{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"\u0110\u1ec3 \u0111i\u1ec1u ch\u1ebf kh\u00ed oxi trong ph\u00f2ng th\u00ed nhi\u1ec7m ng\u01b0\u1eddi ta s\u1eed d\u1ee5ng c\u00e1c mu\u1ed1i n\u00e0o sau \u0111\u00e2y? ","select":["A. $KMn{{O}_{4}}$ ","B. $CaC{{O}_{3}}$ ","C. $KCl{{O}_{3}}$ ","D. C\u1ea3 $A$ v\u00e0 $C$ "],"hint":"","explain":"<span class='basic_left'>Trong ph\u00f2ng th\u00ed nghi\u1ec7m, kh\u00ed oxi \u0111\u01b0\u1ee3c \u0111i\u1ec1u ch\u1ebf b\u1eb1ng c\u00e1ch \u0111un n\u00f3ng h\u1ee3p ch\u1ea5t gi\u00e0u oxi v\u00e0 d\u1ec5 b\u1ecb ph\u00e2n h\u1ee7y \u1edf nhi\u1ec7t \u0111\u1ed9 cao nh\u01b0 $KMn{{O}_{4}}$ v\u00e0 $KCl{{O}_{3}}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2180},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"\u0110un n\u00f3ng $KCl{{O}_{3}}$ c\u00f3 x\u00fac t\u00e1c $Mn{{O}_{2}}$ trong \u1ed1ng nghi\u1ec7m, ng\u01b0\u1eddi ta thu \u0111\u01b0\u1ee3c kh\u00ed oxi b\u1eb1ng c\u00e1ch \u0111\u1ea9y n\u01b0\u1edbc l\u00e0 d\u1ef1a v\u00e0o t\u00ednh ch\u1ea5t ","select":["A. Kh\u00ed oxi tan trong n\u01b0\u1edbc ","B. Kh\u00ed oxi kh\u00f3 h\u00f3a l\u1ecfng ","C. Kh\u00ed \u00edt tan trong n\u01b0\u1edbc ","D. Kh\u00ed oxi nh\u1eb9 h\u01a1n n\u01b0\u1edbc "],"hint":"","explain":"<span class='basic_left'>Oxi l\u00e0 ch\u1ea5t kh\u00ed, kh\u00f4ng m\u00e0u, kh\u00f4ng m\u00f9i, \u00edt tan trong n\u01b0\u1edbc, n\u1eb7ng h\u01a1n kh\u00f4ng kh\u00ed.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2181},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Hi\u1ec7n t\u01b0\u1ee3ng khi s\u1eed d\u1ee5ng t\u00e0n \u0111\u00f3m \u0111\u1ec3 th\u1eed kh\u00ed oxi l\u00e0 : ","select":["A. Que \u0111\u00f3m b\u00f9ng ch\u00e1y ","B. Kh\u00f4ng c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng ","C. Que \u0111\u00f3m t\u1eaft ","D. Que \u0111\u00f3m ch\u00e1y t\u1eeb t\u1eeb r\u1ed3i t\u1eaft h\u1eb3n "],"hint":"","explain":"<span class='basic_left'>Kh\u00ed oxi duy tr\u00ec s\u1ef1 ch\u00e1y, c\u1ea7n \u0111\u1ec3 \u0111\u1ed1t nhi\u00ean li\u1ec7u trong \u0111\u1eddi s\u1ed1ng v\u00e0 s\u1ea3n xu\u1ea5t<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2182},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc trong \u0111\u00f3 m\u1ed9t ch\u1ea5t sinh ra hai hay nhi\u1ec1u ch\u1ea5t m\u1edbi \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 ","select":["A. Ph\u1ea3n \u1ee9ng h\u00f3a h\u1ee3p ","B. Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ee7y ","C. Ph\u1ea3n \u1ee9ng th\u1ebf ","D. Ph\u1ea3n \u1ee9ng trao \u0111\u1ed5i "],"hint":"","explain":"<span class='basic_left'>Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ee7y l\u00e0 ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc trong \u0111\u00f3 m\u1ed9t ch\u1ea5t sinh ra hai hay nhi\u1ec1u ch\u1ea5t m\u1edbi<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2183},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc n\u00e0o sau \u0111\u00e2y l\u00e0 ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ee7y ? ","select":["A. $2KMn{{O}_{4}}\\xrightarrow{{{t}^{o}}}{{K}_{2}}Mn{{O}_{4}}+Mn{{O}_{2}}+{{O}_{2}}$ ","B. $CaO+C{{O}_{2}}\\to CaC{{O}_{3}}$ ","C. $Zn+2HCl\\to ZnC{{l}_{2}}+{{H}_{2}}$ ","D. $2NaOH+CuC{{l}_{2}}\\to Cu{{(OH)}_{2}}+2NaCl$ "],"hint":"","explain":"<span class='basic_left'>Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ee7y l\u00e0 ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc trong \u0111\u00f3 m\u1ed9t ch\u1ea5t sinh ra hai hay nhi\u1ec1u ch\u1ea5t m\u1edbi<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A .<\/span><\/span> ","column":2}]}],"id_ques":2184},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Nhi\u1ec7t ph\u00e2n $m$ gam mu\u1ed1i $KMn{{O}_{4}}$ th\u1ea5y tho\u00e1t ra $44,8$ l\u00edt kh\u00ed kh\u00f4ng m\u00e0u \u1edf \u0111ktc. S\u1ed1 gam mu\u1ed1i \u0111em \u0111i nhi\u1ec7t ph\u00e2n l\u00e0 ","select":["A. $316$ gam ","B. $632$ gam ","C. $623$ gam ","D. $361$ gam "],"hint":"","explain":"<span class='basic_left'>PTHH: $2KMn{{O}_{4}}\\xrightarrow{{{t}^{o}}}{{K}_{2}}Mn{{O}_{4}}+Mn{{O}_{2}}+{{O}_{2}}$<br\/>${{n}_{{{O}_{2}}}}=\\dfrac{44,8}{22,4}=2(mol)$<br\/>Theo ph\u01b0\u01a1ng tr\u00ecnh ph\u1ea3n \u1ee9ng : ${{n}_{KMn{{O}_{4}}}}=2{{n}_{{{O}_{2}}}}=4(mol)$<br\/>$\\to$ $m=4.158=632$ gam<br\/><br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2185},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Ph\u01b0\u01a1ng ph\u00e1p thu kh\u00ed oxi v\u00e0 t\u01b0 th\u1ebf b\u00ecnh thu l\u00e0: ","select":["A. \u0110\u1ea9y n\u01b0\u1edbc v\u00e0 \u0111\u1ec3 \u0111\u1ee9ng b\u00ecnh","B. \u0110\u1ea9y kh\u00f4ng kh\u00ed v\u00e0 \u0111\u1ec3 ng\u1eeda b\u00ecnh ","C. \u0110\u1ea9y n\u01b0\u1edbc v\u00e0 \u0111\u1ec3 \u00fap b\u00ecnh ","D. C\u1ea3 $B$ v\u00e0 $C$ "],"hint":"","explain":"<span class='basic_left'>Thu kh\u00ed oxi b\u1eb1ng ph\u01b0\u01a1ng ph\u00e1p \u0111\u1ea9y kh\u00f4ng kh\u00ed \u0111\u1ec3 ng\u1eeda b\u00ecnh l\u00e0 do oxi n\u1eb7ng h\u01a1n kh\u00f4ng kh\u00ed s\u1ebd \u0111u\u1ed5i h\u1ebft kh\u00f4ng kh\u00ed trong b\u00ecnh ra ngo\u00e0i do v\u1eady m\u00e0 s\u1ebd thu \u0111\u01b0\u1ee3c oxi trong b\u00ecnh<br\/>Thu kh\u00ed oxi b\u1eb1ng ph\u01b0\u01a1ng ph\u00e1p \u0111\u1ea9y n\u01b0\u1edbc v\u00e0 \u0111\u1eb7t \u00fap b\u00ecnh l\u00e0 do oxi \u00edt tan trong n\u01b0\u1edbc v\u00e0 \u0111\u1eb7t up b\u00ecnh l\u00e0 do \u00e1p su\u1ea5t trong b\u00ecnh t\u0103ng s\u1ebd \u0111\u1ea9y n\u01b0\u1edbc ra ngo\u00e0i nh\u01b0 v\u1eady ta s\u1ebd thu \u0111\u01b0\u1ee3c