{"segment":[{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" C\u1ea5u t\u1ea1o ph\u00e2n t\u1eed axetilen g\u1ed3m ","select":["A. hai li\u00ean k\u1ebft \u0111\u01a1n v\u00e0 m\u1ed9t li\u00ean k\u1ebft ba","B. hai li\u00ean k\u1ebft \u0111\u01a1n v\u00e0 m\u1ed9t li\u00ean k\u1ebft \u0111\u00f4i.","C. m\u1ed9t li\u00ean k\u1ebft ba v\u00e0 m\u1ed9t li\u00ean k\u1ebft \u0111\u00f4i","D. hai li\u00ean k\u1ebft \u0111\u00f4i v\u00e0 m\u1ed9t li\u00ean k\u1ebft ba."],"hint":"","explain":"<span class='basic_left'>$H-C\\equiv C-H$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2391},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Axetilen c\u00f3 t\u00ednh ch\u1ea5t v\u1eadt l\u00fd ","select":["A. l\u00e0 ch\u1ea5t kh\u00ed kh\u00f4ng m\u00e0u, kh\u00f4ng m\u00f9i, \u00edt tan trong n\u01b0\u1edbc, n\u1eb7ng h\u01a1n kh\u00f4ng kh\u00ed.","B. l\u00e0 ch\u1ea5t kh\u00ed kh\u00f4ng m\u00e0u, kh\u00f4ng m\u00f9i, \u00edt tan trong n\u01b0\u1edbc, nh\u1eb9 h\u01a1n kh\u00f4ng kh\u00ed.","C. l\u00e0 ch\u1ea5t kh\u00ed kh\u00f4ng m\u00e0u, kh\u00f4ng m\u00f9i, tan trong n\u01b0\u1edbc, nh\u1eb9 h\u01a1n kh\u00f4ng kh\u00ed ","D. l\u00e0 ch\u1ea5t kh\u00ed kh\u00f4ng m\u00e0u, m\u00f9i h\u1eafc, \u00edt tan trong n\u01b0\u1edbc, n\u1eb7ng h\u01a1n kh\u00f4ng kh\u00ed."],"hint":"","explain":"<span class='basic_left'>Axetilen l\u00e0 ch\u1ea5t kh\u00ed kh\u00f4ng m\u00e0u, kh\u00f4ng m\u00f9i, \u00edt tan trong n\u01b0\u1edbc, nh\u1eb9 h\u01a1n kh\u00f4ng kh\u00ed<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":1}]}],"id_ques":2392},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Ch\u1ea5t c\u00f3 li\u00ean k\u1ebft ba trong ph\u00e2n t\u1eed l\u00e0 ","select":["A. metan","B. etilen.","C. axetilen.","D. benzen"],"hint":"","explain":"<span class='basic_left'>$H-C\\equiv C-H$: Axetilen<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2393},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" D\u1eabn kh\u00ed axetilen qua dung d\u1ecbch n\u01b0\u1edbc brom (m\u00e0u da cam) hi\u1ec7n t\u01b0\u1ee3ng x\u1ea3y ra l\u00e0:","select":["A. Dung d\u1ecbch n\u01b0\u1edbc brom \u0111\u1eadm m\u00e0u h\u01a1n","B. Dung d\u1ecbch n\u01b0\u1edbc brom chuy\u1ec3n m\u00e0u \u0111\u1ecf","C. Dung d\u1ecbch n\u01b0\u1edbc brom nh\u1ea1t m\u00e0u h\u01a1n ","D. Kh\u00f4ng c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng g\u00ec."],"hint":"","explain":"<span class='basic_left'>Axetilen c\u00f3 ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch brom n\u00ean l\u00e0m nh\u1ea1t m\u00e0u c\u1ee7a dung d\u1ecbch brom<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2394},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" \u0110\u00e8n x\u00ec oxi \u2013 axetilen c\u00f3 th\u1ec3 h\u00e0n, c\u1eaft kim lo\u1ea1i. Gi\u1ea3i th\u00edch n\u00e0o sau \u0111\u00e2y \u0111\u00fang","select":["A. Khi