Bài tập trung bình bài Bài 30: Silic. Công nghiệp silicat

Home Lớp 9 Hóa học 9 Bài 30: Silic. Công nghiệp silicat Bài tập luyện

{"segment":[{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Trong t\u1ef1 nhi\u00ean silic t\u1ed3n t\u1ea1i d\u01b0\u1edbi d\u1ea1ng","select":["A. \u0110\u01a1n ch\u1ea5t ","B. H\u1ed7n h\u1ee3p","C. H\u1ee3p ch\u1ea5t ","D. V\u1eeba \u0111\u01a1n ch\u1ea5t v\u1eeba h\u1ee3p ch\u1ea5t"],"hint":"","explain":"Silic ch\u1ec9 t\u1ed3n t\u1ea1i \u1edf d\u1ea1ng h\u1ee3p ch\u1ea5t<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2271},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Silic \u0111ioxit thu\u1ed9c lo\u1ea1i oxit n\u00e0o:","select":["A. Oxit baz\u01a1 ","B. Oxit trung t\u00ednh ","C. Oxit axit","D. Oxit l\u01b0\u1ee1ng t\u00ednh."],"hint":"","explain":"Silic \u0111ioxit l\u00e0 oxit axit<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2272},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Th\u00e0nh ph\u1ea7n ch\u00ednh c\u1ee7a xi m\u0103ng l\u00e0:","select":["A. $CaCO_3, Al_2O_3$ ","B. \u0110\u1ea5t s\u00e9t, \u0111\u00e1 v\u00f4i, c\u00e1t","C. $CaO, Al_2O_3$ ","D. $CaSiO_3, Ca(AlO_2)_2$"],"hint":"","explain":"$CaSiO_3, Ca(AlO_2)_2$ l\u00e0 th\u00e0nh ph\u1ea7n ch\u00ednh c\u1ee7a xi m\u0103ng<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2273},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Silic l\u00e0 nguy\u00ean t\u1ed1 ph\u1ed5 bi\u1ebfn \u0111\u1ee9ng th\u1ee9 m\u1ea5y trong t\u1ef1 nhi\u00ean","select":["A. 1 ","B. 2","C. 3 ","D. 4"],"hint":"","explain":"Si l\u00e0 nguy\u00ean t\u1ed1 ph\u1ed5 bi\u1ebfn \u0111\u1ee9ng th\u1ee9 2 sau oxi trong t\u1ef1 nhi\u00ean<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2274},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Si l\u00e0 ch\u1ea5t r\u1eafn m\u00e0u:","select":["A. Tr\u1eafng","B. V\u00e0ng","C. X\u00e1m ","D. \u0110en"],"hint":"","explain":"Si l\u00e0 ch\u1ea5t r\u1eafn m\u00e0u x\u00e1m<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2275},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" \u1ede nhi\u1ec7t \u0111\u1ed9 cao silic ph\u1ea3n \u1ee9ng v\u1edbi oxi \u0111\u1ec3 t\u1ea1o th\u00e0nh","select":["A. $SiO$","B. $Si_2O$","C. $SiO_2$ ","D. $SiO_3$"],"hint":"","explain":"$Si+{{O}_{2}}\\xrightarrow{{{t}^{0}}}Si{{O}_{2}}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2276},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Silic l\u00e0 ch\u1ea5t ","select":["A. D\u1eabn \u0111i\u1ec7n t\u1ed1t ","B. D\u1eabn \u0111i\u1ec7n k\u00e9m ","C. Kh\u00f4ng d\u1eabn \u0111i\u1ec7n","D. D\u1eabn \u0111i\u1ec7n t\u1ed1t h\u01a1n s\u1eaft"],"hint":"","explain":"Si l\u00e0 ch\u1ea5t d\u1eabn \u0111i\u1ec7n k\u00e9m<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2277},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Ch\u1ecdn kh\u1eb3ng \u0111\u1ecbnh sai ","select":["A. Silic l\u00e0 phi kim, c\u00f3 v\u1ebb s\u00e1ng c\u1ee7a kim lo\u1ea1i","B. Silic l\u00e0 phi kim ho\u1ea1t \u0111\u1ed9ng y\u1ebfu h\u01a1n cacbon","C. Silic \u0111ioxit ph\u1ea3n \u1ee9ng \u0111\u01b0\u1ee3c v\u1edbi n\u01b0\u1edbc t\u1ea1o th\u00e0nh axit","D. Tinh th\u1ec3 silic tinh khi\u1ebft l\u00e0 ch\u1ea5t b\u00e1n d\u1eabn"],"hint":"","explain":"Silic \u0111ioxit kh\u00f4ng ph\u1ea3n \u1ee9ng v\u1edbi n\u01b0\u1edbc t\u1ea1o th\u00e0nh axit.