kh\u00ed oxi<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2186},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Nhi\u1ec7t ph\u00e2n $22,05$ gam $KCl{{O}_{3}}$ th\u1ea5y c\u00f3 kh\u00ed bay l\u00ean. Th\u1ec3 t\u00edch c\u1ee7a kh\u00ed \u1edf \u0111ktc l\u00e0 ","select":["A. $6,048(l)$ ","B. $12,096(l)$ ","C. $2,016(l)$ ","D. $7,84(l)$ "],"hint":"","explain":"<span class='basic_left'>${{n}_{KCl{{O}_{3}}}}=\\dfrac{22,05}{122,5}=0,18(mol)$<br\/>$\\begin{aligned} & 2KCl{{O}_{3}}\\xrightarrow{{{t}^{o}}}2KCl+3{{O}_{2}} \\\\ & \\begin{matrix} 2mol & {} & {} & {} & {} & 3mol & {} \\\\\\end{matrix} \\\\ & \\begin{matrix} 0,18mol & \\to & {} & {} & \\dfrac{3}{2}.0,18mol & {} & {} \\\\\\end{matrix} \\\\ \\end{aligned}$<br\/>$\\to {{V}_{{{O}_{2}}}}=\\dfrac{3}{2}.0,18.22,4=6,048(l)$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2187},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"L\u1ea5y c\u00f9ng m\u1ed9t l\u01b0\u1ee3ng $KCl{{O}_{3}}$ v\u00e0 $KMn{{O}_{4}}$ \u0111\u1ec3 \u0111i\u1ec1u ch\u1ebf kh\u00ed oxi. Nh\u1eadn x\u00e9t n\u00e0o sau \u0111\u00e2u \u0111\u00fang?","select":["A. $KCl{{O}_{3}}$ v\u00e0 $KMn{{O}_{4}}$ cho l\u01b0\u1ee3ng oxi nh\u01b0 nhau ","B. $KMn{{O}_{4}}$ cho nhi\u1ec1u kh\u00ed oxi h\u01a1n $KCl{{O}_{3}}$ ","C. $KCl{{O}_{3}}$ cho nhi\u1ec1u kh\u00ed oxi h\u01a1n $KMn{{O}_{4}}$ ","D. $KCl{{O}_{3}}$ v\u00e0 $KMn{{O}_{4}}$ cho l\u01b0\u1ee3ng oxi nh\u01b0 nhau b\u1eb1ng $m=\\dfrac{m}{316}(mol)$ "],"hint":"","explain":"<span class='basic_left'>G\u1ecdi kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a $KCl{{O}_{3}}$ v\u00e0 $KMn{{O}_{4}}$ c\u1ea7n l\u1ea5y \u0111\u1ec3 \u0111i\u1ec1u ch\u1ebf oxi l\u00e0 m (g)<br\/>$\\begin{aligned} & 2KCl{{O}_{3}}\\xrightarrow{{{t}^{o}}}2KCl+3{{O}_{2}}(1) \\\\ & \\begin{matrix}2mol & {} & {} & {} & {} & 3mol & {} \\\\\\end{matrix} \\\\ & \\begin{matrix} \\dfrac{m}{122,5} & {} & \\to & {} & \\dfrac{3}{2}.\\dfrac{m}{122,5} & {} & {} \\\\\\end{matrix} \\\\ & \\Rightarrow {{n}_{{{O}_{2}}(1)}}=\\dfrac{3m}{245}(mol) \\\\ \\end{aligned}$<br\/>$\\begin{aligned} & 2KMn{{O}_{4}}\\xrightarrow{{{t}^{o}}}{{K}_{2}}Mn{{O}_{4}}+Mn{{O}_{2}}+{{O}_{2}}(2) \\\\ & \\begin{matrix} 2mol & {} & {} & {} & {} & {} & {} & {} & {} & 1mol \\\\\\end{matrix} \\\\ & \\begin{matrix} \\dfrac{m}{158}mol & {} & {} & {} & \\to & {} & {} & {} & \\dfrac{1}{2}.