{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"N\u01b0\u1edbc l\u00e0 h\u1ee3p ch\u1ea5t \u0111\u01b0\u1ee3c c\u1ea5u t\u1ea1o t\u1eeb c\u00e1c nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc n\u00e0o ? ","select":["A. Hi\u0111ro v\u00e0 nit\u01a1 ","B. Hi\u0111ro v\u00e0 oxi ","C. Nit\u01a1 v\u00e0 oxi","D. Photpho v\u00e0 oxi "],"hint":"","explain":"<span class='basic_left'>N\u01b0\u1edbc l\u00e0 h\u1ee3p ch\u1ea5t t\u1ea1o b\u1edfi hai nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc l\u00e0 Hi\u0111ro v\u00e0 Oxi<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2320},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"\u0110\u1ec3 t\u1ea1o th\u00e0nh n\u01b0\u1edbc, hi\u0111ro v\u00e0 oxi \u0111\u00e3 h\u00f3a h\u1ee3p v\u1edbi nhau theo t\u1ef7 l\u1ec7 th\u1ec3 t\u00edch l\u00e0 bao nhi\u00eau ? ","select":["A. 2 ph\u1ea7n kh\u00ed hi\u0111ro v\u00e0 3 ph\u1ea7n kh\u00ed oxi ","B. 1 ph\u1ea7n kh\u00ed hi\u0111ro v\u00e0 2 ph\u1ea7n kh\u00ed oxi ","C. 2 ph\u1ea7n kh\u00ed hi\u0111ro v\u00e0 1 ph\u1ea7n kh\u00ed oxi ","D. 3 ph\u1ea7n kh\u00ed hi\u0111ro v\u00e0 2 ph\u1ea7n kh\u00ed oxi "],"hint":"","explain":"<span class='basic_left'>Hi\u0111ro v\u00e0 oxi \u0111\u00e3 h\u00f3a h\u1ee3p v\u1edbi nhau theo t\u1ef7 l\u1ec7 th\u1ec3 t\u00edch l\u00e0 2 ph\u1ea7n kh\u00ed hi\u0111ro v\u00e0 1 ph\u1ea7n kh\u00ed oxi <br\/>PTHH : $2{{H}_{2}}+{{O}_{2}}\\xrightarrow{{{t}^{o}}}2{{H}_{2}}O$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2321},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"T\u00ednh ch\u1ea5t n\u00e0o sau \u0111\u00e2y th\u1ec3 hi\u1ec7n \u0111\u00fang t\u00ednh ch\u1ea5t v\u1eadt l\u00ed c\u1ee7a n\u01b0\u1edbc ? ","select":["A. N\u01b0\u1edbc l\u00e0 ch\u1ea5t l\u1ecfng kh\u00f4ng m\u00e0u, kh\u00f4ng m\u00f9i, kh\u00f4ng v\u1ecb ","B. T\u1ea1i \u00e1p su\u1ea5t kh\u00ed quy\u1ec3n l\u00e0 760 mm Hg, n\u01b0\u1edbc s\u00f4i \u1edf ${{100}^{o}}C$ ","C. N\u01b0\u1edbc c\u00f3 th\u1ec3 h\u00f2a tan \u0111\u01b0\u1ee3c nhi\u1ec1u ch\u1ea5t r\u1eafn, l\u1ecfng, kh\u00ed ","D. T\u1ea5t c\u1ea3 c\u00e1c \u0111\u00e1p \u00e1n tr\u00ean \u0111\u1ec1u \u0111\u00fang "],"hint":"","explain":"<span class='basic_left'>N\u01b0\u1edbc l\u00e0 ch\u1ea5t l\u1ecfng kh\u00f4ng m\u00e0u, kh\u00f4ng m\u00f9i, kh\u00f4ng v\u1ecb, t\u1ea1i \u00e1p su\u1ea5t kh\u00ed quy\u1ec3n l\u00e0 760 mm Hg n\u01b0\u1edbc s\u00f4i \u1edf ${{100}^{o}}C$, n\u01b0\u1edbc h\u00f2a tan \u0111\u01b0\u1ee3c nhi\u1ec1u ch\u1ea5t r\u1eafn, l\u1ecfng, kh\u00ed<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2322},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"D\u00e3y c\u00e1c kim lo\u1ea1i