C. $m = -3$<\/span><\/span><br\/><span class='basic_left'><span class='basic_green'>Nh\u1eadn x\u00e9t:<\/span><br\/> B\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh d\u1ea1ng: $ax \\geq b$ v\u00f4 s\u1ed1 nghi\u1ec7m khi v\u00e0 ch\u1ec9 khi:<br\/> $\\left\\{\\begin{array}{l} a = 0 \\\\ b \\leq 0\\end{array} \\right.$<\/span> <br\/><br\/>","column":2}]}],"id_ques":1143},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":"T\u00ecm $m$ \u0111\u1ec3 b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh sau nghi\u1ec7m \u0111\u00fang v\u1edbi m\u1ecdi $x \\in \\mathbb{R}$<br\/>$m^3(x + 2) \\leq m^2(x -1)$","select":[" A. $m = 0$"," B. $m = -1$ ","C. $m = -3$","D.$m = 3$"],"hint":"","explain":"<span class='basic_left'>Ta c\u00f3: $m^3(x + 2) \\leq m^2(x -1) \\Leftrightarrow m^3x - m^2x \\leq -2m^3 - m^2 \\Leftrightarrow (m^3 - m^2)x \\leq -m^2(2m + 1) $<br\/>B\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh nghi\u1ec7m \u0111\u00fang v\u1edbi m\u1ecdi $x \\in \\mathbb{R}$ khi v\u00e0 ch\u1ec9 khi:<br\/> $\\left\\{\\begin{array}{l} m^3 - m^2 = 0\\\\ -m^2(2m + 1) \\geq 0 \\end{array} \\right.$<br\/>$\\Leftrightarrow$ $\\left\\{\\begin{array}{l} m^2(m - 1) = 0 \\\\ \\left\\{\\begin{array}{l}m^2 \\geq 0 \\hspace{0,2cm} \\forall x \\\\ 2m + 1 \\leq 0 \\end{array} \\right. \\end{array} \\right.$<br\/>$\\Leftrightarrow$ $\\left\\{\\begin{array}{l} \\left[\\begin{array}{l} m = 0\\\\ m = 1 \\end{array} \\right. \\\\ \\left\\{\\begin{array}{l}\\left[\\begin{array}{l} m \\geq 0 \\\\ m \\leq 0 \\end{array} \\right. \\\\ m \\leq \\dfrac{-1}{2} \\end{array} \\right. \\end{array} \\right.$<br\/> $\\Leftrightarrow$ $m = 0$<br\/>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 <span class='basic_pink'>A. $m = 0$<\/span><\/span><br\/><span class='basic_left'><span class='basic_green'>Nh\u1eadn x\u00e9t:<\/span><br\/> B\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh d\u1ea1ng: $ax \\leq b$ v\u00f4 s\u1ed1 nghi\u1ec7m khi v\u00e0 ch\u1ec9 khi:<br\/> $\\left\\{\\begin{array}{l} a = 0 \\\\ b \\geq 0\\end{array} \\right.$<\/span> <br\/><br\/>","column":2}]}],"id_ques":1144},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"Gi\u1ea3i b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh sau: <br\/>$\\dfrac{3x + 5}{2x + 1} > 6$ $(x \\ne \\dfrac{-1}{2})$ ","select":[" A. $ x < \\dfrac{-1}{2}$ v\u00e0 $ x < \\dfrac{1}{9}$"," B. $ \\dfrac{-1}{2} < x < \\dfrac{1}{9}$","C. $ \\dfrac{-1}{9} < x < \\dfrac{-1}{2}$","D.$ \\dfrac{-1}{9} < x < \\dfrac{1}{9}$"],"hint":"","explain":"<span class='basic_left'> Ta c\u00f3: <br\/>$\\dfrac{3x + 5}{2x + 1} > 6$<br\/> $\\Leftrightarrow \\dfrac{3x + 5}{2x + 1} - 6 > 0$<br\/> $\\Leftrightarrow \\dfrac{3x + 5}{2x + 1} - \\dfrac{6(2x + 1)}{2x + 1} > 0$<br\/> $\\Leftrightarrow \\dfrac{3x + 5 - 6(2x + 1)}{2x + 1} > 0$<br\/> $\\Leftrightarrow \\dfrac{3x + 5 - 12x - 6}{2x + 1} > 0$ <br\/>$\\Leftrightarrow \\dfrac{-9x - 1}{2x + 1} > 0$<br\/>$\\Leftrightarrow$ $\\left[\\begin{array}{l} \\left\\{\\begin{array}{l} -9x - 1 > 0\\\\ 2x + 1 > 0\\end{array} \\right. \\\\ \\left\\{\\begin{array}{l} -9x - 1 < 0\\\\ 2x + 1 < 0\\end{array} \\right.\\end{array} \\right.