\\dfrac{m}{158}mol & {} \\\\\\end{matrix} \\\\ & \\Rightarrow {{n}_{{{O}_{2}}(2)}}=\\dfrac{m}{316}(mol) \\\\ \\end{aligned}$<br\/>So s\u00e1nh s\u1ed1 mol c\u1ee7a oxi thu \u0111\u01b0\u1ee3c t\u1eeb ph\u01b0\u01a1ng tr\u00ecnh (1) v\u00e0 (2) : ${{n}_{{{O}_{2}}(1)}}>{{n}_{{{O}_{2}}(2)}}$<br\/>V\u1eady $KCl{{O}_{3}}$ cho nhi\u1ec1u kh\u00ed oxi h\u01a1n $KMn{{O}_{4}}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2188},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"D\u00f9ng $6,4$ kg kh\u00ed oxi \u0111\u1ec3 \u0111\u1ed1t ch\u00e1y kh\u00ed axetilen ${{C}_{2}}{{H}_{2}}$. V\u1edbi l\u01b0\u1ee3ng kh\u00ed oxi nh\u01b0 tr\u00ean, c\u00f3 th\u1ec3 \u0111\u1ed1t ch\u00e1y bao nhi\u00eau ${{m}^{3}}$ kh\u00ed axetilen (\u0111ktc) ? H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n m\u00e0 em cho l\u00e0 \u0111\u00fang","select":["A. $2,792({{m}^{3}})$ ","B. $0,792({{m}^{3}})$ ","C. $3,792({{m}^{3}})$","D. $1,792({{m}^{3}})$ "],"hint":"","explain":"<span class='basic_left'>S\u1ed1 mol kh\u00ed oxi : $n=\\dfrac{6,4.1000}{32}=200(mol)$<br\/>Ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc: $2{{C}_{2}}{{H}_{2}}+5{{O}_{2}}\\to 4C{{O}_{2}}+2{{H}_{2}}O$<br\/>Theo ph\u01b0\u01a1ng tr\u00ecnh c\u1ee9 2 mol ${{C}_{2}}{{H}_{2}}$ s\u1ebd ph\u1ea3n \u1ee9ng v\u1edbi 5 mol ${{O}_{2}}$<br\/>V\u1eady x mol ${{C}_{2}}{{H}_{2}}$ s\u1ebd ph\u1ea3n \u1ee9ng v\u1edbi 200 mol ${{O}_{2}}$<br\/>$\\to x=\\dfrac{200.2}{5}=80(mol)$<br\/>S\u1ed1 ${{m}^{3}}$ kh\u00ed axetilen b\u1ecb \u0111\u1ed1t ch\u00e1y l\u00e0 <br\/>$\\begin{aligned} & \\dfrac{80.22,4}{1000}=1,792({{m}^{3}}) \\\\ & (1{{m}^{3}}=1000d{{m}^{3}}=1000lit) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2189},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Trong c\u00f4ng nghi\u1ec7p, oxi \u0111\u01b0\u1ee3c \u0111i\u1ec1u ch\u1ebf b\u1eb1ng ph\u01b0\u01a1ng ph\u00e1p n\u00e0o sau \u0111\u00e2y? ","select":["A. \u0110i\u1ec7n ph\u00e2n n\u01b0\u1edbc ","B. Nhi\u1ec7t ph\u00e2n mu\u1ed1i $KCl{{O}_{3}}$ v\u00e0 $KMn{{O}_{4}}$ ","C. H\u00f3a l\u1ecfng kh\u00f4ng kh\u00ed \u1edf nhi\u1ec7t \u0111\u1ed9 th\u1ea5p v\u00e0 \u00e1p su\u1ea5t cao ","D. C\u1ea3 $A$ v\u00e0 $C$ "],"hint":"","explain":"<span class='basic_left'><br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2190},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"\u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n $8,1$ gam $Al$. Th\u1ec3 t\u00edch kh\u00ed oxi c\u1ea7n d\u00f9ng cho qu\u00e1 tr\u00ecnh \u0111\u1ed1t ch\u00e1y l\u00e0 ","select":["A. $20,16$ l\u00edt ","B. $5,04$ l\u00edt ","C. $9,04$ l\u00edt ","D. $3,36$ l\u00edt "],"hint":"","explain":"<span class='basic_left'>S\u1ed1 mol c\u1ee7a Al l\u00e0 $n=\\dfrac{8,1}{27}=0,3(mol)$<br\/>PTHH :$4Al+3{{O}_{2}}\\xrightarrow{{{t}^{o}}}2A{{l}_{2}}{{O}_{3}}$<br\/>Theo ph\u01b0\u01a1ng tr\u00ecnh c\u1ee9 4 mol Al s\u1ebd ph\u1ea3n \u1ee9ng v\u1edbi 3 mol ${{O}_{2}}$<br\/>V\u1eady 0,3 mol Al s\u1ebd ph\u1ea3n \u1ee9ng v\u1edbi x mol ${{O}_{2}}$<br\/>$\\to x=\\dfrac{3.0,3}{4}=0,225(mol)$<br\/>$\\to$ V = 0,225.22,4 = 5,04 ( l\u00edt )<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2191},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Tr\u00f2ng