<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2278},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Nguy\u00ean li\u1ec7u s\u1ea3n xu\u1ea5t \u0111\u1ed3 g\u1ed1m, s\u1ee9 l\u00e0:","select":["A. \u0110\u1ea5t s\u00e9t, th\u1ea1ch anh, fenpat","B. C\u00e1t, \u0111\u1ea5t s\u00e9t ","C. \u0110\u1ea5t s\u00e9t, c\u00e1t, fenpat ","D. Fenpat, c\u00e1t."],"hint":"","explain":" \u0110\u1ea5t s\u00e9t, th\u1ea1ch anh, fenpat l\u00e0 nguy\u00ean li\u1ec7u s\u1ea3n xu\u1ea5t g\u1ed1m, s\u1ee9.<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2279},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Th\u00e0nh ph\u1ea7n ch\u00ednh c\u1ee7a th\u1ee7y tinh l\u00e0 mu\u1ed1i silicat c\u1ee7a","select":["A. K v\u00e0 Na ","B. K v\u00e0 Ca","C. Na v\u00e0 Ca","D. Ca v\u00e0 Si"],"hint":"","explain":"Th\u1ee7y tinh c\u00f3 th\u00e0nh ph\u1ea7n ch\u00ednh l\u00e0 natri silicat v\u00e0 canxi silicat.<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2280},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" T\u00ednh kh\u1ed1i l\u01b0\u1ee3ng $CaO$ c\u1ea7n thi\u1ebft \u0111\u1ec3 ph\u1ea3n \u1ee9ng v\u1eeba \u0111\u1ee7 v\u1edbi 6 gam $SiO_2$","select":["A. 2,8 gam","B. 5 gam","C. 5,6 gam ","D. 6,5 gam"],"hint":"","explain":"$\\begin{aligned} & CaO+Si{{O}_{2}}\\xrightarrow{{{t}^{0}}}CaSi{{O}_{3}} \\\\ & {{n}_{CaO}}={{n}_{Si{{O}_{2}}}}=0,1\\,mol \\\\ & {{m}_{CaO}}=5,6\\,gam \\\\ \\end{aligned}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2281},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Nguy\u00ean li\u1ec7u ch\u00ednh \u0111\u1ec3 s\u1ea3n xu\u1ea5t xi m\u0103ng l\u00e0:","select":["A. \u0110\u1ea5t s\u00e9t, \u0111\u00e1 v\u00f4i, c\u00e1t ","B. C\u00e1t, th\u1ea1ch anh, \u0111\u00e1 v\u00f4i ","C. \u0110\u1ea5t s\u00e9t, \u0111\u00e1 v\u00f4i, th\u1ea1ch anh","D. C\u00e1t, s\u00f4\u0111a, \u0111\u1ea5t s\u00e9t"],"hint":"","explain":"\u0110\u1ea5t s\u00e9t, \u0111\u00e1 v\u00f4i, c\u00e1t l\u00e0 nguy\u00ean li\u1ec7u ch\u00ednh \u0111\u1ec3 s\u1ea3n xu\u1ea5t xi m\u0103ng<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2282},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Nguy\u00ean li\u1ec7u s\u1ea3n xu\u1ea5t th\u1ee7y tinh l\u00e0","select":["A. C\u00e1t tr\u1eafng, \u0111\u1ea5t s\u00e9t, s\u00f4\u0111a","B. \u0110\u00e1 v\u00f4i, \u0111\u1ea5t s\u00e9t, c\u00e1t","C. C\u00e1t tr\u1eafng, \u0111\u00e1 v\u00f4i, s\u00f4\u0111a ","D. Fenpat, \u0111\u00e1 v\u00f4i, c\u00e1t."],"hint":"","explain":"C\u00e1t tr\u1eafng, \u0111\u00e1 v\u00f4i, s\u00f4\u0111a