$ <br\/>$\\Leftrightarrow$ $\\left[\\begin{array}{l} \\left\\{\\begin{array}{l} x < \\dfrac{1}{9}\\\\ x >\\dfrac{-1}{2} \\end{array} \\right. \\\\ \\left\\{\\begin{array}{l} x >\\dfrac{1}{9} \\\\ x < \\dfrac{-1}{2}\\end{array} \\right.\\end{array} \\right.$<br\/> $\\Leftrightarrow$ $ \\dfrac{-1}{2} < x < \\dfrac{1}{9}$<br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 B<\/span> <\/span>","column":2}]}],"id_ques":1145},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"T\u00ecm $m$ \u0111\u1ec3 b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh sau v\u00f4 nghi\u1ec7m:<br\/>$(m^2 + m + 1)x + 3m \\geq (m^2 + 2)x + 5m - 1$","select":[" A. $m = 0$"," B. $m = -1$ ","C. $m = 1$","D.$m = 2$"],"hint":"","explain":"<span class='basic_left'>Ta c\u00f3: <br\/>$(m^2 + m + 1)x + 3m \\geq (m^2 + 2)x + 5m - 1 \\Leftrightarrow (m^2 + m + 1)x - (m^2 + 2)x \\geq 5m - 1 - 3m \\Leftrightarrow (m - 1)x \\geq 2m - 1$<br\/>B\u1ea5t ph\u01b0\u01a1ng v\u00f4 nghi\u1ec7m khi v\u00e0 ch\u1ec9 khi:<br\/> $\\left\\{\\begin{array}{l} m - 1 = 0 \\\\ 2m - 1 > 0 \\end{array} \\right.$<br\/>$\\Leftrightarrow$ $\\left\\{\\begin{array}{l} m = 1 \\\\ m > \\dfrac{1}{2}\\end{array} \\right.$ <br\/>$\\Leftrightarrow$ $m = 1$<br\/>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 <span class='basic_pink'>C. $m = 1$<\/span><\/span><br\/><span class='basic_left'><span class='basic_green'>Nh\u1eadn x\u00e9t:<\/span><br\/> B\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh d\u1ea1ng: $ax \\geq b$ v\u00f4 nghi\u1ec7m khi v\u00e0 ch\u1ec9 khi:<br\/> $\\left\\{\\begin{array}{l} a = 0 \\\\ b > 0\\end{array} \\right.$<\/span> <br\/><br\/>","column":2}]}],"id_ques":1146},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"<span class='basic_left'><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai26/lv3/img\/5.jpg' \/><\/center> T\u00ecm c\u00e1c nghi\u1ec7m nguy\u00ean d\u01b0\u01a1ng c\u1ee7a b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh: $2(x - 3) \\leq x + 4$<\/span>","select":[" A. $x \\in \\left\\{0; 1; 2; 3; 4; 5; 6; 7; 8; 9\\right\\}$"," B. $x \\in \\left\\{1; 2; 3; 4; 5; 6; 7; 8; 9\\right\\}$","C. $x \\in \\left\\{1; 2; 3; 4; 5; 6; 7; 8; 9; 10\\right\\}$","D. $x \\in \\left\\{0; 1; 2; 3; 4; 5; 6; 7; 8; 9; 10\\right\\}$"],"hint":"S\u1eed d\u1ee5ng quy t\u1eafc chuy\u1ec3n v\u1ebf v\u00e0 quy t\u1eafc nh\u00e2n v\u1edbi m\u1ed9t s\u1ed1 \u0111\u1ec3 gi\u1ea3i b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh t\u1eeb \u0111\u00f3 t\u00ecm ra k\u1ebft qu\u1ea3 c\u1ea7n t\u00ecm.","explain":"<span class='basic_left'>Ta c\u00f3 $2(x - 3) \\leq x + 4$<br\/>$\\Leftrightarrow 2x - 6 \\leq x + 4$<br\/>$\\Leftrightarrow 2x - x \\leq 4 + 6$<br\/>$\\Leftrightarrow x \\leq 10$<br\/>V\u1eady c\u00e1c nghi\u1ec7m nguy\u00ean d\u01b0\u01a1ng c\u1ee7a b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh l\u00e0 $x \\in \\left\\{1; 2; 3; 4; 5; 6; 7; 8; 9; 10\\right\\}$ <br\/>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 <span class='basic_pink'>C.$x \\in \\left\\{1; 2; 3; 4; 5; 6; 7; 8; 9; 10\\right\\}$<\/span><\/span>","column":2}]}],"id_ques":1147},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":"<span class='basic_left'><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai26/lv3/img\/5.jpg' \/><\/center> B\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh $x^4 - x^2 + 5 > 0$ c\u00f3 nghi\u1ec7m v\u1edbi m\u1ecdi $x$. <b>\u0110\u00fang<\/b> hay <b> Sai<\/b>?