axetilen ch\u00e1y trong oxi nhi\u1ec7t \u0111\u1ed9 c\u00f3 th\u1ec3 l\u00ean t\u1edbi $3000^0C$ khi \u0111\u00f3 h\u1ea7u h\u1ebft c\u00e1c kim lo\u1ea1i \u0111\u1ec1u b\u1ecb n\u00f3ng ch\u1ea3y","B. C\u00f3 th\u1ec3 \u0111i\u1ec1u ch\u1ec9nh th\u00e0nh ph\u1ea7n c\u1ee7a h\u1ed7n h\u1ee3p kh\u00ed theo \u00fd mu\u1ed1n","C. Khi c\u1eaft kim lo\u1ea1i, ng\u01b0\u1eddi ta \u0111i\u1ec1u ch\u1ec9nh sao cho oxi d\u01b0 \u0111\u1ec3 \u0111\u1ed1t ch\u00e1y ph\u1ea7n kim lo\u1ea1i n\u00f3ng ch\u1ea3y","D. C\u1ea3 A, B, C \u0111\u1ec1u \u0111\u00fang"],"hint":"","explain":"<span class='basic_left'>Khi axetilen ch\u00e1y trong oxi nhi\u1ec7t \u0111\u1ed9 c\u00f3 th\u1ec3 l\u00ean t\u1edbi $3000^0C$ khi \u0111\u00f3 h\u1ea7u h\u1ebft c\u00e1c kim lo\u1ea1i \u0111\u1ec1u b\u1ecb n\u00f3ng ch\u1ea3y n\u00ean h\u1ed7n h\u1ee3p \u0111\u00e8n x\u00ec oxi \u2013 axetilen \u0111\u01b0\u1ee3c \u1ee9ng d\u1ee5ng \u0111\u1ec3 h\u00e0n, c\u1eaft kim lo\u1ea1i<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2395},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"\u0110\u1ec3 \u0111i\u1ec1u ch\u1ebf axetilen trong ph\u00f2ng th\u00ed nghi\u1ec7m v\u00e0 trong c\u00f4ng nghi\u1ec7p ta l\u00e0 nh\u01b0 sau:","select":["A. Cho C t\u00e1c d\u1ee5ng v\u1edbi kh\u00ed hi\u0111ro","B. Cho canxi cacbua t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc","C. Cho v\u00f4i s\u1ed1ng t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc","D. Cho C \u0111i qua h\u01a1i n\u01b0\u1edbc."],"hint":"","explain":"<span class='basic_left'>$Ca{{C}_{2}}+2{{H}_{2}}O\\to Ca{{(OH)}_{2}}+{{C}_{2}}{{H}_{2}}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":1}]}],"id_ques":2396},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"C\u00e1ch thu kh\u00ed axetilen trong ph\u00f2ng th\u00ed nghi\u1ec7m l\u00e0:","select":["A. \u0110\u1ea9y kh\u00f4ng kh\u00ed (\u00fap ng\u1eeda b\u00ecnh)","B. \u0110\u1ea9y kh\u00f4ng kh\u00ed (\u00fap ng\u01b0\u1ee3c b\u00ecnh)","C. \u0110\u1ea9y n\u01b0\u1edbc","D. \u0110\u1ea9y kh\u00ed oxi"],"hint":"","explain":"<span class='basic_left'>Axetilen kh\u00f4ng tan trong n\u01b0\u1edbc v\u00e0 nh\u1eb9 h\u01a1n kh\u00f4ng kh\u00ed n\u00ean \u0111\u01b0\u1ee3c thu b\u1eb1ng c\u00e1ch \u0111\u1ea9y n\u01b0\u1edbc<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2397},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" C\u00f4ng th\u1ee9c c\u1ee7a axetilen l\u00e0:","select":["A. $C_2H_4$","B. $C_2H_6$","C. $C_2H_2$","D. $C_3H_2$"],"hint":"","explain":"<span class='basic_left'>Axetilen : $C_2H_2$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2398},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Kh\u00ed axetilen KH\u00d4NG c\u00f3 t\u00ednh ch\u1ea5t h\u00f3a h\u1ecdc n\u00e0o sau \u0111\u00e2y ","select":["A. Ph\u1ea3n \u1ee9ng c\u1ed9ng v\u1edbi dung d\u1ecbch brom.","B. Ph\u1ea3n \u1ee9ng ch\u00e1y v\u1edbi oxi","C. Ph\u1ea3n \u1ee9ng c\u1ed9ng v\u1edbi hi\u0111ro ","D. Ph\u1ea3n \u1ee9ng th\u1ebf v\u1edbi clo ngo\u00e0i \u00e1nh s\u00e1ng"],"hint":"","explain":"<span class='basic_left'>Kh\u00ed axetilen kh\u00f4ng c\u00f3 ph\u1ea3n \u1ee9ng th\u1ebf clo nh\u01b0 metan.