Bài tập trung bình bài Bài 2: Một số Oxit quan trọng

Home Lớp 9 Hóa học 9 Bài 2: Một số Oxit quan trọng Bài tập luyện

{"segment":[{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Oxit khi t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc t\u1ea1o ra dung d\u1ecbch axit sunfuric l\u00e0:","select":["A. $CO_2$ ","B. $SO_3$","C. $SO_2$ ","D. $K_2O$"],"hint":"","explain":"oxit axit t\u01b0\u01a1ng \u1ee9ng t\u1ea1o ra $H_2SO_4$ l\u00e0 $SO_3$ theo ph\u1ea3n \u1ee9ng: <br\/> $S{{O}_{3}}+{{H}_{2}}O\\to {{H}_{2}}S{{O}_{4}}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1771},{"time":24,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Oxit \u0111\u01b0\u1ee3c d\u00f9ng l\u00e0m ch\u1ea5t h\u00fat \u1ea9m (ch\u1ea5t l\u00e0m kh\u00f4) trong ph\u00f2ng th\u00ed nghi\u1ec7m l\u00e0:","select":["A. $CuO$","B. $ZnO$","C. $PbO$ ","D. $CaO$"],"hint":"","explain":" $CaO$ \u0111\u01b0\u1ee3c d\u00f9ng l\u00e0m ch\u1ea5t h\u00fat \u1ea9m <br\/> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":1772},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" D\u1eabn h\u1ed7n h\u1ee3p kh\u00ed g\u1ed3m $CO_2 , CO , SO_2$ l\u1ed9i qua dung d\u1ecbch n\u01b0\u1edbc v\u00f4i trong (d\u01b0), kh\u00ed tho\u00e1t ra l\u00e0 :","select":["A. $CO$","B. $CO_2$ ","C. $SO_2$ ","D. $CO_2$ v\u00e0 $SO_2$"],"hint":"","explain":" $CO_2$ v\u00e0 $SO_2$ l\u00e0 c\u00e1c oxit axit n\u00ean c\u00f3 ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch baz\u01a1. C\u00f2n $CO$ l\u00e0 axit trung t\u00ednh kh\u00f4ng ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch baz\u01a1 v\u00e0 tho\u00e1t ra ngo\u00e0i.<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":1773},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" S\u1ea3n ph\u1ea9m c\u1ee7a ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ee7y Canxicacbonat b\u1edfi nhi\u1ec7t l\u00e0:","select":["A. $CaO$ v\u00e0 $CO$","B. $CaO$ v\u00e0 $CO_2$","C. $CaO$ v\u00e0 $SO_2$","D. $CaO$ v\u00e0 $P_2O_5$"],"hint":"","explain":"Canxicacbonat $(CaCO_3)$ b\u1ecb ph\u00e2n h\u1ee7y b\u1edfi nhi\u1ec7t theo ph\u1ea3n \u1ee9ng: <br\/> $CaC{{O}_{3}}\\xrightarrow{{{t}^{0}}}CaO+C{{O}_{2}}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1774},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Oxit n\u00e0o sau \u0111\u00e2y khi t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc t\u1ea1o ra dung d\u1ecbch c\u00f3 pH > 7 ","select":["A. $CO_2$ ","B. $SO_2$","C. $CaO$","D. $P_2O_5$"],"hint":"","explain":"pH > 7 l\u00e0 m\u00f4i tr\u01b0\u1eddng baz\u01a1 n\u00ean oxit t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc ph\u1ea3i l\u00e0 oxit c\u1ee7a kim lo\u1ea1i ki\u1ec1m, ki\u1ec1m th\u1ed5. Ch\u1ec9 c\u00f3 \u0111\u00e1p \u00e1n C th\u1ecfa m\u00e3n <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":1775},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" C\u1eb7p ch\u1ea5t t\u00e1c d\u1ee5ng v\u1edbi nhau s\u1ebd t\u1ea1o ra kh\u00ed l\u01b0u hu\u1ef3nh \u0111ioxit l\u00e0:","select":["A. $CaCO_3$ v\u00e0 $HCl$","B. $Na_2SO_3$ v\u00e0 $H_2SO_4$","C. $CuCl_2$ v\u00e0 $KOH$","D. $K_2CO_3$ v\u00e0 $HNO_3$"],"hint":"","explain":"Mu\u1ed1i sunfit t\u00e1c d\u1ee5ng v\u1edbi axit s\u1ebd thu \u0111\u01b0\u1ee3c kh\u00ed l\u01b0u hu\u1ef3nh \u0111ioxit ($SO_2$). Ch\u1ec9 c\u00f3 B th\u1ecfa m\u00e3n: <br\/> $N{{a}_{2}}S{{O}_{3}}+{{H}_{2}}S{{O}_{4}}\\to N{{a}_{2}}S{{O}_{4}}+S{{O}_{2}}+{{H}_{2}}O$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1776},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Ch\u1ea5t n\u00e0o sau \u0111\u00e2y g\u00f3p ph\u1ea7n nhi\u1ec1u nh\u1ea5t v\u00e0o s\u1ef1 h\u00ecnh th\u00e0nh m\u01b0a axit ?","select":["A. $CO_2$","B. $SO_2$","C. $N_2$","D. $O_3$"],"hint":"","explain":" $SO_2$ l\u00e0 nguy\u00ean nh\u00e2n ch\u00ednh g\u00e2y n\u00ean m\u01b0a axit <br\/> $CO_2$ l\u00e0 nguy\u00ean nh\u00e2n ch\u00ednh g\u00e2y n\u00ean hi\u1ec7u \u1ee9ng nh\u00e0 k\u00ednh<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1777},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Ch\u1ea5t kh\u00ed n\u1eb7ng g\u1ea5p 2,2069 l\u1ea7n kh\u00f4ng kh\u00ed l\u00e0:","select":["A. $CO_2$","B. $SO_2$","C. $SO_3$","D. $NO$"],"hint":"","explain":"Gi\u1ea3 s\u1eed kh\u00ed c\u1ea7n t\u00ecm l\u00e0 X <br\/> $\\begin{aligned}& {{d}_{x\/kk}}=2,2069 \\\\ & =>\\,{{M}_{X}}=2,2069.29=64\\,(S{{O}_{2}}) \\\\ \\end{aligned}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1778},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Ch\u1ea5t l\u00e0m qu\u1ef3 t\u00edm \u1ea9m chuy\u1ec3n sang m\u00e0u \u0111\u1ecf l\u00e0:","select":["A. $MgO$","B. $CaO$","C. $SO_2$","D. $K_2O$"],"hint":"","explain":"Ch\u1ea5t l\u00e0m qu\u1ef3 chuy\u1ec3n sang m\u00e0u \u0111\u1ecf l\u00e0 oxit axit. Ch\u1ec9 c\u00f3 $SO_2$ th\u1ecfa m\u00e3n.<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":1779},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" V\u00f4i s\u1ed1ng c\u00f3 c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc l\u00e0 :","select":["A. $Ca$","B. $Ca(OH)_2$","C. $CaCO_3$","D. $CaO$"],"hint":"","explain":" $CaO$: v\u00f4i s\u1ed1ng <br\/> $CaCO_3$: \u0111\u00e1 v\u00f4i <br\/> $Ca(OH)_2$: dung d\u1ecbch n\u01b0\u1edbc v\u00f4i trong.