{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":" Tr\u00ean c\u00f9ng m\u1ed9t n\u1eeda m\u1eb7t ph\u1eb3ng b\u1edd c\u00f3 ch\u1ee9a tia Ox, v\u1ebd hai tia Oy v\u00e0 Oz sao cho $\\widehat{xOy}$ = $75^o$, $\\widehat{xOz}$ = $150^o$. H\u00e3y ch\u1ecdn c\u00e2u sai:","select":["A. Tia Oy l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOz","B. Tia Oz l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOz","C. Tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz","D. $\\widehat{yOz}$ = $75^o$"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai13/lv3/img\/H624_K101.png' \/><\/center>Ta c\u00f3: $\\widehat{xOy}$ < $\\widehat{xOz}$ (v\u00ec $75^o$ < $150^o$)<br\/>N\u00ean <b>tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<\/b> (1)<br\/>Suy ra $\\widehat{xOy}$ + $\\widehat{yOz}$ = $\\widehat{xOz}$ <br\/>Thay $\\widehat{xOy}$ = $75^o$, $\\widehat{xOz}$ = $150^o$, ta \u0111\u01b0\u1ee3c:<br\/> $75^o$ + $\\widehat{yOz}$ = $150^o$<br\/>$\\widehat{yOz}$ = $150^o$ - $75^o$ = $75^o$<br\/>M\u00e0 $\\widehat{xOy}$ = $75^o$ n\u00ean <b>$\\widehat{xOy}$ = $\\widehat{yOz}$<\/b> (2)<br\/>T\u1eeb (1) v\u00e0 (2) suy ra <b>tia Oy l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOz<\/b><br\/>V\u1eady \u0111\u00e1p \u00e1n sai l\u00e0: <span class='basic_pink'>B. Tia Oz l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOz<\/span><\/span> <br\/><\/span><span class='basic_left'><span class='basic_green'>Nh\u1eadn x\u00e9t:<\/span><br\/>Oy l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOz khi:<br\/>+ Tia Oy l\u00e0 tia n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<br\/>+ $\\widehat{xOy}$ = $\\widehat{yOz}$ <\/span>","column":2}]}],"id_ques":2191},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":" Cho $\\widehat{aOb}$ = $60^o$. Bi\u1ebft tia Ot l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a $\\widehat{aOb}$. T\u00ednh $\\widehat{tOb}$","select":["A. $20^o$","B. $25^o$","C. $30^o$","D. $120^o$"],"hint":"","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai13/lv3/img\/H624_K103.png' \/><\/center>Tia Ot l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a $\\widehat{aOb}$ <br\/>Suy ra $\\widehat{aOt}$ = $\\widehat{tOb}$ = $\\dfrac{1}{2}$ $\\widehat{aOb}$ = $\\dfrac{1}{2}$. $60^o$ = $30^o$<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n : <span class='basic_pink'>C. $30^o$<\/span><\/span> <br\/>","column":2}]}],"id_ques":2192},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":" Tr\u00ean c\u00f9ng m\u1ed9t n\u1eeda m\u1eb7t ph\u1eb3ng b\u1edd c\u00f3 ch\u1ee9a tia Ox, v\u1ebd hai tia Oy v\u00e0 Oz sao cho $\\widehat{xOy}$ = $28^o$, $\\widehat{xOz}$ = $56^o$. H\u00e3y ch\u1ecdn c\u00e2u sai:","select":["A. Tia Oy l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOz","B. G\u00f3c xOy v\u00e0 yOz l\u00e0 hai g\u00f3c ph\u1ee5 nhau","C. Tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz","D. $\\widehat{yOz}$ = $28^o$"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai13/lv3/img\/H624_K106.png' \/><\/center>Ta c\u00f3: $\\widehat{xOy}$ < $\\widehat{xOz}$ (v\u00ec $28^o$ < $56^o$)<br\/>N\u00ean <b>tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<\/b> (1)<br\/>Suy