<\/span>","select":[" A. \u0110\u00fang"," B. Sai"],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>Ph\u01b0\u01a1ng ph\u00e1p gi\u1ea3i:<\/span><br\/>Bi\u1ebfn \u0111\u1ed5i b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh v\u1ec1 d\u1ea1ng $\\left[f(x)\\right]^2 + k > 0$ (v\u1edbi $k > 0$)<\/span> <br\/><span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3: $x^4 - x^2 + 5 = (x^2)^2 - 2.x^2. \\dfrac{1}{2} + \\left(\\dfrac{1}{2}\\right)^2 + \\dfrac{19}{4} = \\left(x^2 - \\dfrac{1}{2}\\right)^2 + \\dfrac{19}{4}$<br\/>V\u00ec $\\left(x^2 - \\dfrac{1}{2}\\right)^2 \\geq 0$ v\u1edbi m\u1ecdi $x$ n\u00ean $ \\left(x^2 - \\dfrac{1}{2}\\right)^2 + \\dfrac{19}{4} > 0$ v\u1edbi m\u1ecdi $x$<br\/>V\u1eady $x^4 - x^2 + 5 > 0$ c\u00f3 nghi\u1ec7m v\u1edbi m\u1ecdi gi\u00e1 tr\u1ecb $x$<br\/>Ta ch\u1ecdn \u0111\u00e1p \u00e1n: <span class='basic_pink'>A. \u0110\u00fang<\/span><\/span> <br\/><\/span><br\/>","column":2}]}],"id_ques":1148},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":"<span class='basic_left'><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai26/lv3/img\/6.jpg' \/><\/center> T\u00ecm c\u00e1c nghi\u1ec7m nguy\u00ean \u00e2m c\u1ee7a b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh: $7x + 5 \\geq 5(x - 1)$<\/span>","select":[" A. $x \\in \\left\\{-5; -4; -3; -2; -1\\right\\}$"," B. $x \\in \\left\\{-5; -4; -3; -2; -1; 0\\right\\}$","C. $x \\in \\left\\{-4; -3; -2; -1\\right\\}$","D. $x \\in \\left\\{-4; -3; -2; -1; 0\\right\\}$"],"hint":"S\u1eed d\u1ee5ng quy t\u1eafc chuy\u1ec3n v\u1ebf v\u00e0 quy t\u1eafc nh\u00e2n v\u1edbi m\u1ed9t s\u1ed1 \u0111\u1ec3 gi\u1ea3i b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh t\u1eeb \u0111\u00f3 t\u00ecm ra k\u1ebft qu\u1ea3 c\u1ea7n t\u00ecm.","explain":"<span class='basic_left'>Ta c\u00f3 $7x + 5 \\geq 5(x - 1) $<br\/>$\\Leftrightarrow 7x + 5 \\geq 5x - 5$<br\/>$\\Leftrightarrow 7x - 5x \\geq -5 - 5$<br\/>$\\Leftrightarrow 2x \\geq -10$<br\/>$\\Leftrightarrow x \\geq -5$<br\/>V\u1eady c\u00e1c nghi\u1ec7m nguy\u00ean \u00e2m c\u1ee7a b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh l\u00e0 $x \\in \\left\\{-5; -4; -3; -2; -1\\right\\}$ <br\/>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 <span class='basic_pink'>A. $x \\in \\left\\{-5; -4; -3; -2; -1\\right\\}$<\/span><\/span>","column":2}]}],"id_ques":1149},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":"Gi\u1ea3i b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh sau: <br\/>$12(x - 4) - 3(2x + 1) > 5 - x$ ","select":[" $S = \\left\\{x \\mid x > -8\\right\\} $"," $S = \\left\\{x \\mid x < -8\\right\\} $","$S = \\left\\{x \\mid x < 8\\right\\} $","$S = \\left\\{x \\mid x > 8\\right\\} $"],"hint":"","explain":"<span class='basic_left'> $12(x - 4) - 3(2x + 1) > 5 - x$<br\/>$\\Leftrightarrow 12x - 48 - 6x - 3 > 5 - x$<br\/> $\\Leftrightarrow 6x - 51 > 5 - x$<br\/>$\\Leftrightarrow 6x + x > 5 + 51$<br\/>$\\Leftrightarrow 7x > 56$<br\/>$\\Leftrightarrow x > 8$ <br\/> V\u1eady $S = \\left\\{x \\mid x > 8 \\right\\}$ <br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 $S = \\left\\{x \\mid x > 8\\right\\} $<\/span> <\/span>","column":2}]}],"id_ques":1150}],"lesson":{"save":0,"level":3}}