Toán lớp 12 - Đề kiểm tra cuối học kì 1 - Toán lớp 12 - Tháng 12 - Số 4

{"save":1,"level":1,"time":"60","total":25,"point":5,"segment":[{"id":"984","test_id":"284","question":"<p>Th\u1ec3 t&iacute;ch c\u1ee7a kh\u1ed1i l\u0103ng tr\u1ee5 c&oacute; di\u1ec7n t&iacute;ch \u0111&aacute;y B v&agrave; chi\u1ec1u cao h l&agrave;<br \/>&nbsp;<\/p>","options":["<span class=\"math-tex\">$V=\\frac{1}{3}Bh$<\/span>","<span class=\"math-tex\">$V=\\frac{1}{2}Bh$<\/span>","<span class=\"math-tex\">$V=Bh$<\/span>","<span class=\"math-tex\">$V=\\frac{\\sqrt{3}}{2}Bh$<\/span>"],"correct":"3","answer":"<p>C&ocirc;ng th\u1ee9c t&iacute;nh th\u1ec3 t&iacute;ch h&igrave;nh l\u0103ng tr\u1ee5 :V = Bh<\/p>","type":"choose","user_id":"108","test":"0","date":"2020-03-27 23:05:08"},{"id":"986","test_id":"284","question":"<p>H&agrave;m s\u1ed1 n&agrave;o sau \u0111&acirc;y kh&ocirc;ng c&oacute; \u0111i\u1ec3m c\u1ef1c tr\u1ecb?<br \/>&nbsp;<\/p>","options":["<span class=\"math-tex\">$y=-{{x}^{4}}+2{{x}^{2}}-5$<\/span>","<span class=\"math-tex\">$y={{x}^{3}}+6x-2019$<\/span>","<span class=\"math-tex\">$y=-\\frac{1}{4}{{x}^{4}}+6$<\/span>","<span class=\"math-tex\">$y={{x}^{4}}+2{{x}^{2}}-5$<\/span>"],"correct":"2","answer":"<p><span class=\"math-tex\">$y=-{{x}^{4}}+2{{x}^{2}}-1$<\/span>&nbsp;c&oacute; <span class=\"math-tex\">$a.b<0$<\/span>. N&ecirc;n h&agrave;m s\u1ed1 c&oacute; 3&nbsp;c\u1ef1c tr\u1ecb (lo\u1ea1i A)<\/p><p><span class=\"math-tex\">$y={{x}^{3}}+6x-2019$<\/span>&nbsp;c&oacute; <span class=\"math-tex\">${{y}^{\/}}=3{{x}^{2}}+6>0,\\forall x\\in \\mathbb{R}$<\/span>. N&ecirc;n h&agrave;m s\u1ed1 kh&ocirc;ng c&oacute; c\u1ef1c tr\u1ecb (nh\u1eadn B)<br \/><span class=\"math-tex\">$y=-\\frac{1}{4}{{x}^{4}}+6$<\/span>&nbsp;c&oacute; <span class=\"math-tex\">$a.b=0$<\/span>. N&ecirc;n h&agrave;m s\u1ed1 c&oacute; 1&nbsp;c\u1ef1c tr\u1ecb<br \/><span class=\"math-tex\">$y={{x}^{4}}+2{{x}^{2}}-5$<\/span> c&oacute; a.b&gt;0. N&ecirc;n h&agrave;m s\u1ed1 c&oacute; 1&nbsp;c\u1ef1c tr\u1ecb<\/p>","type":"choose","user_id":"108","test":"0","date":"2020-03-27 23:09:17"}]}