ph\u00f2ng th\u00ed nghi\u1ec7m, ng\u01b0\u1eddi ta \u0111\u1ed1t n\u00f3ng kali clorat thu \u0111\u01b0\u1ee3c V l\u00edt kh\u00ed oxi, to\u00e0n b\u1ed9 kh\u00ed oxi thu \u0111\u01b0\u1ee3c \u0111em \u0111\u1ed1t ch\u00e1y $2,4$ gam m\u1ed9t m\u1eabu l\u01b0u hu\u1ef3nh kh\u00f4ng tinh khi\u1ebft, thu \u0111\u01b0\u1ee3c $1,568$ l\u00edt kh\u00ed sunfur\u01a1 $S{{O}_{2}}$ (\u0111ktc). \u0110\u1ed9 tinh khi\u1ebft c\u1ee7a m\u1eabu l\u01b0u hu\u1ef3nh \u0111\u00e3 d\u00f9ng l\u00e0 ","select":["A. $93,33\\%$ ","B. $98,5\\%$ ","C. $97,33\\%$ ","D. $99,33\\%$ "],"hint":"","explain":"<span class='basic_left'>PTHH: $S+{{O}_{2}}\\to S{{O}_{2}}$<br\/>S\u1ed1 mol kh\u00ed $S{{O}_{2}}$ sinh ra sau ph\u1ea3n \u1ee9ng : $n=\\dfrac{1,568}{22,4}=0,07(mol)$<br\/>Theo ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc, \u0111\u1ec3 sinh ra 0,07 mol $S{{O}_{2}}$ ph\u1ea3i c\u00f3 0,07 mol S<br\/>$\\to {{m}_{S}}=0,07.32=2,24(g)$<br\/>\u0110\u1ed9 tinh khi\u1ebft c\u1ee7a m\u1eabu l\u01b0u hu\u1ef3nh l\u00e0 $\\dfrac{2,24.100\\%}{2,4}=93,33\\%$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2192},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Cho $15,3$ gam oxit kim lo\u1ea1i $M$ h\u00f3a tr\u1ecb $II$ v\u00e0o n\u01b0\u1edbc thu \u0111\u01b0\u1ee3c $17,1$ baz\u01a1. C\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a oxit l\u00e0 ( Bi\u1ebft ph\u1ea3n \u1ee9ng x\u1ea3y ra nh\u01b0 sau: oxit kim lo\u1ea1i + n\u01b0\u1edbc $\\to$ baz\u01a1 )","select":["A. $FeO$ ","B. $CuO$ ","C. $BaO$ ","D. $MgO$ "],"hint":"","explain":"<span class='basic_left'>M c\u00f3 h\u00f3a tr\u1ecb II v\u00e0 O c\u00f3 h\u00f3a tr\u1ecb II<br\/>\u0110\u1eb7t c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a oxit l\u00e0 $MO$<br\/>$\\to$ C\u00f4ng th\u1ee9c c\u1ee7a baz\u01a1 l\u00e0 $M{{(OH)}_{2}}$<br\/>PTHH: $MO+{{H}_{2}}O\\to M{{(OH)}_{2}}$ <br\/>Theo \u0111\u1ecbnh lu\u1eadt b\u1ea3o to\u00e0n kh\u1ed1i l\u01b0\u1ee3ng : <br\/>$\\begin{aligned} & {{m}_{{{H}_{2}}O}}={{m}_{M{{(OH)}_{2}}}}-{{m}_{MO}}=17,1-15,3=1,8(g) \\\\ & \\Rightarrow {{n}_{{{H}_{2}}O}}=\\dfrac{1,8}{18}=0,1(mol) \\\\ \\end{aligned}$ <br\/>Theo ph\u01b0\u01a1ng tr\u00ecnh: <br\/>${{n}_{MO}}={{n}_{{{H}_{2}}O}}=0,1(mol)\\to M+16=\\dfrac{15,3}{0,1}\\to M=137$<br\/>V\u1eady CTHH c\u1ee7a oxit l\u00e0 BaO<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2193},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"M\u1ed9t oxit c\u1ee7a l\u01b0u hu\u1ef3nh trong \u0111\u00f3 oxi chi\u1ebfm $60\\%$ v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng.C\u00f4ng th\u1ee9c ph\u00e2n t\u1eed c\u1ee7a oxit l\u00e0 ","select":["A. ${{S}_{2}}{{O}_{3}}$ ","B. $S{{O}_{3}}$ ","C. $SO$ ","D. $S{{O}_{2}}$ "],"hint":"","explain":"<span