t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc \u1edf nhi\u1ec7t \u0111\u1ed9 th\u01b0\u1eddng l\u00e0 ","select":["A. $Na,K,Ca$ ","B. $Fe,Zn,Ag$ ","C. $Na,Al,Cu$ ","D. $Zn,Pb,Cr$ "],"hint":"","explain":"<span class='basic_left'>N\u01b0\u1edbc t\u00e1c d\u1ee5ng v\u1edbi m\u1ed9t s\u1ed1 kim lo\u1ea1i \u1edf nhi\u1ec7t \u0111\u1ed9 th\u01b0\u1eddng ( nh\u01b0 Na,K,Ca ) t\u1ea1o th\u00e0nh bazo v\u00e0 hi\u0111ro.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2323},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Ph\u1ea7n tr\u0103m kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a nguy\u00ean t\u1ed1 Hi\u0111ro trong n\u01b0\u1edbc l\u00e0 ","select":["A. $88,97\\%$ ","B. $11,11\\%$ ","C. $9,87\\%$ ","D. $12,11\\%$ "],"hint":"","explain":"<span class='basic_left'>Kh\u1ed1i l\u01b0\u1ee3ng mol c\u1ee7a n\u01b0\u1edbc l\u00e0 M = 1.2 + 16 = 18 (g\/mol)<br\/>Trong 1 mol n\u01b0\u1edbc c\u00f3 2 mol nguy\u00ean t\u1eed H v\u00e0 1 mol nguy\u00ean t\u1eed O<br\/>$\\to \\%{{m}_{H}}=\\dfrac{2.100\\%}{18}=11,11\\%$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2324},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Cho c\u00e1c oxit : $CaO,A{{l}_{2}}{{O}_{3,}}{{N}_{2}}{{O}_{5,}}CuO,N{{a}_{2}}O,BaO,{{P}_{2}}{{O}_{5,}}F{{e}_{2}}{{O}_{3,}}{{K}_{2}}O$. S\u1ed1 oxit t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc t\u1ea1o ra dung d\u1ecbch l\u00e0m \u0111\u1ed5i m\u00e0u qu\u1ef3 t\u00edm th\u00e0nh xanh ? ","select":["A. 5 ","B. 6 ","C. 4 ","D. 2 "],"hint":"","explain":"<span class='basic_left'>C\u00f3 4 oxit bazo t\u00e1c d\u1ee5ng \u0111\u01b0\u1ee3c v\u1edbi n\u01b0\u1edbc t\u1ea1o th\u00e0nh dung d\u1ecbch bazo l\u00e0m qu\u1ef3 t\u00edm chuy\u1ec3n sang m\u00e0u xanh l\u00e0 CaO, Na2O, BaO, K2O.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2325},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"C\u00f3 3 ch\u1ea5t g\u1ed3m : $ZnO,{{K}_{2}}O,S{{O}_{3}}$ \u0111\u1ef1ng ri\u00eang bi\u1ec7t trong 3 l\u1ecd b\u1ecb m\u1ea5t nh\u00e3n. \u0110\u1ec3 nh\u1eadn bi\u1ebft c\u00e1c ch\u1ea5t tr\u00ean ta d\u00f9ng thu\u1ed1c th\u1eed l\u00e0 ","select":["A. N\u01b0\u1edbc v\u00e0 phenolphtalein ","B. N\u01b0\u1edbc ","C. Dung d\u1ecbch NaOH ","D. Dung d\u1ecbch HCl "],"hint":"","explain":"<span class='basic_left'>$ZnO$ kh\u00f4ng tan trong n\u01b0\u1edbc, ${{K}_{2}}O$ tan trong n\u01b0\u1edbc t\u1ea1o th\u00e0nh dung d\u1ecbch $KOH$ l\u00e0m dung d\u1ecbch phenolphtalein chuy\u1ec3n th\u00e0nh m\u00e0u h\u1ed3ng, $S{{O}_{3}}$ tan trong n\u01b0\u1edbc t\u1ea1o th\u00e0nh axit ${{H}_{2}}S{{O}_{4}}$ kh\u00f4ng l\u00e0m \u0111\u1ed5i m\u00e0u phenolphtalein. <br\/>$\\begin{aligned} & {{K}_{2}}O+{{H}_{2}}O\\to 