l\u00e0 nguy\u00ean li\u1ec7u s\u1ea3n xu\u1ea5t th\u1ee7y tinh<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2283},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" 8 gam dung d\u1ecbch NaOH c\u00f3 th\u1ec3 h\u00f2a tan t\u1ed1i \u0111a bao nhi\u00eau gam silic \u0111ioxit ","select":["A. 6 gam","B. 12 gam","C. 15 gam ","D. 18 gam "],"hint":"","explain":"$\\begin{aligned} & Si{{O}_{2}}+2NaOH\\to N{{a}_{2}}Si{{O}_{3}}+{{H}_{2}}O \\\\ & {{n}_{Si{{O}_{2}}}}=\\dfrac{1}{2}{{n}_{NaOH}}=0,1\\,mol \\\\ & {{m}_{Si{{O}_{2}}}}=6\\,gam \\\\ \\end{aligned}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2284},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Qu\u00e1 tr\u00ecnh s\u1ea3n xu\u1ea5t th\u1ee7y tinh c\u1ea7n 1 l\u01b0\u1ee3ng caxi oxit l\u00e0 112 kg \u0111\u01b0\u1ee3c ph\u00e2n h\u1ee7y t\u1eeb \u0111\u00e1 v\u00f4i. Th\u1ec3 t\u00edch kh\u00ed cacbonic tho\u00e1t ra l\u00e0","select":["A. 22,4 $m^3$ ","B. 33,6 $m^3$","C. 44,8 $m^3$ ","D. 67,2 $m^3$"],"hint":"","explain":"$\\begin{aligned} & CaC{{O}_{3}}\\xrightarrow{{{t}^{0}}}CaO+C{{O}_{2}} \\\\ & {{n}_{C{{O}_{2}}}}={{n}_{CaO}}=\\dfrac{{{112.10}^{3}}}{56}={{2.10}^{3}}\\,mol \\\\ & {{V}_{C{{O}_{2}}}}=44,{{8.10}^{3}}\\,l=44,8\\,{{m}^{3}}\\, \\\\ \\end{aligned}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2285},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Qu\u00e1 tr\u00ecnh s\u1ea3n xu\u1ea5t th\u1ee7y tinh c\u1ea7n 1 l\u01b0\u1ee3ng silic \u0111ioxit l\u00e0 1,2 t\u1ea5n. C\u1ea7n l\u1ea5y l\u01b0\u1ee3ng c\u00e1t th\u1ea1ch anh l\u00e0 bao nhi\u00eau t\u1ea5n bi\u1ebft th\u1ea1ch anh ch\u1ee9a 62,5% silic \u0111ioxit ","select":["A. 1,6 t\u1ea5n","B. 1,85 t\u1ea5n ","C. 1,92 t\u1ea5n ","D. 2,05 t\u1ea5n"],"hint":"","explain":"${{m}_{\\text{c\u00e1t}}}=\\dfrac{1,2.100\\%}{62,5\\%}=1,92\\,\\text{t\u1ea5n}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2286},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" \u0110\u1ec3 thu \u0111\u01b0\u1ee3c 11,6 gam canxi silicat c\u1ea7n m\u1ed9t l\u01b0\u1ee3ng c\u00e1t l\u00e0 bao nhi\u00eau. Bi\u1ebft th\u00e0nh ph\u1ea7n ch\u00ednh c\u1ee7a c\u00e1t l\u00e0 silic \u0111ioxit chi\u1ebfm 47,5% kh\u1ed1i l\u01b0\u1ee3ng. ","select":["A. 6 gam","B. 7,8 gam","C. 10,7 gam","D. 12,6 gam"],"hint":"","explain":"$\\begin{aligned} & CaO+Si{{O}_{2}}\\xrightarrow{{{t}^{0}}}CaSi{{O}_{3}} \\\\ & {{n}_{CaSi{{O}_{3}}}}={{n}_{Si{{O}_{2}}}}=0,1\\,mol \\\\ & {{m}_{Si{{O}_{2}}}}=6\\,gam \\\\ & {{m}_{\\text{c\u00e1t}}}=\\dfrac{6.100\\%}{47,5\\%}\\approx 12,6\\,gam \\\\ \\end{aligned}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2287},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110un n\u00f3ng m gam Silic trong oxi d\u01b0 thu \u0111\u01b0\u1ee3c 53,4 gam silic \u0111ioxit. Gi\u00e1 tr\u1ecb c\u1ee7a m l\u00e0","select":["A. 18,69 gam ","B. 24,92 gam ","C. 37,38 gam ","D. 12,46 gam"],"hint":"","explain":"$\\begin{aligned} & Si+{{O}_{2}}\\xrightarrow{{{t}^{0}}}Si{{O}_{2}} \\\\ & {{n}_{Si}}={{n}_{Si{{O}_{2}}}}=0,89\\,mol \\\\ & {{m}_{Si}}=24,92\\,gam \\\\ \\end{aligned}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2288},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Qu\u00e1 tr\u00ecnh s\u1ea3n xu\u1ea5t th\u1ee7y tinh c\u1ea7n 1 l\u01b0\u1ee3ng caxi oxit l\u00e0 112 kg. Kh\u1ed1i l\u01b0\u1ee3ng \u0111\u00e1 v\u00f4i c\u1ea7n cho qu\u00e1 tr\u00ecnh s\u1ea3n xu\u1ea5t l\u00e0. Bi\u1ebft hi\u1ec7u su\u1ea5t nhi\u1ec7t ph\u00e2n \u0111\u00e1 v\u00f4i \u0111\u1ea1t 75%","select":["A. 200 kg ","B. 253,5 kg","C. 266,67 kg ","D. 297,33 kg"],"hint":"","explain":"$\\begin{aligned}& CaC{{O}_{3}}\\xrightarrow{{{t}^{0}}}CaO+C{{O}_{2}} \\\\ & 100kg\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,56kg \\\\ & x\\,kg\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,112\\,kg \\\\ & x=\\dfrac{112.100}{56}=200\\,kg \\\\ & H=75\\%\\Rightarrow {{m}_{\\text{\u0111\u00e1 v\u00f4i}}}=\\dfrac{200.100\\%}{75\\%}\\approx 266,67\\,kg \\\\ \\end{aligned}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2289},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" M\u1ed9t lo\u1ea1i thu\u1ef7 tinh kh\u00f3 n\u00f3ng ch\u1ea3y ch\u1ee9a 18,43% $K_2O$, 10,98% $CaO$ , 70,59% $SiO_2$ v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng. Th\u00e0nh ph\u1ea7n c\u1ee7a thu\u1ef7 tinh n\u00e0y bi\u1ec3u di\u1ec5n d\u01b0\u1edbi d\u1ea1ng c\u00e1c oxit l\u00e0","select":["A. $K_2O.CaO.4SiO_2$ ","B. $K_2O.2CaO.6SiO_2$ ","C. $K_2O.CaO.6SiO_2$ ","D. $K_2O.3CaO.8SiO_2$ "],"hint":"","explain":"Gi\u1ea3 s\u1eed c\u00f3 100 gam th\u1ee7y tinh. <br\/>$\\begin{aligned} & \\Rightarrow {{m}_{{{K}_{2}}O}}=18,43\\,gam;\\,\\,\\,{{m}_{CaO}}=10,98\\,gam;\\,\\,\\,\\,\\,\\,{{m}_{Si{{O}_{2}}}}=70,59\\,gam \\\\ & \\Rightarrow {{n}_{{{K}_{2}}O}}\\approx 0,196\\,mol;\\,\\,\\,{{n}_{CaO}}\\approx 0,196\\,mol;\\,\\,\\,\\,\\,\\,{{n}_{Si{{O}_{2}}}}\\approx 1,1765\\,mol \\\\ & \\Rightarrow {{n}_{{{K}_{2}}O}}:{{n}_{CaO}}:\\,{{n}_{Si{{O}_{2}}}}=0,196\\,mol:0,196\\,mol:1,1765\\,mol \\\\ & \\Rightarrow {{n}_{{{K}_{2}}O}}:{{n}_{CaO}}:\\,{{n}_{Si{{O}_{2}}}}\\approx 1:1:6 \\\\ \\end{aligned}$ <br\/>V\u1eady c\u00f4ng th\u1ee9c c\u1ea7n t\u00ecm l\u00e0: $K_2O.CaO.6SiO_2$<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2290}],"lesson":{"save":0,"level":2}}

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Câu hỏi này theo dạng chọn đáp án đúng, sau khi đọc xong câu hỏi, bạn bấm vào một trong số các đáp án mà chương trình đưa ra bên dưới, sau đó bấm vào nút gửi để kiểm tra đáp án và sẵn sàng chuyển sang câu hỏi kế tiếp

Trả lời đúng trong khoảng thời gian quy định bạn sẽ được + số điểm như sau:
Trong khoảng 1 phút đầu tiên	+ 5 điểm
Trong khoảng 1 phút -> 2 phút	+ 4 điểm
Trong khoảng 2 phút -> 3 phút	+ 3 điểm
Trong khoảng 3 phút -> 4 phút	+ 2 điểm
Trong khoảng 4 phút -> 5 phút	+ 1 điểm

Quá 5 phút: không được cộng điểm

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