ra $\\widehat{xOy}$ + $\\widehat{yOz}$ = $\\widehat{xOz}$ <br\/>Thay $\\widehat{xOy}$ = $28^o$, $\\widehat{xOz}$ = $56^o$, ta \u0111\u01b0\u1ee3c:<br\/> $28^o$ + $\\widehat{yOz}$ = $56^o$<br\/>$\\widehat{yOz}$ = $56^o$ - $28^o$ = $28^o$<br\/>M\u00e0 $\\widehat{xOy}$ = $28^o$ n\u00ean <b>$\\widehat{xOy}$ = $\\widehat{yOz}$<\/b> (2)<br\/>T\u1eeb (1) v\u00e0 (2) suy ra <b>tia Oy l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOz<\/b><br\/><br\/>+ $\\widehat{xOy}$ + $\\widehat{yOz}$ = $\\widehat{xOz}$ = $56^o$ <br\/>Do \u0111\u00f3 <b>g\u00f3c xOy v\u00e0 yOz kh\u00f4ng ph\u1ea3i l\u00e0 hai g\u00f3c ph\u1ee5 nhau<\/b><br\/>V\u1eady \u0111\u00e1p \u00e1n sai l\u00e0: <span class='basic_pink'>B. G\u00f3c xOy v\u00e0 yOz l\u00e0 hai g\u00f3c ph\u1ee5 nhau<\/span><\/span> <br\/><\/span><span class='basic_left'><span class='basic_green'>Nh\u1eadn x\u00e9t:<\/span><br\/>Oy l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOz khi:<br\/>+ Tia Oy l\u00e0 tia n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<br\/>+ $\\widehat{xOy}$ = $\\widehat{yOz}$ <\/span>","column":2}]}],"id_ques":2193},{"time":14,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["30"],["30"]]],"list":[{"point":10,"width":60,"type_input":"","ques":"Cho tia Ot l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOy, $\\widehat{xOy}$ v\u00e0 $\\widehat{yOz}$ l\u00e0 hai g\u00f3c ph\u1ee5 nhau. Bi\u1ebft $\\widehat{xOt}$ = $30^o$. V\u1eady $\\widehat{tOy}$ = _input_$^o$, $\\widehat{yOz}$ = _input_$^o$","hint":"","explain":"<span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai13/lv3/img\/H624_K107.png' \/><\/center>Ta c\u00f3: Tia Ot l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a $\\widehat{xOy}$ <br\/>Suy ra $\\widehat{xOt}$ = $\\widehat{tOy}$ = $\\dfrac{1}{2}$ $\\widehat{xOy}$ = $30^o$<br\/>L\u1ea1i c\u00f3: $\\widehat{xOt}$ = $\\dfrac{1}{2}$ $\\widehat{xOy}$<br\/>Do \u0111\u00f3: $\\widehat{xOy}$ = 2. $\\widehat{xOt}$ = 2. $30^o$ = $60^o$<br\/> $\\widehat{xOy}$ v\u00e0 $\\widehat{yOz}$ l\u00e0 hai g\u00f3c ph\u1ee5 nhau<br\/>Do \u0111\u00f3 $\\widehat{xOy}$ + $\\widehat{yOz}$ = $90^o$<br\/>Suy ra $\\widehat{yOz}$ = $90^o$ - $\\widehat{xOy}$ = $90^o$ - $60^o$ = $30^o$<br\/>V\u1eady c\u00e1c s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u1ea7n l\u01b0\u1ee3t t\u1eeb tr\u00e1i qua ph\u1ea3i l\u00e0: <span class='basic_pink'> 30, 30<\/span><\/span> <br\/><\/span> "}]}],"id_ques":2194},{"time":14,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["42"],["84"]]],"list":[{"point":10,"width":60,"type_input":"","ques":"Cho tia Ot l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOy. Bi\u1ebft $\\widehat{xOt}$ = $42^o$. V\u1eady $\\widehat{tOy}$ = _input_$^o$, $\\widehat{xOy}$ = _input_$^o$","hint":"","explain":"<span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai13/lv3/img\/H624_K108.png' \/><\/center>Ta c\u00f3: Tia Ot l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a $\\widehat{xOy}$ <br\/>Suy ra $\\widehat{xOt}$ = $\\widehat{tOy}$ = $\\dfrac{1}{2}$ $\\widehat{xOy}$ = $42^o$<br\/>L\u1ea1i c\u00f3: $\\widehat{xOt}$ = $\\dfrac{1}{2}$ $\\widehat{xOy}$<br\/>Do \u0111\u00f3: $\\widehat{xOy}$ = 2. $\\widehat{xOt}$ = 2. $42^o$ = $84^o$<br\/>V\u1eady c\u00e1c s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u1ea7n l\u01b0\u1ee3t t\u1eeb tr\u00e1i qua ph\u1ea3i l\u00e0: <span class='basic_pink'> 42, 84<\/span><\/span> <br\/> "}]}],"id_ques":2195},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":" Cho hai tia Ox, Oy c\u00f9ng n\u1eb1m tr\u00ean n\u1eeda m\u1eb7t ph\u1eb3ng c\u00f3 b\u1edd ch\u1ee9a tia Ot. Bi\u1ebft $\\widehat{tOy}$ = $80^o$, $\\widehat{xOy}$ = $30^o$ v\u00e0 tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Ot. G\u1ecdi On l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOy, Om l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c tOy. S\u1ed1 \u0111o c\u1ee7a g\u00f3c mOn l\u00e0:","select":["A. $40^o$","B. $70^o$","C. $60^o$","D. $55^o$"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai13/lv3/img\/H624_K111.png' \/><\/center> Ta c\u00f3: Tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Ot<br\/>Do \u0111\u00f3: $\\widehat{tOy}$ + $\\widehat{xOy}$ = $\\widehat{xOt}$ <br\/>Thay $\\widehat{tOy}$ = $80^o$, $\\widehat{xOy}$ = $30^o$ ta \u0111\u01b0\u1ee3c: <br\/>$\\widehat{xOt}$ = $80^o$ + $30^o$ = $110^o$<br\/>+ Om l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c tOy<br\/>Do \u0111\u00f3: $\\widehat{tOm}$ = $\\widehat{mOy}$ = $\\dfrac{1}{2}$ $\\widehat{tOy}$ = $\\dfrac{1}{2}$.$80^o$ = $40^o$<br\/>+ Tia On l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOy<br\/>Do \u0111\u00f3: $\\widehat{yOn}$ = $\\widehat{xOn}$ = $\\dfrac{1}{2}$ $\\widehat{xOy}$ = $\\dfrac{1}{2}$.$30^o$ = $15^o$<br\/>+ $\\widehat{xOn}$ < $\\widehat{xOt}$ ( v\u00ec $15^o$ < $110^o$) n\u00ean tia On n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Ot<br\/>Suy ra: $\\widehat{xOn}$ + $\\widehat{nOt}$ = $\\widehat{xOt}$<br\/>Thay $\\widehat{xOn}$ = $15^o$, $\\widehat{xOt}$ = $110^o$ ta \u0111\u01b0\u1ee3c: <br\/>$15^o$ + $\\widehat{nOt}$ = $110^o$<br\/>$\\widehat{nOt}$ = $110^o$ - $15^o$ = $95^o$<br\/>+ $\\widehat{tOm}$ < $\\widehat{tOn}$ ( v\u00ec $40^o$ < $95^o$) n\u00ean tia Om n\u1eb1m gi\u1eefa hai tia Ot v\u00e0 On<br\/>Suy ra: $\\widehat{tOm}$ + $\\widehat{mOn}$ = $\\widehat{tOn}$<br\/>Thay $\\widehat{tOm}$ = $40^o$, $\\widehat{tOn}$ = $95^o$ ta \u0111\u01b0\u1ee3c:<br\/>$40^o$ + $\\widehat{mOn}$ = $95^o$<br\/>$\\widehat{mOn}$ = $95^o$ - $40^o$ = $55^o$<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: <span class='basic_pink'>D. $55^o$<\/span><\/span> <br\/><\/span><\/span><span class='basic_left'><span class='basic_green'>Nh\u1eadn x\u00e9t:<\/span><br\/>Oy l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOz khi:<br\/>+ Tia Oy l\u00e0 tia n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<br\/>+ $\\widehat{xOy}$ = $\\widehat{yOz}$ = $\\dfrac{1}{2}$$\\widehat{xOz}$<\/span>","column":2}]}],"id_ques":2196},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":" Cho hai $\\widehat{xOy}$ v\u00e0 $\\widehat{yOz}$ k\u1ec1 b\u00f9. Bi\u1ebft $\\widehat{xOy}$ = $100^o$. G\u1ecdi Om l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c yOz. S\u1ed1 \u0111o c\u1ee7a g\u00f3c xOm l\u00e0:","select":["A. $80^o$","B. $90^o$","C. $40^o$","D. $140^o$"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai13/lv3/img\/H624_K115.png' \/><\/center> Ta