2KOH \\\\ & S{{O}_{3}}+{{H}_{2}}O\\to {{H}_{2}}S{{O}_{4}} \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2326},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Cho c\u00e1c oxit : $S{{O}_{2}},C{{O}_{2}},CO,{{P}_{2}}{{O}_{5}},NO,{{N}_{2}}{{O}_{5}},S{{O}_{3}},BaO,CaO,FeO,ZnO$. S\u1ed1 oxit t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc t\u1ea1o ra axit t\u01b0\u01a1ng \u1ee9ng l\u00e0 ","select":["A. 4 ","B. 5 ","C. 8 ","D. 6 "],"hint":"","explain":"<span class='basic_left'>N\u01b0\u1edbc t\u00e1c d\u1ee5ng v\u1edbi m\u1ed9t s\u1ed1 oxit axit nh\u01b0 $S{{O}_{2}},C{{O}_{2}},{{P}_{2}}{{O}_{5}},{{N}_{2}}{{O}_{5}},S{{O}_{3}}$ t\u1ea1o ra axit t\u01b0\u01a1ng \u1ee9ng<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2327},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Trong \u0111\u1eddi s\u1ed1ng v\u00e0 s\u1ea3n xu\u1ea5t n\u01b0\u1edbc \u0111\u00f3ng vai tr\u00f2 g\u00ec ? ","select":["A. H\u00f2a tan nhi\u1ec1u ch\u1ea5t dinh d\u01b0\u1ee1ng c\u1ea7n thi\u1ebft cho c\u01a1 th\u1ec3 s\u1ed1ng ","B. Tham gia v\u00e0o nhi\u1ec1u qu\u00e1 tr\u00ecnh h\u00f3a h\u1ecdc quan tr\u1ecdng trong c\u01a1 th\u1ec3 ng\u01b0\u1eddi v\u00e0 \u0111\u1ed9ng v\u1eadt ","C. N\u01b0\u1edbc ph\u1ee5c v\u1ee5 cho \u0111\u1eddi s\u1ed1ng h\u00e0nh ng\u00e0y c\u1ee7a con ng\u01b0\u1eddi trong sinh ho\u1eb7t, s\u1ea3n xu\u1ea5t n\u00f4ng nghi\u1ec7p, c\u00f4ng nghi\u1ec7p, x\u00e2y d\u1ef1ng... ","D. T\u1ea5t c\u1ea3 c\u00e1c \u0111\u00e1p \u00e1n tr\u00ean \u0111\u1ec1u \u0111\u00fang "],"hint":"","explain":"<span class='basic_left'>N\u01b0\u1edbc h\u00f2a tan nhi\u1ec1u ch\u1ea5t dinh d\u01b0\u1ee1ng c\u1ea7n thi\u1ebft cho c\u01a1 th\u1ec3 s\u1ed1ng, tham gia v\u00e0o nhi\u1ec1u qu\u00e1 tr\u00ecnh h\u00f3a h\u1ecdc quan tr\u1ecdng trong c\u01a1 th\u1ec3 ng\u01b0\u1eddi v\u00e0 \u0111\u1ed9ng v\u1eadt, n\u01b0\u1edbc ph\u1ee5c v\u1ee5 cho \u0111\u1eddi s\u1ed1ng h\u00e0nh ng\u00e0y c\u1ee7a con ng\u01b0\u1eddi trong sinh ho\u1eb7t, s\u1ea3n xu\u1ea5t n\u00f4ng nghi\u1ec7p, c\u00f4ng nghi\u1ec7p, x\u00e2y d\u1ef1ng... <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2328},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Cho n\u1ed5 m\u1ed9t h\u1ed7n h\u1ee3p 1,5 mol kh\u00ed hi\u0111ro v\u00e0 18,48 l\u00edt kh\u00ed oxi \u1edf \u0111ktc. Kh\u1ed1i l\u01b0\u1ee3ng n\u01b0\u1edbc \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh l\u00e0 ","select":["A. 18 gam ","B. 20 gam ","C. 27 gam ","D. 30 gam "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{{{O}_{2}}}}=\\dfrac{18,48}{22,4}=0,825(mol) \\\\ & 2{{H}_{2}}+{{O}_{2}}\\xrightarrow{{{t}^{o}}}2{{H}_{2}}O \\\\ \\end{aligned}$<br\/>T\u1eeb