<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":1780},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" C\u1eb7p ch\u1ea5t t\u00e1c d\u1ee5ng v\u1edbi nhau t\u1ea1o ra mu\u1ed1i natrisunfit l\u00e0:","select":["A. $NaOH$ v\u00e0 $CO_2$","B. $Na_2O$ v\u00e0 $SO_3$","C. $NaOH$ v\u00e0 $SO_3$ ","D. $NaOH$ v\u00e0 $SO_2$"],"hint":"","explain":"Mu\u1ed1i natrisunfit ($Na_2SO_3$). Ch\u1ec9 c\u00f3 \u0111\u00e1o \u00e1n D th\u1ecfa m\u00e3n: <br\/> $2NaOH+S{{O}_{2}}\\to N{{a}_{2}}S{{O}_{3}}+{{H}_{2}}O$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":1781},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Trong h\u01a1i th\u1edf, Ch\u1ea5t kh\u00ed l\u00e0m \u0111\u1ee5c n\u01b0\u1edbc v\u00f4i trong l\u00e0:","select":["A. $CO_2$","B. $SO_2$","C. $SO_3$","D. $NO_2$"],"hint":"","explain":"C\u1ea3 kh\u00ed $CO_2$ v\u00e0 $SO_2$ \u0111\u1ec1u l\u00e0m \u0111\u1ee5c n\u01b0\u1edbc v\u00f4i trong. Trong h\u01a1i th\u1edf ng\u01b0\u1eddi c\u00f3 ch\u1ee9a kh\u00ed $CO_2$.<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":1782},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" H\u00f2a tan h\u1ebft 5,6 gam CaO v\u00e0o dung d\u1ecbch HCl 14,6% . Kh\u1ed1i l\u01b0\u1ee3ng dung d\u1ecbch HCl \u0111\u00e3 d\u00f9ng l\u00e0 :","select":["A. 50 gam","B. 40 gam","C. 60 gam ","D. 73 gam"],"hint":"","explain":"$\\begin{aligned}& {{n}_{CaO}}=\\dfrac{5,6}{56}=0,1\\,mol \\\\ & CaO+2HCl\\to CaC{{l}_{2}}+{{H}_{2}}O \\\\ & {{n}_{HCl}}=2{{n}_{CaO}}=0,2\\,mol \\\\ & {{m}_{HCl}}=0,2.36,5=7,3 \\\\ & {{m}_{\\text{dd}\\,HCl}}=\\dfrac{7,3.100%}{14,6%}=50\\,gam \\\\ \\end{aligned}$<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":1783},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Oxit c\u1ee7a m\u1ed9t nguy\u00ean t\u1ed1 h\u00f3a tr\u1ecb (II) ch\u1ee9a 28,57% oxi v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng . Nguy\u00ean t\u1ed1 \u0111\u00f3 l\u00e0:","select":["A. Ca ","B. Mg","C. Fe ","D. Cu"],"hint":"","explain":"Gi\u1ea3 s\u1eed c\u00f4ng th\u1ee9c oxit l\u00e0 AO <br\/>$\\begin{aligned}& \\%{{m}_{O}}=\\dfrac{16}{A+16}.100\\%=28,57 \\\\ & =>\\,A=40\\,(Ca) \\\\ \\end{aligned}$<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":1784},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" \u0110\u1ec3 thu \u0111\u01b0\u1ee3c 5,6 t\u1ea5n v\u00f4i s\u1ed1ng v\u1edbi hi\u1ec7u su\u1ea5t ph\u1ea3n \u1ee9ng \u0111\u1ea1t 95% th\u00ec l\u01b0\u1ee3ng $CaCO_3$ c\u1ea7n d\u00f9ng l\u00e0 :","select":["A. 9 t\u1ea5n ","B. 9,5 t\u1ea5n","C. 10 t\u1ea5n ","D. 10,5 t\u1ea5n"],"hint":"","explain":"$\\begin{aligned}& CaC{{O}_{3}}\\xrightarrow{{{t}^{0}}}CaO+C{{O}_{2}} \\\\ & 100\\text{ t\u1ea5n}\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\text{56 t\u1ea5n} \\\\ & \\text{x t\u1ea5n}\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\text{5,6 t\u1ea5n} \\\\ & \\text{x = }\\dfrac{5,6.100}{56}=10\\text{ t\u1ea5n} \\\\ & H=95\\%\\,\\,\\,=>\\,{{m}_{CaC{{O}_{3}}}}=\\dfrac{10.100\\%}{95\\%}=10,5\\text{ t\u1ea5n} \\\\ \\end{aligned}$<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":1785},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110\u1ec3 lo\u1ea1i b\u1ecf kh\u00ed CO2 c\u00f3 l\u1eabn trong h\u1ed7n h\u1ee3p ($O_2 , CO_2$) , ng\u01b0\u1eddi ta cho h\u1ed7n h\u1ee3p \u0111i qua dung d\u1ecbch ch\u1ee9a:","select":["A. $HCl$","B. $Ca(OH)_2$","C. $Na_2SO_4$","D. $NaCl$"],"hint":"","explain":"\u0110\u1ec3 lo\u1ea1i b\u1ecf kh\u00ed $CO_2$ c\u00f3 l\u1eabn trong h\u1ed7n h\u1ee3p ($O_2, CO_2$) ta ph\u1ea3i cho h\u1ed7n h\u1ee3p t\u00e1c d\u1ee5ng v\u1edbi ch\u1ea5t m\u00e0 $CO_2$ c\u00f3 ph\u1ea3n \u1ee9ng c\u00f2n $O_2$ kh\u00f4ng ph\u1ea3n \u1ee9ng. Ch\u1ec9 c\u00f3 $Ca(OH)_2$ th\u1ecfa m\u00e3n <br\/> $Ca{{(OH)}_{2}}+C{{O}_{2}}\\to CaC{{O}_{3}}\\downarrow +{{H}_{2}}O$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1786},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Cho 2,24 l\u00edt $CO_2$ (\u0111ktc) t\u00e1c d\u1ee5ng v\u1edbi dung d\u1ecbch $Ba(OH)_2$ d\u01b0. Kh\u1ed1i l\u01b0\u1ee3ng ch\u1ea5t k\u1ebft t\u1ee7a thu \u0111\u01b0\u1ee3c l\u00e0 :","select":["A. 19,7 g ","B. 19,5 g","C. 19,3 g","D. 19 g"],"hint":"","explain":"$\\begin{aligned}& {{n}_{C{{O}_{2}}}}=\\dfrac{2,24}{22,4}=0,1\\,mol \\\\ & Ba{{(OH)}_{2}}+C{{O}_{2}}\\to BaC{{O}_{3}}\\downarrow +{{H}_{2}}O \\\\ & {{n}_{\\downarrow }}={{n}_{C{{O}_{2}}}}=0,1\\,mol \\\\ & {{m}_{\\downarrow }}=0,1.197=19,7\\,gam \\\\ \\end{aligned}$<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":1787},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" H\u00f2a tan 12,6 gam natrisunfit v\u00e0o dung d\u1ecbch axit clohidric d\u01b0. Th\u1ec3 t\u00edch kh\u00ed $SO_2$ thu \u0111\u01b0\u1ee3c \u1edf \u0111ktc l\u00e0:","select":["A. 4,48 l\u00edt ","B. 3,36 l\u00edt","C. 2,24 l\u00edt ","D. 1,12 l\u00edt"],"hint":"","explain":"$\\begin{aligned}& {{n}_{N{{a}_{2}}S{{O}_{3}}}}=\\dfrac{12,6}{126}=0,1\\,mol \\\\ & N{{a}_{2}}S{{O}_{3}}+2HCl\\to 2NaCl+S{{O}_{2}}+{{H}_{2}}O \\\\ & {{n}_{S{{O}_{2}}}}={{n}_{N{{a}_{2}}S{{O}_{3}}}}=0,1\\,mol \\\\ & {{V}_{S{{O}_{2}}}}=0,1.22,4=2,24\\,\\,l \\\\ \\end{aligned}$<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":1788},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" H\u00f2a tan h\u1ebft 11,7g h\u1ed7n h\u1ee3p g\u1ed3m $CaO$ v\u00e0 $CaCO_3$ c\u1ea7n 100 ml dung d\u1ecbch $HCl$ 3M . Kh\u1ed1i l\u01b0\u1ee3ng mu\u1ed1i thu \u0111\u01b0\u1ee3c l\u00e0 :","select":["A. 16,65 g ","B. 15,56 g","C. 166,5 g","D. 155,6 g"],"hint":"","explain":"G\u1ecdi x, y l\u1ea7n l\u01b0\u1ee3t l\u00e0 s\u1ed1 mol c\u1ee7a CaO, CaCO3 <br\/>Kh\u1ed1i l\u01b0\u1ee3ng h\u1ed7n h\u1ee3p b\u1eb1ng 11,7 gam