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2399},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Li\u00ean k\u1ebft $C\\equiv C$ trong ph\u00e2n t\u1eed axetilen c\u00f3 \u0111\u1eb7c \u0111i\u1ec3m ","select":["A. m\u1ed9t li\u00ean k\u1ebft k\u00e9m b\u1ec1n d\u1ec5 \u0111\u1ee9t ra trong c\u00e1c ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc.","B. hai li\u00ean k\u1ebft k\u00e9m b\u1ec1n nh\u01b0ng ch\u1ec9 c\u00f3 m\u1ed9t li\u00ean k\u1ebft b\u1ecb \u0111\u1ee9t ra trong ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc.","C. hai li\u00ean k\u1ebft k\u00e9m b\u1ec1n d\u1ec5 \u0111\u1ee9t l\u1ea7n l\u01b0\u1ee3t trong c\u00e1c ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc.","D. ba li\u00ean k\u1ebft k\u00e9m b\u1ec1n d\u1ec5 \u0111\u1ee9t l\u1ea7n l\u01b0\u1ee3t trong c\u00e1c ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc."],"hint":"","explain":"<span class='basic_left'>Li\u00ean k\u1ebft 3 l\u00e0 c\u00f3 2 li\u00ean k\u1ebft k\u00e9m b\u1ec1n d\u1ec5 b\u1ecb \u0111\u1ee9t g\u00e3y trong c\u00e1c ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2400},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Metan, axetilen, etilen \u0111\u1ec1u c\u00f3 ph\u1ea3n \u1ee9ng:","select":["A. Ph\u1ea3n \u1ee9ng th\u1ebf","B. Ph\u1ea3n \u1ee9ng c\u1ed9ng ","C. Ph\u1ea3n \u1ee9ng ch\u00e1y","D. Ph\u1ea3n \u1ee9ng tr\u00f9ng h\u1ee3p"],"hint":"","explain":"<span class='basic_left'>C\u00e1c hi\u0111rocacbon \u0111\u1ec1u c\u00f3 ph\u1ea3n \u1ee9ng ch\u00e1y.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2401},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" \u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 5,6 l\u00edt kh\u00ed $C_2H_2$ trong b\u00ecnh ch\u1ee9a kh\u00ed oxi d\u01b0. Th\u1ec3 t\u00edch kh\u00ed $CO_2$ thu \u0111\u01b0\u1ee3c (trong c\u00f9ng \u0111i\u1ec1u ki\u1ec7n nhi\u1ec7t \u0111\u1ed9 v\u00e0 \u00e1p su\u1ea5t) l\u00e0 ","select":["A. 11,2 l\u00edt","B. 16,8 l\u00edt.","C. 22,4 l\u00edt ","D. 33,6 l\u00edt"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& 2{{C}_{2}}{{H}_{2}}+5{{O}_{2}}\\xrightarrow{{{t}^{0}}}4C{{O}_{2}}+2{{H}_{2}}O \\\\ & {{n}_{C{{O}_{2}}}}=2{{n}_{{{C}_{2}}{{H}_{2}}}}=2.0,25=0,5\\,mol \\\\ & {{V}_{{{O}_{2}}}}=11,2\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2402},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" D\u00e3y c\u00e1c ch\u1ea5t n\u00e0o sau \u0111\u00e2y \u0111\u1ec1u l\u00e0m m\u1ea5t m\u00e0u dung d\u1ecbch brom","select":["A. $CH_4; C_6H_6$","B. $C_2H_4; C_2H_6$.","C. $CH_4; C_2H_4$","D. $C_2H_4; C_2H_2$."],"hint":"","explain":"<span class='basic_left'>$C_2H_4; C_2H_2$.: \u0111\u1ec1u l\u00e0m m\u1ea5t m\u00e0u n\u01b0\u1edbc brom.