ph\u01b0\u01a1ng tr\u00ecnh l\u1eadp t\u1ef7 s\u1ed1 :<br\/>$\\dfrac{{{n}_{{{H}_{2}}}}}{2}=0,75<\\dfrac{{{n}_{{{O}_{2}}}}}{1}=0,825$<br\/>$\\to$ Oxi d\u01b0, n\u00ean ta t\u00ednh kh\u1ed1i l\u01b0\u1ee3ng n\u01b0\u1edbc theo s\u1ed1 mol hi\u0111ro<br\/>$\\begin{aligned} & {{n}_{{{H}_{2}}O}}={{n}_{{{H}_{2}}}}=1,5(mol) \\\\ & \\to {{m}_{{{H}_{2}}O}}=1,5.18=27(g) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2329},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Cho 6,9 gam Na t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc. Th\u1ec3 t\u00edch kh\u00ed hi\u0111ro thu \u0111\u01b0\u1ee3c l\u00e0 ","select":["A. 3,36 l\u00edt ","B. 4,48 l\u00edt ","C. 1,12 l\u00edt ","D. 6,8 l\u00edt "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{Na}}=\\dfrac{6,9}{23}=0,3(mol) \\\\ & 2Na+2{{H}_{2}}O\\to 2NaOH+{{H}_{2}} \\\\ & \\begin{matrix} 0,3mol & {} & \\to & {} & {} & 0,15mol & {} \\\\\\end{matrix} \\\\ & \\to {{V}_{{{H}_{2}}}}=0,15.22,4=3,36(l) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2330},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Cho 266 kg v\u00f4i s\u1ed1ng (CaO) t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc. Kh\u1ed1i l\u01b0\u1ee3ng $Ca{{(OH)}_{2}}$ thu \u0111\u01b0\u1ee3c theo l\u00fd thuy\u1ebft l\u00e0 ( bi\u1ebft r\u1eb1ng v\u00f4i s\u1ed1ng c\u00f3 $10\\%$ t\u1ea1p ch\u1ea5t kh\u00f4ng t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc ) ","select":["A. 249,75 kg ","B. 316,35 kg ","C. 351,5 kg ","D. 400 kg "],"hint":"","explain":"<span class='basic_left'>Kh\u1ed1i l\u01b0\u1ee3ng v\u00f4i s\u1ed1ng CaO nguy\u00ean ch\u1ea5t l\u00e0 <br\/>${{m}_{CaO}}=\\dfrac{266.(100-10)}{100}=239,4(kg)$<br\/>Ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc :<br\/>$\\begin{aligned} & {{n}_{CaO}}=\\dfrac{239,4}{56}=4,275(kmol) \\\\ & CaO+{{H}_{2}}O\\to Ca{{(OH)}_{2}} \\\\ & \\begin{matrix} 4,275 & \\to & {} & 4,275 & {} & {} & (kmol) \\\\\\end{matrix} \\\\ & \\to {{m}_{Ca{{(OH)}_{2}}}}=4,275.74=316,35(kg) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2331},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Cho 1,86 gam m\u1ed9t oxit c\u1ee7a kim lo\u1ea1i R h\u00f3a tr\u1ecb I t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc. Sau m\u1ed9t th\u1eddi gian thu \u0111\u01b0\u1ee3c 0,06 mol dung d\u1ecbch l\u00e0m \u0111\u1ed5i m\u00e0u qu\u1ef3 t\u00edm th\u00e0nh xanh. C\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a oxit l\u00e0 ","select":["A. ${{K}_{2}}O$ ","B. ${{N}_{2}}O$ ","C. ${{Ca}_{2}}O$ ","D. ${{Na}_{2}}O$ "],"hint":"","explain":"<span class='basic_left'>R h\u00f3a tr\u1ecb I v\u00e0 Oxi h\u00f3a tr\u1ecb II<br\/>Theo quy t\u1eafc h\u00f3a