class='basic_left'>Gi\u1ea3 s\u1eed c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed c\u1ee7a oxit \u0111\u00f3 c\u00f3 d\u1ea1ng : ${{S}_{x}}{{O}_{y}}$<br\/>Theo gi\u1ea3 thi\u1ebft ta c\u00f3: <br\/>$\\begin{aligned} & \\%O=\\dfrac{{{M}_{O}}}{{{M}_{{{S}_{x}}{{O}_{y}}}}}.100\\%=60\\%\\Rightarrow \\dfrac{16y}{32x+16y}=\\dfrac{60}{100} \\\\ & \\Rightarrow \\dfrac{x}{y}=\\dfrac{640}{1920}=\\dfrac{1}{3}\\Rightarrow \\left\\{ \\begin{aligned} & x=1 \\\\ & y=3 \\\\ \\end{aligned} \\right. \\\\ \\end{aligned}$<br\/>V\u1eady c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a oxit l\u01b0u hu\u1ef3nh l\u00e0 $S{{O}_{3}}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2194},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Nung m\u1ed9t ch\u1ea5t canxi cacbonat trong m\u1ed9t ch\u00e9n nung, ng\u01b0\u1eddi ta thu \u0111\u01b0\u1ee3c v\u00f4i s\u1ed1ng c\u00f3 CTHH l\u00e0 $CaO$ v\u00e0 kh\u00ed tho\u00e1t ra l\u00e0 $C{{O}_{2}}$. K\u1ebft qu\u1ea3 c\u1ee7a th\u00ed nghi\u1ec7m \u0111\u01b0\u1ee3c ghi nh\u01b0 sau: Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a ch\u00e9n nung r\u1ed7ng l\u00e0 $30$ gam; Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a ch\u00e9n nung v\u00e0 canxi cacbonat l\u00e0 $40$ gam; Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a ch\u00e9n nung v\u00e0 $CaO$ l\u00e0 $35,6$ gam. Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a $CaO$ c\u00f3 trong ch\u00e9n sau khi nung l\u00e0 ","select":["A. $5,6$ gam ","B. $35,6$ gam ","C. $30$ gam ","D. $10$ gam "],"hint":"","explain":"<span class='basic_left'>Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a $CaO$ c\u00f3 trong ch\u00e9n sau khi nung = Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a ch\u00e9n nung v\u00e0 $CaO$ - Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a ch\u00e9n nung r\u1ed7ng = $5,6$ gam<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2195},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Cho ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ee7y $KCl{{O}_{3}}$ nh\u01b0 sau : $2KCl{{O}_{3}}\\xrightarrow{{{t}^{0}}}2KCl+3{{O}_{2}}$. Mu\u1ed1n \u0111i\u1ec1u ch\u1ebf \u0111\u01b0\u1ee3c $3,36$ l\u00edt kh\u00ed oxi \u1edf \u0111ktc c\u1ea7n d\u00f9ng bao nhi\u00eau gam $KCl{{O}_{3}}$ ? ","select":["A. $14,25(g)$ ","B. $32,25(g)$ ","C. $12,25(g)$ ","D. $15(g)$ "],"hint":"","explain":"<span class='basic_left'>${{n}_{{{O}_{2}}}}=\\dfrac{3,36}{22,4}=0,15(mol)$<br\/>Theo ph\u01b0\u01a1ng tr\u00ecnh : <br\/>${{n}_{KCl{{O}_{3}}}}=\\dfrac{2}{3}{{n}_{{{O}_{2}}}}=0,1(mol)\\to {{m}_{KCl{{O}_{3}}}}=0,1.122,5=12,25(g)$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2196},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Cho ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ee7y $KMn{{O}_{4}}$ nh\u01b0 sau : $2KMn{{O}_{4}}\\xrightarrow{{{t}^{o}}}{{K}_{2}}Mn{{O}_{4}}+Mn{{O}_{2}}+{{O}_{2}}$. N\u1ebfu c\u00f3 $118,5$ gam $KMn{{O}_{4}}$ tham gia ph\u1ea3n \u1ee9ng, s\u1ebd thu \u0111\u01b0\u1ee3c bao nhi\u00eau l\u00edt kh\u00ed oxi \u1edf \u0111ktc, bi\u1ebft hi\u1ec7u su\u1ea5t ph\u1ea3n \u1ee9ng l\u00e0 $90\\%$.","select":["A. $8,4(l)$ ","B. $7,56(l)$ ","C. $8,86(l)$ ","D. $9,56(l)$ "],"hint":"","explain":"<span class='basic_left'>${{n}_{KMn{{O}_{4}}}}=\\dfrac{118,5}{158}=0,75(mol)$<br\/>Theo ph\u01b0\u01a1ng tr\u00ecnh : ${{n}_{{{O}_{2}}}}=\\dfrac{1}{2}{{n}_{KMn{{O}_{4}}}}=0,375(mol)$<br\/>Th\u1ec3 t\u00edch th\u1ef1c t\u1ebf oxi thu \u0111\u01b0\u1ee3c l\u00e0 <br\/>${{V}_{{{O}_{2}}}}=0,375.22,4.\\dfrac{90}{100}=7,56(l)$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2197},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Trong ph\u00f2ng th\u00ed nghi\u1ec7m ng\u01b0\u1eddi ta \u0111i\u1ec1u ch\u1ebf nh\u00f4m oxit ${{Al}_{2}}{{O}_{3}}$ b\u1eb1ng c\u00e1ch d\u00f9ng oxi, oxi h\u00f3a nh\u00f4m \u1edf nhi\u1ec7t \u0111\u1ed9 cao. S\u1ed1 gam nh\u00f4m v\u00e0 th\u1ec3 t\u00edch kh\u00ed oxi \u1edf \u0111ktc c\u1ea7n d\u00f9ng \u0111\u1ec3 \u0111i\u1ec1u ch\u1ebf \u0111\u01b0\u1ee3c $0,864$ gam ${{Al}_{2}}{{O}_{3}}$ l\u00e0 ","select":["A. ${{V}_{{{O}_{2}}}}=0,432(l),{{m}_{Al}}=0,2688(g)$ ","B. ${{V}_{{{O}_{2}}}}=0,8546(l),{{m}_{Al}}=0,3256(g)$ ","C. ${{V}_{{{O}_{2}}}}=0,28448(l),{{m}_{Al}}=0,459(g)$ ","D. ${{V}_{{{O}_{2}}}}=0,3256(l),{{m}_{Al}}=0,8546(g)$ "],"hint":"","explain":"<span class='basic_left'>${{n}_{A{{l}_{2}}{{O}_{3}}}}=\\dfrac{0,864}{102}=0,00847(mol)$<br\/>$\\begin{aligned} & 4Al+3{{O}_{2}}\\to 2A{{l}_{2}}{{O}_{3}} \\\\ & \\begin{matrix} 4mol & 3mol & 2mol & {} & {} & {} & {} & {} \\\\\\end{matrix} \\\\ & \\begin{matrix} y & {} & x & \\leftarrow & 0,00847mol & {} & {} & {} \\\\\\end{matrix} \\\\ & \\to x=\\dfrac{3}{2}.0,00847=0,0127(mol)\\Rightarrow {{V}_{{{O}_{2}}}}=0,0127.22,4=0,28448(l) \\\\ & \\to y=\\dfrac{4}{2}.0,00847=0,017(mol)\\Rightarrow {{m}_{Al}}=0,017.27=0,459(g) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2198},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"\u01afu \u0111i\u1ec3m c\u1ee7a vi\u1ec7c s\u1ea3n xu\u1ea5t kh\u00ed oxi trong c\u00f4ng nghi\u1ec7p so v\u1edbi trong ph\u00f2ng th\u00ed nghi\u1ec7m l\u00e0 ","select":["A. Ngu\u1ed3n nguy\u00ean li\u1ec7u phong ph\u00fa ","B. S\u1ea3n xu\u1ea5t \u0111\u01b0\u1ee3c m\u1ed9t l\u01b0\u1ee3ng l\u1edbn oxi ","C. Chi ph\u00ed r\u1ebb ti\u1ec1n ","D. T\u1ea5t c\u1ea3 c\u00e1c \u0111\u00e1p \u00e1n tr\u00ean "],"hint":"","explain":"<span class='basic_left'><br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2199}],"lesson":{"save":0,"level":2}}