n\u00ean ta c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh:<br\/>56x + 100y = 11,7 (1)<br\/>$\\begin{aligned}& {{n}_{HCl}}=0,1.3=0,3\\,mol \\\\ & CaO+2HCl\\to CaC{{l}_{2}}+{{H}_{2}}O \\\\ & x\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,2x \\\\ & CaC{{O}_{3}}+2HCl\\to CaC{{l}_{2}}+C{{O}_{2}}+{{H}_{2}}O \\\\ & y\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,2y \\\\ & {{n}_{HCl}}=0,3\\,mol \\\\ & =>\\,2x+2y=0,3(2) \\\\ \\end{aligned}$<br\/>T\u1eeb (1) v\u00e0 (2) gi\u1ea3i ra x = y =0,075 mol<br\/>${{m}_{CaC{{l}_{2}}}}=0,075.2.111=16,65\\,gam$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":1789},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Cho 20 gam h\u1ed7n h\u1ee3p X g\u1ed3m $CuO$ v\u00e0 $Fe_2O_3$ t\u00e1c d\u1ee5ng v\u1eeba \u0111\u1ee7 v\u1edbi 0,2 l\u00edt dung d\u1ecbch $HCl$ c\u00f3 n\u1ed3ng \u0111\u1ed9 3,5M. Th\u00e0nh ph\u1ea7n ph\u1ea7n tr\u0103m theo kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a $CuO$ v\u00e0 $Fe_2O_3$ trong h\u1ed7n h\u1ee3p X l\u1ea7n l\u01b0\u1ee3t l\u00e0 :","select":["A. 25% v\u00e0 75%","B. 20% v\u00e0 80%","C. 22% v\u00e0 78% ","D. 30% v\u00e0 70%"],"hint":"","explain":"G\u1ecdi x, y l\u1ea7n l\u01b0\u1ee3t l\u00e0 s\u1ed1 mol c\u1ee7a CuO, Fe2O3<br\/>Kh\u1ed1i l\u01b0\u1ee3ng h\u1ed7n h\u1ee3p b\u1eb1ng 20 gam n\u00ean ta c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh:<br\/>80x + 160y = 20 (1)<br\/>$\\begin{aligned}& {{n}_{HCl}}=0,2.3,5=0,7mol \\\\ & CuO+2HCl\\to CuC{{l}_{2}}+{{H}_{2}}O \\\\ & x\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,2x \\\\ & F{{e}_{2}}{{O}_{3}}+6HCl\\to 2FeC{{l}_{3}}+3{{H}_{2}}O \\\\ & y\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,6y \\\\ & {{n}_{HCl}}=0,7\\,mol \\\\ & =>\\,2x+6y=0,7(2) \\\\ \\end{aligned}$<br\/>T\u1eeb (1) v\u00e0 (2) gi\u1ea3i ra x = 0,05 mol ; y =0,1 mol<br\/>$\\begin{aligned}& \\%{{m}_{CuO}}=\\dfrac{0,05.80}{20}=20\\% \\\\ & \\%{{m}_{F{{e}_{2}}{{O}_{3}}}}=100\\%-20\\%=80\\% \\\\ \\end{aligned}$<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1790}],"lesson":{"save":0,"level":2}}

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Câu hỏi này theo dạng chọn đáp án đúng, sau khi đọc xong câu hỏi, bạn bấm vào một trong số các đáp án mà chương trình đưa ra bên dưới, sau đó bấm vào nút gửi để kiểm tra đáp án và sẵn sàng chuyển sang câu hỏi kế tiếp

Trả lời đúng trong khoảng thời gian quy định bạn sẽ được + số điểm như sau:
Trong khoảng 1 phút đầu tiên	+ 5 điểm
Trong khoảng 1 phút -> 2 phút	+ 4 điểm
Trong khoảng 2 phút -> 3 phút	+ 3 điểm
Trong khoảng 3 phút -> 4 phút	+ 2 điểm
Trong khoảng 4 phút -> 5 phút	+ 1 điểm

Quá 5 phút: không được cộng điểm

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