tr\u1ecb ta c\u00f3 oxit d\u1ea1ng : ${{R}_{2}}O$<br\/>Dung d\u1ecbch sau ph\u1ea3n \u1ee9ng l\u00e0m \u0111\u1ed5i m\u00e0u qu\u1ef3 t\u00edm th\u00e0nh xanh<br\/>$\\to$ Dung d\u1ecbch \u0111\u00f3 l\u00e0 baz\u01a1. V\u1eady oxit c\u1ee7a kim lo\u1ea1i R l\u00e0 oxit baz\u01a1<br\/>PTHH : <br\/>$\\begin{aligned} & {{R}_{2}}O+{{H}_{2}}O\\to 2ROH \\\\ & \\begin{matrix} 0,03 & \\leftarrow & {} & 0,06 & {} & {} & (mol) \\\\\\end{matrix} \\\\ & \\to {{M}_{{{R}_{2}}O}}=\\dfrac{1,86}{0,03}=62 \\\\ & \\to 2{{M}_{R}}+{{M}_{O}}=62\\to {{M}_{R}}=23 \\\\ \\end{aligned}$<br\/>V\u1eady R l\u00e0 Natri (Na)<br\/>$\\to$ C\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a oxit l\u00e0 ${{Na}_{2}}O$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2332},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Cho 4,6 gam h\u1ed7n h\u1ee3p kim lo\u1ea1i Ca v\u00e0 Fe t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc, sau m\u1ed9t th\u1eddi gian thu \u0111\u01b0\u1ee3c 0,56 l\u00edt khi hi\u0111ro \u1edf \u0111ktc. Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a Fe l\u00e0 ","select":["A. 1 gam ","B. 2,8 gam ","C. 3,6 gam ","D. 3,2 gam "],"hint":"","explain":"<span class='basic_left'>Fe kh\u00f4ng tan trong n\u01b0\u1edbc, ch\u1ec9 c\u00f3 Ca tan \u0111\u01b0\u1ee3c trong n\u01b0\u1edbc<br\/>$\\begin{aligned} & {{n}_{{{H}_{2}}}}=\\dfrac{0,56}{22,4}=0,025(mol) \\\\ & Ca+2{{H}_{2}}O\\to Ca{{(OH)}_{2}}+{{H}_{2}} \\\\ & \\begin{matrix} 0,025 & {} & \\leftarrow & {} & {} & 0,025 & (mol) \\\\\\end{matrix} \\\\ \\end{aligned}$<br\/> Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a Ca l\u00e0 0,025x40 = 1 gam <br\/>V\u1eady kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a Fe l\u00e0 4,6 - 1 = 3,6 gam<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2333},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Bi\u1ec7n ph\u00e1p n\u00e0o d\u01b0\u1edbi \u0111\u00e2y \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng \u0111\u1ec3 ch\u1ed1ng \u00f4 nhi\u1ec5m ngu\u1ed3n n\u01b0\u1edbc ? ","select":["A. Kh\u00f4ng \u0111\u01b0\u1ee3c v\u1ee9t r\u00e1c th\u1ea3i xu\u1ed1ng ao, h\u1ed3, kinh r\u1ea1ch, s\u00f4ng ","B. Tr\u1ed3ng nhi\u1ec1u c\u00e2y xanh ","C. X\u1eed l\u00fd n\u01b0\u1edbc th\u1ea3i sinh ho\u1ea1t v\u00e0 n\u01b0\u1edbc th\u1ea3i c\u00f4ng nghi\u1ec7p tr\u01b0\u1edbc khi cho n\u01b0\u1edbc th\u1ea3i ch\u1ea3y v\u00e0o h\u1ed3, s\u00f4ng, bi\u1ec3n ","D. C\u1ea3 A v\u00e0 C "],"hint":"","explain":"<span class='basic_left'>M\u1ed7i ng\u01b0\u1eddi c\u1ea7n g\u00f3p ph\u1ea7n gi\u1eef cho c\u00e1c ngu\u1ed3n n\u01b0\u1edbc kh\u00f4ng b\u1ecb \u00f4 nhi\u1ec5m : Kh\u00f4ng \u0111\u01b0\u1ee3c v\u1ee9t