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2403},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Cho 0,1 mol kh\u00ed axetilen qua dung d\u1ecbch n\u01b0\u1edbc brom d\u01b0. Kh\u1ed1i l\u01b0\u1ee3ng n\u01b0\u1edbc brom tham gia ph\u1ea3n \u1ee9ng l\u00e0:","select":["A. 8 gam","B. 16 gam","C. 24 gam","D. 32 gam"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & H-C\\equiv C-H+2B{{r}_{2}}\\to B{{r}_{2}}CH-CHB{{r}_{2}} \\\\ & {{n}_{B{{r}_{2}}}}=2{{n}_{{{C}_{2}}{{H}_{2}}}}=0,2\\,mol \\\\ & {{m}_{B{{r}_{2}}}}=32\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2404},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Cho 0,56 l\u00edt (\u0111ktc) h\u1ed7n h\u1ee3p kh\u00ed metan v\u00e0 axetilen t\u00e1c d\u1ee5ng v\u1edbi dung d\u1ecbch brom d\u01b0, l\u01b0\u1ee3ng brom \u0111\u00e3 tham gia ph\u1ea3n \u1ee9ng l\u00e0 5,6 gam. Th\u00e0nh ph\u1ea7n ph\u1ea7n tr\u0103m v\u1ec1 th\u1ec3 t\u00edch c\u1ee7a m\u1ed7i kh\u00ed trong h\u1ed7n h\u1ee3p ban \u0111\u1ea7u l\u1ea7n l\u01b0\u1ee3t l\u00e0:","select":["A. 20%; 80%","B. 40% ; 60%.","C. 30%; 70%.","D. 60%; 40%."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{hh}}=0,025\\,mol \\\\ & {{C}_{2}}{{H}_{2}}+2B{{r}_{2}}\\to {{C}_{2}}{{H}_{2}}B{{r}_{4}} \\\\ & {{n}_{{{C}_{2}}{{H}_{2}}}}=\\dfrac{1}{2}{{n}_{B{{r}_{2}}}}=\\dfrac{1}{2}.0,035=0,0175 \\\\ & \\%{{V}_{{{C}_{2}}{{H}_{2}}}}=\\dfrac{0,0175}{0,025}.100\\%=70\\% \\\\ & \\%{{V}_{C{{H}_{4}}}}=30\\% \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2405},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Khi \u0111\u1ed1t kh\u00ed axetilen, s\u1ed1 mol $CO_2$ v\u00e0 $H_2O$ \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh theo t\u1ec9 l\u1ec7 l\u00e0","select":["A. 2 : 1","B. 1 : 2","C. 1 : 3","D. 1 : 1"],"hint":"","explain":"<span class='basic_left'>$2{{C}_{2}}{{H}_{2}}+5{{O}_{2}}\\xrightarrow{{{t}^{0}}}4C{{O}_{2}}+2{{H}_{2}}O$ .${{n}_{C{{O}_{2}}}}:{{n}_{{{H}_{2}}O}}=4:2=2:1$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2406},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 1 mol kh\u00ed axetilen th\u00ec c\u1ea7n bao nhi\u00eau l\u00edt kh\u00f4ng kh\u00ed (c\u00e1c kh\u00ed \u0111o \u1edf \u0111ktc, bi\u1ebft r\u1eb1ng oxi chi\u1ebfm 20% th\u1ec3 t\u00edch kh\u00f4ng kh\u00ed) ","select":["A. 300 l\u00edt","B. 280 l\u00edt","C. 240 l\u00edt","D. 120 l\u00edt"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & 2{{C}_{2}}{{H}_{2}}+5{{O}_{2}}\\xrightarrow{{{t}^{0}}}4C{{O}_{2}}+2{{H}_{2}}O \\\\ & {{n}_{{{O}_{2}}}}=\\dfrac{5}{2}{{n}_{{{C}_{2}}{{H}_{2}}}}=\\dfrac{5}{2}.1=2,5\\,mol \\\\ & {{V}_{{{O}_{2}}}}=56\\,l\\Rightarrow {{V}_{KK}}=\\dfrac{56.100\\%}{20\\%}=280\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2407},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Trong \u0111i\u1ec1u ki\u1ec7n th\u00edch h\u1ee3p 1 mol kh\u00ed axetilen t\u00e1c d\u1ee5ng ho\u00e0n to\u00e0n v\u1edbi 2 mol kh\u00ed hi\u0111ro, thu \u0111\u01b0\u1ee3c ch\u1ea5t kh\u00ed l\u00e0 ","select":["A. $C_2H_4$","B. $C_2H_6$.","C. $C_3H_4$,","D. $C_3H_6$."],"hint":"","explain":"<span class='basic_left'>${{C}_{2}}{{H}_{2}}+2{{H}_{2}}\\xrightarrow{{{t}^{o}},xt}{{C}_{2}}{{H}_{6}}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2408},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" M\u1ed9t h\u1ed7n h\u1ee3p kh\u00ed g\u1ed3m metan v\u00e0 axetilen c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng 3 gam, \u1edf \u0111i\u1ec1u ki\u1ec7n ti\u00eau chu\u1ea9n chi\u1ebfm th\u1ec3 t\u00edch l\u00e0 3,36 l\u00edt. Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a metan v\u00e0 axetilen trong h\u1ed7n h\u1ee3p l\u1ea7n l\u01b0\u1ee3t l\u00e0","select":["A. 1,44 gam; 1,56 gam","B. 1,56 gam; 1,44 gam","C. 1,5 gam; 1,5 gam ","D. 2 gam; 1 gam"],"hint":"","explain":"<span class='basic_left'>H\u01b0\u1edbng d\u1eabn :G\u1ecdi x, y l\u1ea7n l\u01b0\u1ee3t l\u00e0 s\u1ed1 mol c\u1ee7a metan v\u00e0 axetilen trong h\u1ed7n h\u1ee3p ban \u0111\u1ea7u. <br\/>$\\left. \\begin{aligned} & {{m}_{hh}}=3g\\Rightarrow 16x+26y=3 \\\\ & {{n}_{hh}}=0,015\\,mol\\Rightarrow x+y=0,015 \\\\ \\end{aligned} \\right\\}\\Rightarrow x=0,09;y=0,06\\Rightarrow {{m}_{C{{H}_{4}}}}=1,44\\,g;\\,{{m}_{{{C}_{2}}{{H}_{2}}}}=1,56\\,g$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2409},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Cho 0,56 l\u00edt h\u1ed7n h\u1ee3p kh\u00ed etilen v\u00e0 axetilen t\u00e1c d\u1ee5ng h\u1ebft v\u1edbi dung d\u1ecbch brom d\u01b0, kh\u1ed1i l\u01b0\u1ee3ng brom tham gia ph\u1ea3n \u1ee9ng l\u00e0 5,6 gam. Th\u1ec3 t\u00edch kh\u00ed axetilen trong h\u1ed7n h\u1ee3p ban \u0111\u1ea7u l\u00e0","select":["A. 0,112 l\u00edt","B. 0,168 l\u00edt ","C. 0,224 l\u00edt","D. 0,336 l\u00edt"],"hint":"","explain":"<span class='basic_left'>G\u1ecdi x, y l\u1ea7n l\u01b0\u1ee3t l\u00e0 s\u1ed1 mol c\u1ee7a etilen v\u00e0 axetilen trong h\u1ed7n h\u1ee3p <br\/> $\\begin{aligned}& {{n}_{hh}}=0,025\\,mol\\Rightarrow x+y=0,025\\,\\,\\,(1) \\\\ & {{C}_{2}}{{H}_{4}}+B{{r}_{2}}\\to {{C}_{2}}{{H}_{4}}B{{r}_{2}} \\\\ & x\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,x \\\\ & {{C}_{2}}{{H}_{2}}+2B{{r}_{2}}\\to {{C}_{2}}{{H}_{2}}B{{r}_{4}} \\\\ & y\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,2y \\\\ & {{n}_{B{{r}_{2}}}}=0,035\\,\\Rightarrow x+2y=0,035\\,\\,\\,\\,\\,(2) \\\\ \\end{aligned}$ <br\/> Gi\u1ea3i (1) v\u00e0 (2) ta c\u00f3 x = 0,015; y = 0,01 <br\/>${{V}_{{{C}_{2}}{{H}_{2}}}}=0,01.22,4=0,224\\,l$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2410}],"lesson":{"save":0,"level":2}}