c\u00f3: $\\widehat{xOy}$ v\u00e0 $\\widehat{yOz}$ k\u1ec1 b\u00f9<br\/>Do \u0111\u00f3: $\\widehat{xOy}$ + $\\widehat{yOz}$ = $\\widehat{xOz}$ = $180^o$<br\/>Thay $\\widehat{xOy}$ = $100^o$ ta \u0111\u01b0\u1ee3c: <br\/>$100^o$ + $\\widehat{yOz}$ = $180^o$<br\/>Suy ra $\\widehat{yOz}$ = $180^o$ - $100^o$ = $80^o$<br\/>+ Om l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c yOz<br\/>Do \u0111\u00f3: $\\widehat{yOm}$ = $\\widehat{mOz}$ = $\\dfrac{1}{2}$ $\\widehat{yOz}$ = $\\frac{1}{2}$.$80^o$ = $40^o$<br\/>+ $\\widehat{mOz}$ < $\\widehat{zOx}$ ( v\u00ec $40^o$ < $180^o$) n\u00ean tia Om n\u1eb1m gi\u1eefa hai tia Oz v\u00e0 Ox<br\/>Suy ra: $\\widehat{xOm}$ + $\\widehat{mOz}$ = $\\widehat{xOz}$<br\/>Thay $\\widehat{zOm}$ = $40^o$, $\\widehat{xOz}$ = $180^o$ ta \u0111\u01b0\u1ee3c:<br\/>$40^o$ + $\\widehat{xOm}$ = $180^o$<br\/>$\\widehat{xOm}$ = $180^o$ - $40^o$ = $140^o$<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: <span class='basic_pink'>D. $140^o$<\/span><\/span> <br\/><\/span><\/span><span class='basic_left'><span class='basic_green'>Nh\u1eadn x\u00e9t:<\/span><br\/>Oy l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOz khi:<br\/>+ Tia Oy l\u00e0 tia n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<br\/>+ $\\widehat{xOy}$ = $\\widehat{yOz}$ <\/span>","column":2}]}],"id_ques":2197},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":" Cho hai $\\widehat{xOy}$ v\u00e0 $\\widehat{yOz}$ k\u1ec1 b\u00f9. Bi\u1ebft $\\widehat{xOy}$ = $100^o$. G\u1ecdi On l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOy, Om l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c yOz. S\u1ed1 \u0111o c\u1ee7a g\u00f3c mOn l\u00e0:","select":["A. $80^o$","B. $90^o$","C. $40^o$","D. $100^o$"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai13/lv3/img\/H624_K113.png' \/><\/center> Ta c\u00f3: $\\widehat{xOy}$ v\u00e0 $\\widehat{yOz}$ k\u1ec1 b\u00f9<br\/>Do \u0111\u00f3: $\\widehat{xOy}$ + $\\widehat{yOz}$ = $\\widehat{xOz}$ = $180^o$<br\/>Thay $\\widehat{xOy}$ = $100^o$ ta \u0111\u01b0\u1ee3c: <br\/>$100^o$ + $\\widehat{yOz}$ = $180^o$<br\/>Suy ra $\\widehat{yOz}$ = $180^o$ - $100^o$ = $80^o$<br\/>+ Om l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c yOz<br\/>Do \u0111\u00f3: $\\widehat{yOm}$ = $\\widehat{mOz}$ = $\\frac{1}{2}$ $\\widehat{yOz}$ = $\\dfrac{1}{2}$.$80^o$ = $40^o$<br\/>+ Tia On l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOy<br\/>Do \u0111\u00f3: $\\widehat{yOn}$ = $\\widehat{xOn}$ = $\\dfrac{1}{2}$ $\\widehat{xOy}$ = $\\dfrac{1}{2}$.$100^o$ = $50^o$<br\/>+ $\\widehat{xOn}$ < $\\widehat{xOz}$ ( v\u00ec $50^o$ < $180^o$) n\u00ean tia On n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<br\/>Suy ra: $\\widehat{xOn}$ + $\\widehat{nOz}$ = $\\widehat{xOz}$<br\/>Thay $\\widehat{xOn}$ = $50^o$, $\\widehat{xOz}$ = $180^o$ ta \u0111\u01b0\u1ee3c: <br\/>$50^o$ + $\\widehat{nOz}$ = $180^o$<br\/>$\\widehat{nOz}$ = $180^o$ - $50^o$ = $130^o$<br\/>+ $\\widehat{zOm}$ < $\\widehat{zOn}$ ( v\u00ec $40^o$ < $130^o$) n\u00ean tia Om n\u1eb1m gi\u1eefa hai tia Oz v\u00e0 On<br\/>Suy ra: $\\widehat{zOm}$ + $\\widehat{mOn}$ = $\\widehat{zOn}$<br\/>Thay $\\widehat{zOm}$ = $40^o$, $\\widehat{zOn}$ = $130^o$ ta \u0111\u01b0\u1ee3c:<br\/>$40^o$ + $\\widehat{mOn}$ = $130^o$<br\/>$\\widehat{mOn}$ = $130^o$ - $40^o$ = $90^o$<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: <span class='basic_pink'>B. $90^o$<\/span><\/span> <br\/><\/span><\/span><span class='basic_left'><span class='basic_green'>Nh\u1eadn x\u00e9t:<\/span><br\/>Oy l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOz khi:<br\/>+ Tia Oy l\u00e0 tia n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<br\/>+ $\\widehat{xOy}$ = $\\widehat{yOz}$ <\/span>","column":2}]}],"id_ques":2198},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":" Cho hai $\\widehat{xOy}$ v\u00e0 $\\widehat{yOz}$ k\u1ec1 b\u00f9. Bi\u1ebft $\\widehat{xOy}$ = $80^o$. G\u1ecdi Om l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOy. S\u1ed1 \u0111o c\u1ee7a g\u00f3c mOz l\u00e0:","select":["A. $80^o$","B. $75^o$","C. $95^o$","D. $140^o$"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai13/lv3/img\/H624_K118.png' \/><\/center> Ta c\u00f3: $\\widehat{xOy}$ v\u00e0 $\\widehat{yOz}$ k\u1ec1 b\u00f9<br\/>Do \u0111\u00f3: $\\widehat{xOy}$ + $\\widehat{yOz}$ = $\\widehat{xOz}$ = $180^o$<br\/>Thay $\\widehat{xOy}$ = $80^o$ ta \u0111\u01b0\u1ee3c: <br\/>$80^o$ + $\\widehat{yOz}$ = $180^o$<br\/>Suy ra $\\widehat{yOz}$ = $180^o$ - $80^o$ = $100^o$<br\/>+ Om l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOy<br\/>Do \u0111\u00f3: $\\widehat{xOm}$ = $\\widehat{mOy}$ = $\\dfrac{1}{2}$ $\\widehat{xOy}$ = $\\dfrac{1}{2}$.$80^o$ = $40^o$<br\/>+ $\\widehat{xOm}$ < $\\widehat{xOz}$ ( v\u00ec $40^o$ < $180^o$) n\u00ean tia Om n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<br\/>Suy ra: $\\widehat{xOm}$ + $\\widehat{mOz}$ = $\\widehat{xOz}$<br\/>Thay $\\widehat{xOm}$ = $40^o$, $\\widehat{xOz}$ = $180^o$ ta \u0111\u01b0\u1ee3c:<br\/>$40^o$ + $\\widehat{mOz}$ = $180^o$<br\/>$\\widehat{mOz}$ = $180^o$ - $40^o$ = $140^o$<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: <span class='basic_pink'>D. $140^o$<\/span><\/span> <br\/><\/span><\/span><span class='basic_left'><span class='basic_green'>Nh\u1eadn x\u00e9t:<\/span><br\/>Oy l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOz khi:<br\/>+ Tia Oy l\u00e0 tia n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<br\/>+ $\\widehat{xOy}$ = $\\widehat{yOz}$ <\/span>","column":2}]}],"id_ques":2199},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":" Cho $\\widehat{xOy}$ = $60^o$. Bi\u1ebft tia Ot l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a $\\widehat{xOy}$. T\u00ednh $\\widehat{tOy}$","select":["A. $30^o$","B. $40^o$","C. $50^o$","D. $60^o$"],"hint":"","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai13/lv3/img\/H624_K119.png' \/><\/center>Tia Ot l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a $\\widehat{xOy}$ <br\/>Suy ra $\\widehat{xOt}$ = $\\widehat{tOy}$ = $\\dfrac{1}{2}$ $\\widehat{xOy}$ = $\\dfrac{1}{2}$. $60^o$ = $30^o$<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n : <span class='basic_pink'>A. $30^o$<\/span><\/span> <br\/>","column":2}]}],"id_ques":2200}],"lesson":{"save":0,"level":3}}