r\u00e1c th\u1ea3i xu\u1ed1ng ao, h\u1ed3, kinh r\u1ea1ch, s\u00f4ng. Ph\u1ea3i x\u1eed l\u00fd n\u01b0\u1edbc th\u1ea3i sinh ho\u1ea1t v\u00e0 n\u01b0\u1edbc th\u1ea3i c\u00f4ng nghi\u1ec7p tr\u01b0\u1edbc khi cho n\u01b0\u1edbc th\u1ea3i ch\u1ea3y v\u00e0o h\u1ed3, s\u00f4ng, bi\u1ec3n <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2334},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"\u0110\u1ec3 \u0111i\u1ec1u ch\u1ebf 2,94 gam axit sunfuric th\u00ec c\u1ea7n bao nhi\u00eau gam oxit $S{{O}_{3}}$ h\u00f3a h\u1ee3p v\u1edbi n\u01b0\u1edbc? ","select":["A. 5,6 gam ","B. 4,7 gam ","C. 3,6 gam ","D. 2,4 gam "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{{{H}_{2}}S{{O}_{4}}}}=\\dfrac{2,94}{98}=0,03(mol) \\\\ & S{{O}_{3}}+{{H}_{2}}O\\to {{H}_{2}}S{{O}_{4}} \\\\ & \\begin{matrix} 0,03 & \\leftarrow & {} & 0,03 & {} & {} & (mol) \\\\\\end{matrix} \\\\ & \\to {{m}_{S{{O}_{3}}}}=0,03.(32+16.3)=2,4(g) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2335},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Cho m\u1ed9t m\u1ea9u Na c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng 1,38 gam v\u00e0o n\u01b0\u1edbc, sau m\u1ed9t th\u1eddi gian thu \u0111\u01b0\u1ee3c 0,5712 l\u00edt kh\u00ed hi\u0111ro \u1edf \u0111i\u1ec1u ki\u1ec7n ti\u00eau chu\u1ea9n. Hi\u1ec7u su\u1ea5t c\u1ee7a ph\u1ea3n \u1ee9ng l\u00e0 ","select":["A. $80\\%$ ","B. $70\\%$ ","C. $85\\%$ ","D. $90\\%$ "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{Na}}=\\dfrac{1,38}{23}=0,06(mol) \\\\ & {{n}_{{{H}_{2}}}}=\\dfrac{0,5712}{22,4}=0,0255(mol) \\\\ & 2Na+2{{H}_{2}}O\\to 2NaOH+{{H}_{2}} \\\\ & \\begin{matrix} 0,051mol & \\leftarrow & {} & {} & 0,0255mol & {} & {} \\\\\\end{matrix} \\\\ & \\to {{n}_{Na(pu)}}=0,051<{{n}_{Na(bd)}}=0,06 \\\\ \\end{aligned}$<br\/>V\u1eady ph\u1ea3n \u1ee9ng x\u1ea3y ra kh\u00f4ng ho\u00e0n to\u00e0n, l\u01b0\u1ee3ng Na v\u1eabn c\u00f2n d\u01b0 sau ph\u1ea3n \u1ee9ng <br\/>$\\to Hs=\\dfrac{0,051}{0,06}.100\\%=85\\%$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2336},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Cho m\u1ed9t h\u1ed7n h\u1ee3p oxit t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc sau ph\u1ea3n \u1ee9ng thu \u0111\u01b0\u1ee3c dung d\u1ecbch l\u00e0m xanh qu\u1ef3 t\u00edm, oxit thu\u1ed9c lo\u1ea1i oxit n\u00e0o ? ","select":["A. Oxit baz\u01a1 ","B. Oxit axit ","C. Oxit l\u01b0\u1ee1ng t\u00ednh ","D. Oxit trung t\u00ednh "],"hint":"","explain":"<span class='basic_left'>N\u01b0\u1edbc t\u00e1c d\u1ee5ng v\u1edbi m\u1ed9t s\u1ed1 oxit baz\u01a1 ( nh\u01b0 $CaO,CaO,N{{a}_{2}}O,{{K}_{2}}O$ )t\u1ea1o ra baz\u01a1 m\u00e0 baz\u01a1 l\u00e0m \u0111\u1ed5i qu\u1ef3 t\u00edm th\u00e0nh xanh<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2337},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"\u0110\u1ed1t ch\u00e1y 15 $c{{m}^{3}}$ kh\u00ed hi\u0111ro trong 20 $c{{m}^{3}}$ kh\u00ed oxi. Bi\u1ebft c\u00e1c th\u1ec3 t\u00edch kh\u00ed \u0111o c\u00f9ng \u1edf ${{100}^{o}}C$ v\u00e0 \u00e1p su\u1ea5t kh\u00ed quy\u1ec3n. Th\u1ec3 t\u00edch ch\u1ea5t kh\u00ed c\u00f2n l\u1ea1i sau ph\u1ea3n \u1ee9ng l\u00e0 ","select":["A. 15 $c{{m}^{3}}$ kh\u00ed hi\u0111ro ","B. 5 $c{{m}^{3}}$ kh\u00ed hi\u0111ro ","C. 15 $c{{m}^{3}}$ h\u01a1i n\u01b0\u1edbc ","D. 12,5 $c{{m}^{3}}$ kh\u00ed oxi "],"hint":"","explain":"<span class='basic_left'>C\u00e1c th\u1ec3 t\u00edch kh\u00ed \u0111o c\u00f9ng \u1edf ${{100}^{o}}C$ v\u00e0 \u00e1p su\u1ea5t kh\u00ed quy\u1ec3n n\u00ean t\u1ef7 l\u1ec7 th\u1ec3 t\u00edch b\u1eb1ng t\u1ef7 l\u1ec7 s\u1ed1 mol <br\/>$2{{H}_{2}}+{{O}_{2}}\\xrightarrow{{{t}^{o}}}2{{H}_{2}}O$<br\/>Theo ph\u01b0\u01a1ng tr\u00ecnh c\u1ee9 2 th\u1ec3 t\u00edch kh\u00ed hi\u0111ro t\u00e1c d\u1ee5ng v\u1edbi 1 th\u1ec3 t\u00edch kh\u00ed \u00f4xi<br\/>L\u1eadp t\u1ef7 l\u1ec7 : $\\dfrac{15}{2}<\\dfrac{20}{1}$<br\/> Suy ra H2 ph\u1ea3n \u1ee9ng h\u1ebft,oxi d\u01b0. T\u00ednh theo H2 ta c\u00f3 th\u1ec3 t\u00edch O2 ph\u1ea3n \u1ee9ng =1\/2(th\u1ec3 t\u00edch H2)=15:2=7,5 (cm3). <br\/> Th\u1ec3 t\u00edch O2 d\u01b0 =20-7,5=12,5 (cm3) <br\/> Th\u1ec3 t\u00edch H2O = th\u1ec3 t\u00edch H2=15 (cm3) <br\/> V\u1eady kh\u00ed sau ph\u1ea3n \u1ee9ng c\u00f2n 12,5 cm3 kh\u00ed oxi v\u00e0 sinh ra 15 cm3 h\u01a1i n\u01b0\u1edbc <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2338},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"L\u01b0\u1ee3ng n\u01b0\u1edbc tr\u00ean tr\u00e1i \u0111\u1ea5t l\u00e0 r\u1ea5t l\u1edbn, chi\u1ebfm bao nhi\u00eau $\\%$ di\u1ec7n t\u00edch tr\u00e1i \u0111\u1ea5t ? ","select":["A. $75\\%$ ","B. $25\\%$ ","C. $85\\%$ ","D. $90\\%$ "],"hint":"","explain":"<span class='basic_left'>L\u01b0\u1ee3ng n\u01b0\u1edbc tr\u00ean tr\u00e1i \u0111\u1ea5t l\u00e0 r\u1ea5t l\u1edbn v\u00ec 3\/4 di\u1ec7n t\u00edch tr\u00e1i \u0111\u1ea5t l\u00e0 c\u00e1c \u0111\u1ea1i d\u01b0\u01a1ng, bi\u1ec3n, h\u1ed3, s\u00f4ng ng\u00f2i. C\u00f3 nhi\u1ec1u m\u1ecf n\u01b0\u1edbc trong l\u00f2ng \u0111\u1ea5t. Nh\u01b0ng s\u1ef1 ph\u00e2n b\u1ed1 n\u01b0\u1edbc tr\u00ean b\u1ec1 m\u1eb7t tr\u00e1i \u0111\u1ea5t kh\u00f4ng \u0111\u1ed3ng \u0111\u1ec1u. C\u00f3 nhi\u1ec1u v\u00f9ng \u0111\u1ea5t r\u1ea5t hi\u1ebfm n\u01b0\u1edbc, \u0111\u1ea5t \u0111ai bi\u1ebfn th\u00e0nh sa m\u1ea1c<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2339}],"lesson":{"save":0,"level":2}}